2. The lifetimes of two types of LEDs were compared, two samples were collected and the following are the results (in 1000 hours) n mean Type I st.dev. 25 56.8 4.3 Type II 18 54.6 3.6 Find a 95% confidence interval for the difference of the two means. Using the CI, test the hypothesis that the means are equal.
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- HelpA group of students sampled water from 34 lakes in St. Joseph County. If the mean dissolvedoxygen level was 3.2 with a standard deviation of .57 find a 90% confidence interval for thedissolved oxygen levels in St Joseph County lakes.The 87.19% confidence interval estimate for p was (0.2, 0.38). Find p′ and ME. pp′= ME=
- A2.28/10Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…
- People with high blood pressure suffer from hypertension. Data on fasting blood sugar (milligrams/deciliter) and magnesium (milligrams/deciliter) in blood specimens collected from 50 patients diagnosed with hypertension were collected. The accompanying technology printout gives 95% confidence intervals for the mean fasting blood sugar (FBS) and mean magnesium level (MAG). Use this information to complete parts a through d below. Variable Mean StDev SE Mean 958 CI FBS 50 104.99 37.05 5.24 94.47, 115.51 ) MAG 50 1.83173 0.05298 0.00749 ( 1.8166B, 1.84678) a. Locate and interpret the 95% confidence interval for mean fasting blood sugar on the printout. (Type integers or decimals. Do not round.) O A. The 95% confidence interval for mean fasting blood sugar indicates that the mean fasting blood sugar level will be between and milligrams per deciliter in 95% of similarly constructed samples. B. The 95% confidence interval for mean fasting blood sugar indicates that the true mean fasting…Independent students show that the average length of education of 70 r/s California adults is 12.7 years with standard deviation 5.33 years, while the figures of 36 r/s Hawaii adults are 14.2 and 3.15 . Construct a 98% confidence interval for the difference between the overall average length of educations of California adults and that of Hawaii adults.7.1-6. To determine whether the bacteria count was lower in the west basin of Lake Macatawa than in the east basin, n = 37 samples of water were taken from the west basin and the number of bacteria colonies in 100 milliliters of water was counted. The sample characteris- tics were = 11.95 and s= 11.80, measured in hundreds of colonies. Find an approximate 95% confidence interval for the mean number of colonies (say, w) in 100 milliliters of water in the west basin.
- A study was carried out to compare the mean compressive strength of two types of concrete. 10 samples of each type of concrete were collected. Data (in psi) are presented in the next table. (The data table is in the picture) Assuming normality, determine a 95% confidence interval for the difference of the stockings and interpret it. Note: Solve what is requested step by step in order to arrive at the answer, do not skip steps.Page 2 of 6 A study of the growth of a certain kind of orchid showed that (under controlled conditions) a mm random sample of 40 of these orchids grew on the average, x = 32.5 уear тm Given that s = 3.2 construct a 99% confidence interval for the true mean annual growth %3D уear of this kind of orchid.#21)