2. The lifetimes of two types of LEDs were compared, two samples were collected and the following are the results (in 1000 hours) n mean Type I st.dev. 25 56.8 4.3 Type II 18 54.6 3.6 Find a 95% confidence interval for the difference of the two means. Using the CI, test the hypothesis that the means are equal.
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- Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of u = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9 ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the Decision (step 5) for this problem? There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 7.3 ppb. O There is sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. O There is…Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of µ = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the calculation (step 4) for this problem? Z = -2.34 z = 2.34 z = 2.24 z = -2.24Above Answer is Wrong, Please Help!
- A medical researcher wishes to see whether the pulse rates of smokers are higher than the pulse rates of nonsmokers. Samples of 100 smokers and 100 nonsmokers are selected. The results are shown below. Smokers Nonsmokers X = 90 S1 = 5 nj = 100 X2 = 88 %3D S2 = 6 n2 = 100 a) Find a 99% confidence interval for the true mean difference in smokers pulse rates and nonsmokers pulse rates. b) At a = 0.05, can we conclude that the pulse rates of smokers is higher than the pulse rates on nonsmokers?A study was performed to determine whether men and women differ in repeatability in assembling components on a specific engine part. Random samples of 28 men and 25 women were selected, and each subject assembled the units. The two sample standard deviations of assembly time were S??? = 1.98 minutes and S????? = 2.31 minutes. Do we accept the claim that men and women differ in repeatability for this assembly task? Use α = 0.02. (Treat S??? ?? S1,??? S????? ?? S2) Find the: Parameter of interest: ? Null hypothesis: ? Alternative hypothesis: ? Test statistic: ? Reject H0 if: ? Computations: ? Conclusion: ?Vn 17:11. A stenographer claims that she can take dictation at the rate of 120 words Can we reject her claim on the basis of 100 trials in which she demonstrates a mean of 116 words with a standard deviation of 15 words ? Use 5 per cent level of significance.[Delhi Univ. B.A. (Econ. Hons.), 1990] per minute. wiz to Isvol 2 10 000
- Please help me understand. Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and proportions of each group answering yes'' are given below. Pop. 1:Pop. 2:n1=95,n2=94,p^1=0.8p^2=0.568 Suppose that the data yields (0.1088,0.3552) for a confidence interval for the difference p1−p2 of the population proportions. What is the confidence level? (Give your answer in terms of percentages.) Confidence Level = %8/10Two random samples of 29 individuals were selected. One sample participated in an activity which simulates hard work. The average breath rate of these individuals was 22 breaths per minute. The other sample did some normal walking. The mean breath rate of these individuals was 12. Find the 90% confidence interval of the difference in the breath rates if the population standard deviation was 4.1 for breath rate per minute. Use μ1 for the mean breath rate of individuals stimulated with hard work. Round the answers to one decimal place. <μ1-μ2
- PLEASE ANSWER USING THESE 7 STEPS:-PARAMETER OF THE INTEREST-NULL HYPOTHESIS-ALTERNATIVE HYPOTHESIS-TEST STATISTICS-REJECT Ho IF -COMPUTATIONS-CONCLUSIONThe mean noise level of 19 randomly selected areas designated as emergency rooms was 63.1 dBA and the sample standard deviation is 5.0 dBA. The mean noise level for 24 randomly selected areas designated as operating theaters was 56.3 dBA and the sample standard deviation was 7.0 dBA. An engineer reported a confidence interval of (1.8454, 11.409) for the difference in the mean noise level between areas designated as emergency rooms and areas designated for operating theaters, but neglected to specify the significance level. Estimate the significance level of the confidence interval if the population standard deviations, 01 and oz of the two populations are unknown and unequal. At the estimated significance level, could it be concluded that there is a difference in the means?How many subjects participated in an independent-samples t-test if a researcher reports,t (20) = 3.68, alpha = .05, two-tail?