Two brands of batteries are tested, and their voltage is compared. The data follow. Test the elaim that voltage of brand X is less than voltage of brand Y. Assume that both variables are normally distributed. use a 0.05 level of significance. Brand X Brand Y sample mean = 8.2 Sample mean= 8.4 O, = 0.3 n, = 27 oy = 0.1 ny = 30
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- For the population of college students, the number of hours spent studying per week is normally distributed with a = 4.40 and = 2.32 hours. We surveyed a random sample of students majoring in psychology about the number of hours they spent studying this past week. The data is as follows: 6, 8, 9, 4, 3, 11, 4, 6, 5, 7 What is the dependent variable? What is the level of measurement of the dependent variable? 3. Is there a significant increase in the number of hours spent studying for our sample compared to the population of college students? Perform a complete hypothesis test (z-test) using alpha = .01 level. SHOW ALL WORKA physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =SHOW YOUR SOLUTION COMPLETELY. MAKE SURE YOUR FINALS ANSWERS SHOULD BE IN 4 DECIMAL PLACES.
- J In-shop othesis test for the difference between two population proportions 02562 2600368.qx3zqy7 Jump to level 1 The manager of a coffee shop is trying to determine if drive-through customers buy fewer items than customers who come into the shop. The manager randomly samples both populations and calculates the proportion of customers in each that buy three or more items. The results of the data collected are shown below. What are the population parameters? Y Pick Drive-through Successes 27 Successes What is the level of significance? Ex: 0.12 Observations 76 Observations 41 119 0.345 p-hat_1 0.355 p-hat_2 What is the null hypothesis Ho? Pick Confidence Level 0.1429 What is the alternative hypothesis Ha? Pick p-value Should Ho be rejected or does Ho fail to be rejected? Pick What conclusion can be drawn from the data? Pick evidence exists to support the claim that drive-through customers buy fewer items than in-shop customers. 2 p WThe following results are from an independent-measures, two-factor study with n = 10 participants in each treatment condition. Factor A: Factor B: A₁ A₂ B₁ n = 10 M = 4 T = 40 SS = 50 n = 10 M = 5 T = 50 SS = 60 ΣΧ2 = 640 Factor B: B₂ n = 10 M = 1 T = 10 SS = 30 n = 10 M = 2 T = 20 SS = 40Ost watched Ani... Question 2 Y Part 1 of 4 A doctor in Cleveland wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 9% level of significance to test whether the average life span of heart disease patients in Cleveland differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 7.4, 7.8, 7.7, 7.5, 8, 8.2, 7.8, 8.6, 8, 7.8, 8.3, 8.3, 8, 7.6, 8.2, 7.9, 7.3, 8, 8.6, 7.3, 8.3, 8, 7.8, 8, 7.8, 8.1, 8.1, 8, 7.6, 7.6, 7.7, 7.4, 7.7, 7.8, 7.8 Life Span of Patients Treated at Hospital 2: 7.9, 7.9, 8.2, 8, 8.1, 8.5, 8.3, 8.4, 8, 8.2, 7.7, 8, 8, 7.8, 7.9, 8.1, 8.1, 7.8, 7.9, 8, 8.5, 8.3, 8.2, 8.3, 7.8, 7.9 Life Span of Patients Treated at Hospital 3: 8.2, 8.1, 7.4, 8.7, 8.6, 8.2, 7.9, 8.1, 8.1, 8.3, 8.3, 8, 7.6, 8, 7.4, 8.6, 8.2, 8.2, 7.9, 7.7, 8.1, 7.9, 8, 8.3 Life Span of…
- You run a PPM correlation on sprint speed and vertical jump height in NFL running backs and find an r value of 0.89. Your sample has a mean sprint speed of 11 m/s ± 0.3 m/s and a mean jump height of 0.49 m ± 0.3 m. What is the effect size estimate? 2.96 0.89 -35.033 35.033 0.267Alpha equals 0.01 level of significance for the given sample data.Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. a. Identify the independent and dependent variables. b. In a sentence, state the null hypothesis being tested. c. Using symbols, state the null and alternative hypotheses. d. Determine the critical region using a one-tailed test with alpha = .05. e .Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). f. State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). g. Based on your analysis, is there a relationship between the drug and attention span?
- A program administrator at a high school wanted to see if there was a significant association between experiencing verbal abuse and anxiety in teenage women. She wasn't sure what to expect. Perform the correct statistical procedure to assess the degree of association between these variables and interpret your findings. Set alpha = .05 for your statistical test. YOU CAN EITHER TYPE YOUR WORK OUT HERE OR TAKE A PICTURE OF HANDWRITTEN WORK AND EMAIL IT TO ME. %3D Anxiety Verbal Abuse 5. 4. 4.Let X be a random variable with X = -3and oz 5. Find the mean and the variance of Y = -2X -3A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 50 men and 74 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women Mean N StDev SE Mean Men Women 95% Cl for mu Men - mu Women (- 10.67, - 1.13) T-Test mu Men = mu Women (vs H2 B. Ho: H1 = H2;