The formula for the family-wise error rate when conducting multiple comparisons with t-tests is 1 - (1 - α)c. Could you intuitively explain where this formula comes from? That is, why does subtracting the quantity (1 - α)c from one calculate the cumulative probability of a type I error?
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The formula for the family-wise error rate when conducting multiple comparisons with t-tests is 1 - (1 - α)c.
Could you intuitively explain where this formula comes from? That is, why does subtracting the quantity (1 - α)c from one calculate the cumulative
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- A diet center wanted to test three different methods for losing weight to determine if the average weight loss (reported in pounds/week) for each method is the same. The results for the three methods are tabulated below. Given that there is a significant difference between the three methods, use the Tukey test to determine if there is a significant difference between each pair of methods. Let a=0.05. (picture attached)Cardiovascular Disease Suppose the incidence rate of myocardial infarction (MI) was 5 per 1000 among 45- to 54-year-old men in 2000. To look at changes in incidence over time, 5000 men in this age group were followed for 1 year starting in 2010. Fifteen new cases of MI were found. 7.14 Of the 15 new MI cases in the preceding study, 5 died within 24 hours. Test whether the 24-hour case- fatality rate changed from 2000 to 2010.Standard Error is a measure of how much the point estimate changes from sample to sample. The proportion of heads from flipping five coins has a relatively large standard error (SE = .2236), and it is not uncommon to see point estimates from 0% to 100%. The proportion of heads from flipping 1000 coins has a relatively small standard error (SE = .0158), and points estimates will rarely fall outside 45% to 55% heads. Р(1 — р) For proportions, the formula is SE = where n is the sample size and p = p, the sample n proportion (point estimate). Compute the standard error, given a) point estimate = 0.61, null value = 0.7, and n = 120. The standard error = b) point estimate = 0.42, null value = 0.5, and n = 50. The standard error =
- 13% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 341 people from the inner city surveyed, 41 of them suffered from sleep apnea. What can be concluded at the level of significance of α= 0.01?(please show your answer to 3 decimal places.) a. The test statistic = (please show your answer to 3 decimal places.) b.The p-value = (Please show your answer to 4 decimal places.)Cardiovascular Disease Suppose the incidence rate of myocardial infarction (MI) was 5 per 1000 among 45- to 54-year-old men in 2000. To look at changes in incidence over time, 5000 men in this age group were followed for 1 year starting in 2010. Fifteen new cases of MI were found. A- Of the 15 new MI cases in the preceding study, 5 died within 24 hours. Test whether the 24-hour case fatality rate changed from 2000 to 2010. B- Suppose we eventually plan to accumulate 50 MIcases during the period 2010–2015. Assume that the24-hour case-fatality rate is truly 20% during this period.How much power would such a study have in distinguishingbetween case-fatality rates in 2000 and 2010–2015 if atwo-sided test with significance level .05 is planned?To examine the relationship between alcohol consumption and birth weight, a researcher selects a sample of n = 20 pregnant rats and mixes alcohol with their food for 2 weeks before the pups are born. One newborn pup is randomly selected from each subject’s litter and the average with weight for the n = 20 pups is recorded. It is known that the average birth weight for regular rats (without exposure to alcohol) is μ = 5.6 grams. What type of test would you use to test the hypothesis that alcohol consumption during pregnancy reduces birth weights? Would you use a one-tailed or two-tailed test? What would be an appropriate measure of effect size to report?
- Studies show that the level of anxiety has changed since the pandemic. The average score before the pandemic was mu equal to 36. A sample of 20 individuals surveyed in the past two weeks produced M=37.6 and s=9.8. Based on the sample, was there a significant difference in the average anxiety level since the pandemic started at the 5% significance level? What is the positive critical value? (a)2.093 (b)2.086 (c)1.729 (d)1.725Suppose you live in a city where 10% of the population has had Coronavirus. There is an antibody test that screens to see whether you have had the disease. Like all medical tests, it is not perfect; the sensitivity is 93.8% and the specificity is 95.6%. [These are real figures for a particular test.] These numbers refer to the true positive and true negative rate, respectively; that is, sensitivity is P(positive test|had disease) and specificity is P(negative test|did not have disease).
