A two-way ANOVA experiment with interaction was conducted. Factor A had three levels (columns), factor B had five levels (rows), andsix observations were obtained for each combination. Assume normality in the underlying populations. The results include thefollowing sum of squares terms:SST=1542 SSA= 1042 SSB = 358 SSAB = 39a. Construct an ANOVA table. (Round "MS" to 4 decimal places and "F" to 3 decimal places.)ANOVASource of VariationRowsColumnsInteractionErrorTotalSS0dfAnswer is not complete.0MSFp-value0.0000.0000.002

The experiment is a -way ANOVA.Factor A has (columns ) levels Factor B has (rows) levels No. of…

Answered: A two-way ANOVA experiment with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q18. Why do we conduct post hoc analysis in ANOVA? a. To make a comparison on individual adjusted R-squares B. To make a comparison of the individual group meansC. To make a comparison of the individual group scatter plots D. None of the above
Two samples with P, =.25,n, = 36 and p, = .3,n, = 49. Test if populations p, # p, at a= 0.05 level of significance. 8 %3D
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
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At age 9 the average weight for both boys and girls are exactly the same. A random sample of 9 year olds gave the following results.... Boys: Girls:Sample Size: 65 50Mean weight (lbs): 130 125Pop. Variance: 120 130 At alpha 0.05, do the data support the claim that there is a difference in heights?
Which choice would be correct? Extraneous variables that are not directly studied but may influence the DV can be statistically controlled by: a. ANOVA b. ANCOVA c. Friedman's two-way ANOVA d. MANOVA
The data is presented in parallel format. Before running the ANOVA in Excel, you will need to put it into serial (column) format. You will need to create a categorical variable for the first factor (days) and for the second factor (time of day). This is a critical step.The data presented shows exam scores for students randomly assigned to the sections meeting on these days at these times of the day: Thursday Friday Morning Afternoon Morning Afternoon 70.878.15978.246.646.476.559.376.370 65.678.359.359.778.680.892.780.865.392.3 90.890.569.177.36977.558.677.877.558.6 63.372.854.254.472.166.26372.56672.2 Conduct a 2-way ANOVA. First, find the group means for each level of the factors. (Report answers accurate to 2 decimal places.)Days: MThursday=MThursday= MFriday=MFriday= Time of day: Mmorning=Mmorning= Mafternoon=Mafternoon= Report the results of the ANOVA for the main & interaction effects. (Report P-values accurate to 4 decimal places and…
A two-way ANOVA experiment with no interaction is conducted. Factor A has four levels (columns) and Factor B has eight levels (rows). Assume normality in the underlying populations. The results include the following sum of squares terms: SST=367.5 SSA = 207.0 SSE = 52.4 a. Construct an ANOVA table. (Round "SS" and "MS" to 2 decimal places and "F" to 3 decimal places.) ANOVA Source of Variation Rows Columns Error Total SS X Answer is complete but not entirely correct. 207.00 X 108.10 X 52.40 367.50 df 7 3 21 31 MS 29.57 X 36.03 X 2.50 F 11.850 X 14.412 X p- value 0.001 0.000
A study was conducted of 90 adult male patients following a new treatment for congestive heart failure. One of the variables measured on the patients was the increase in exercise capacity (in minutes) over a 4-week treatment The previous treatment regime had produced an average increase of μ = 2 minutes. The researchers wanted to evaluate whether the new treatment had increased the value of μ in comparison to the previous treatment. The sample data yielded ?̅ = 2.17 and ? = 1.05: Using α = 05, what conclusions can you draw about the research hypothesis?

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