5. Give the ground state electronic configuration of each of the following. You may abbreviate complete shells as a noble gas in brackets (e.g. [He]. [Ar]). a) Cu* b) Fe c) Au d) Nd³- e) Mo6 ) Os-

Introduction to Chemical Engineering Thermodynamics
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ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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I have done 5a, b and C. 

5. Give the ground state electronic configuration of each of the following. You may abbreviate
complete shells as a noble gas in brackets (e.g. [He], [Ar]).
a) Cu*
b) Fe
c) Au+
d) Nd3+
e) Mo
f) Os8.
3
6. Identify the elements that have the ground-state electron configurations:
a) [Ne]3s*3p*
b) [Kr]5s?
c) [Ar]4s*3d
d) [Kr]5s²4d*
e) [Kr]5s°4d105p!
) [Xe]6s°4f
Transcribed Image Text:5. Give the ground state electronic configuration of each of the following. You may abbreviate complete shells as a noble gas in brackets (e.g. [He], [Ar]). a) Cu* b) Fe c) Au+ d) Nd3+ e) Mo f) Os8. 3 6. Identify the elements that have the ground-state electron configurations: a) [Ne]3s*3p* b) [Kr]5s? c) [Ar]4s*3d d) [Kr]5s²4d* e) [Kr]5s°4d105p! ) [Xe]6s°4f
Expert Solution
Step 1

5

(d)

Given ion is Nd3+.

Atomic number of Nd is 60.

There are 60 electrons in Nd and 57 electrons in Nd3+ ion due to loss of 3 electrons..

 

Write the electron configuration of Nd3+ as follows:

Nd3+ = 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 4f3= Xe 4f3

 

Therefore, the required solution is Xe 4f3.

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