2. VLE : MODIFIED RAOULTS LAW APPROACH A 60(1 ) : 40(2) liquid blend of unknown compound A (1) and B (2) is in equilibrium with its vapor at 291.20 F. At this temperature, an azeotrope is formed in which x1az = 0.294 and that the saturation pressures of the first and second component is equal to 0.742atm and 0.312atm respectively. If the natural logarithm of activity coefficient of a given component is equal to the product of one parameter Margules coefficient, A multiplied by the square of the other component’s liquid mole fraction; solved for the following : a. The Margules coefficient, A  b. Equilibrium pressure P  c. Vapor composition of component 1

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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2. VLE : MODIFIED RAOULTS LAW APPROACH
A 60(1 ) : 40(2) liquid blend of unknown compound A (1) and B (2) is in equilibrium with its vapor at 291.20 F. At this temperature, an azeotrope is formed in which x1az = 0.294 and that the saturation pressures of the first and second component is equal to 0.742atm and 0.312atm respectively.

If the natural logarithm of activity coefficient of a given component is equal to the product of one parameter Margules coefficient, A multiplied by the square of the other component’s liquid mole fraction; solved for the
following :
a. The Margules coefficient, A 
b. Equilibrium pressure P 
c. Vapor composition of component 1 

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