== 13.6 A multinomial experiment with k = 3 cells and n = 320 produced the data shown in the accompanying table. Do these data provide sufficient evidence to contradict the null hypothesis that p₁ = .25, P2 = .25, and pз = .50? Test, using a = .05. p3 Cell 1 2 3 ni 78 60 182
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
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- Shown below is a randomization dotplot for sample differences in student pulse rates during a quiz versus listening to a lecture. Use the randomization dotplot to answer the questions that follow: The randomization dotplot is based on 5000 simulated samples under the null hypothesis assumption that there is no difference in mean pulse rates during a quiz versus during a lecture. The alternative hypothesis is that the difference is greater than zero (or that the mean pulse rate is higher during a quiz). If we assume the null hypothesis is true, of the choices below, which of these sample differences would be the least likely to occur (or, to say it another way, which would give the strongest evidence in favor of the alternative hypothesis?…The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,95110,951 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 184184 of their customers and calculates that these customers used an average of 11,162kWh11,162kWh of electricity last year. Assuming that the population standard deviation is 1263kWh1263kWh, is there sufficient evidence to support the power company's claim at the 0.050.05 level of significance? Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.10.3.15-T In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsible for long-term memory storage, in adolescents. The researchers randomly selected 20 adolescents with alcohol use disorders to determine whether the hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm. An analysis of the sample data revealed that the hippocampal volume is approximately normal with no outliers and x= 8.03 cm and s =0.8 cm°. Conduct the appropriate test at the a= 0.01 level of significance. Ho: = 9.02 H1:p < 9.02 (Type integers or decimals. Do not round.) Identify the t-statistic. to = - 5.53 (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.)
- Ackerman and Goldsmith (2011) report that students who study from a screen (phone, tablet, or computer) tended to have lower quiz scores than students who studied the same material from printed pages. To test this finding, a professor identifies a sample n=16 of students who used the electronic version of the course textbook and determines that this sample had an average score of M=72.5 on the final exam. During the previous three years, the final exam scores for the general population of students taking the course averaged μ=77 with a standard deviation of σ=8 and formed a roughly normal distribution. The professor would like to use the sample to determine whether students studying from an electronic screen had exam scores that are significantly different from those for the general population. Assuming a two-tailed test, state the null hypothesis in a sentence that includes the two variables being examined. Using the standard four-step procedure, conduct a two-tailed hypothesis…of LO %24 2. Based on their records, a hospital claims that the proportion, p, of full-term babies born in the community that weigh more than 7 pounds is 36%. A pediatrician who works with several hospitals in the community would like to verify the hospital's claim. In a random sample of 180 babies born in the community, 46 weighed over 7 pounds. Is there enough evidence to reject the hospital's claim at the 0.01 level of significance? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H. H:p=0.36 H: pD -2.921 (d) Find the p-value. (Round to three or more decimal places.) (e) Can we reject the claim that the proportion of full-term babies born in the community that weigh more than 7 pounds is 36%? OYes ONo tab 1. 3. 4. 9. 7. 8. 6. 0. opun %23 %3D i %3D ABCResearchers conducted trials to investigate the effects of color on creativity. Subjects with a. Red background were asked to think of creative uses for a brick; other subjects with a blue background were given the same task. Responses were scored by a panel of judges and results from scores of creativity are given in the accompanying table. Higher scores correspond to more creativity. The researchers make the claim that "blue enhances performance on a creative task". Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. what are the null and alternative hypothesis identify the test statistic ifentify the p value
- Looking at the above summary statistics from July 2020 for patients with confirmed Covid-19 in adult critical care, answer the following questions: What is the sample size for patients with confirmed COVID 19 were in Adult Critical Care beds in the sample hospital (Hammersmith Hospital) What is the sample size for All critical care units for Patients with confirmed COVID19 Give a brief explanation of SD Give a brief explanation of IQR How old were the patients in General Adult Critical Care with confirmed COVID19 one SD below the mean at Hammersmith Hospital How old were the patients in General Adult Critical Care with confirmed COVID19 on the 25th centile at Hammersmith Hospital Calculate .6.38 Parasitic worm. Lymphatic filariasis is a disease caused by a parasitic worm. Complications of the disease can lead to extreme swelling and other complications. Here we consider results from a randomized experiment that compared three different drug treatment options to clear people of the this parasite, which people are working to eliminate entirely. The results for the second year of the study are given below:46 Clear at Year 2 Not Clear at Year 2 Three drugs Two drugs Two drugs annually 52 2 31 24 42 14 (a) Set up hypotheses for evaluating whether there is any difference in the performance of the treatments, and also check conditions. (b) Statistical software was used to run a chi-square test, which output: x2 = 23.7 df = 2 p-value = 7.2e-6 Use these results to evaluate the hypotheses from part (a), and provide a conclusion in the context of the problem.9.4 Differences between Proportions
- An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 52 43 Intermediate 55 44 Full sized 61 45 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sized H0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized H0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?Electronic H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?Electronic Find the…4.5.11 Assigned Media Question Help A professional basketball star who had a reputation for being a poor free throw shooter made 5096 of the 9725 free throws that he attempted, for a success ratio of close to the value of 0.524? (Hint: A proportion is said to be "reasonably close" if it 0.524. A simulation was developed to generate random numbers between 1 and 1000. An outcome of 1 through 524 was considered to be a free throw that is made, and an outcome of 525 through 1000 was considered to be a free throw that is missed. The list below shows the results for five generated numbers where 1 represents a free throw that was made and 0 represents a free throw that was missed. Complete parts (a) and (b). a. Is the proportion of successful free throws P from the simulation reasonably is within the given success ratio ± the probability of a single event.) No, P is not reasonably close to the value of 0.524. Yes, P is reasonably close to the value of 0.524. 1 1 0 0 b. The simulation was…Q. 3 A researcher calculated the negative predictive value of a test for carriers of X-linked ornithine transcarbamylase deficiency (OTCD - a disorder of the urea cycle). A test known as the "allopurinol test" is often used as a screening device of potential carriers whose relatives are OTCD patients. Sensitivity and specificity of the allopurinol test is estimated the as 0.927 and 0.997 respectively Also the prevalence is estimated in the population of individuals with OTCD as (1/32000). Use this information and Bayes theorem to calculate the predictive value negative of the allopurinol screening test.
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