You devise a new temperature scale based on the properties of the liquid propylene glycol, which has a melting point of -59°C and a boiling point of 188°C. Temperature on the new scale will be in °P, where 0.0°P will be correspond to -60.0°C, near the melting point of propylene glycol, and 100°P will correspond to 190.0°C, near the boiling point of propylene glycol. If a substance has a temperature of 49.0°P, what would be its temperature in °C?
You devise a new temperature scale based on the properties of the liquid propylene glycol, which has a melting point of -59°C and a boiling point of 188°C. Temperature on the new scale will be in °P, where 0.0°P will be correspond to -60.0°C, near the melting point of propylene glycol, and 100°P will correspond to 190.0°C, near the boiling point of propylene glycol. If a substance has a temperature of 49.0°P, what would be its temperature in °C?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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You devise a new temperature scale based on the properties of the liquid propylene glycol, which has a melting point of -59°C and a boiling point of 188°C. Temperature on the new scale will be in °P, where 0.0°P will be correspond to -60.0°C, near the melting point of propylene glycol, and 100°P will correspond to 190.0°C, near the boiling point of propylene glycol. If a substance has a temperature of 49.0°P, what would be its temperature in °C?
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