A process that produces titanium forgings for automobile turbocharger wheels is to be controlled through use of a fraction nonconforming chart. Initially, one sample of size 150 is taken each day for twenty days, and the results shown in the table below are observed. (a) Establish a control chart to monitor future production. (b) What is the smallest sample size that could be used for this process and still give a positive lower control limit on the chart? Nonconforming Unit Data Nonconforming Nonconforming Day Units Day Units 1 3242521205 1234567 8 9 10 3 11 12 13 14 15 16 17 18 19 20 2413601232
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- A process sampled 20 times with a sample of size 8 resulted in = 29.5 and R = 1.4. Compute the upper and lower control limits for the x chart for this process. (Round your answers to two decimal places.) UCL = LCL = Compute the upper and lower control limits for the R chart for this process. (Round your answers to two decimal places.) UCL = LCL =A housing development can only build on a certain plot of land if can show that the average level of arsenic in the groundwater is less than 60 parts-per-million (ppm). Soil samples are drawn from the site and tested in a lab. The results of the samples (in ppm) are given below. Is there enough evidence to say that the land is ready for development using a level of significance of 5%? You may assume that the level of ground arsenic is normally distributed in the area. Sample Reults: 16 50 35 80 15 27 99 a. Enter the null hypothesis for this test. Hoe 78 b. Enter the alternative hypothesis for this test. H₁: 78 78 c. is the original claim located in the null or alternative hypothesis? Select an answer d. What is the test statistic for the given statistics? e. What is the p-value for this test? f. What is the decision based on the given statistics? Select an answer 68 11 98 34 g. What is the correct interpretation of this decision? Using a level of significance, there Select an answer…If the average fraction defective of a large sample of products is 0.1537, calculate the control limits (given that sub-group size is 2000).
- Doritos chips are one of the most popular chips in the year 2020. Frito-Lay produces snack-sized bags of Doritos with 1.75-ounce bags. Unfortunately, Frito-Lay has received many complaints that the bags of chips lack the promised amount of chips. PepsiCo, the owner of Frito-Lay, decide to run an internal investigation of their Doritos chip production. They sample around 500 bags of chips to discover that they found an average of 1.59 ounces with a standard deviation of .12 ounces. Conduct a hypothesis test with an alpha-level of .05. Should they change their production of Doritos chips to match the 1.75 ounces on the bag?Polyunsaturated fatty acids in the diet favorably affect several risk factors for cardiovascular disease. The principal dietary polyunsaturated fat is linoleic acid. Suppose we randomly selected twelve adults for our study. We took their blood pressure measurements (systolic blood pressure) at the start and recorded them for each adult. Then we placed required these adults to consume 23g/day of safflower oil which is high in linoleic acid for four weeks. At the end of the four weeks, we took another systolic blood pressure(SBP) measurement. The paired data is provided below: Subject 1 2 3 4 5 6 7 8 9 10 11 12 Baseline SBP 119.67 100.00 123.56 109.89 96.22 133.33 115.78 126.39 122.78 117.44 111.33 92.39 1-month SBP 117.33 98.78 123.83 107.67 95.67 128.89 113.22 121.56 126.33 110.39 107.00 93.06 Use the appropriate nonparametric test at alpha level of 0.05, to test whether the diet heavy in linoleic acid increases systolic blood pressure (SBP).Polyunsaturated fatty acids in the diet favorably affect several risk factors for cardiovascular disease. The principal dietary polyunsaturated fat is linoleic acid. Suppose we randomly selected twelve adults for our study. We took their blood pressure measurements (systolic blood pressure) at the start and recorded them for each adult. Then we placed required these adults to consume 23g/day of safflower oil which is high in linoleic acid for four weeks. At the end of the four weeks, we took another systolic blood pressure(SBP) measurement. The paired data is provided below: Subject 1 2 3 4 5 6 7 8 9 10 11 12 Baseline SBP 119.67 100.00 123.56 109.89 96.22 133.33 115.78 126.39 122.78 117.44 111.33 92.39 1-month SBP 117.33 98.78 123.83 107.67 95.67 128.89 113.22 121.56 126.33 110.39 107.00 93.06 Use the appropriate nonparametric test at alpha level of 0.05, to test whether the diet heavy in linoleic acid increases systolic blood pressure (SBP). Use Steps 0-5
- If we collect a sample of blood platlet counts much larger than the sample included with exercise 3, and if our sample includes a single outlier, how will that outlier appear in a histogramThe Environmental Protection Agency (EPA) has collected data on LC50 measurements (concen- trations that kill 50% of test animals) for certain chemicals likely to be found in freshwater rivers and lakes. For certain species of fish, the LC50 measurements (in parts per million) for DDT in 12 experiments were as follows: 16, 5, 21, 19, 10, 5, 8, 2, 7, 2, 4, 9 Assume that the LC50 measurements have an approximately normal distribution. Construct a 95% confidence interval for the true mean LC50 for DDT.Two different types of injection-molding machines are used to form plastic parts. A part is considered defective if it has excessive shrinkage or is discolored. Two random samples, each of size 300, are selected, and 16 defective parts are found in the sample from machine 1, while 8 defective parts are found in the sample from machine 2. Is it reasonable to conclude that both machines produce the same proportion of defective parts? Use a = 0.05. (a) Test the hypothesis Ho: P₁ = P2 verses H₁: P₁ P2. What is zo? Round your answer to two decimal places (e.g. 98.76). Zo = (b) Is it reasonable to conclude that both machines produce the same proportion of defective parts?
- True or FalseCalculate the S control chart limits for a process with average X-bar equal to 700, and S-bar equal to 8, when using a sample size of n = 3. The specifications are 705 ± 15 and the process output is normally distributed, LCL = 3.42, UCL = 12.58 LCL = 0, UCL = 20.54 LCL = 0.94, UCL = 15.06 LCL = 0, UCL = 16.71 O LCL = 2.27, UCL = 13.73Blood cocaine concentration (mg/L) was determinedboth for a sample of individuals who had died fromcocaine-induced excited delirium (ED) and for a sampleof those who had died from a cocaine overdose withoutexcited delirium; survival time for people in bothgroups was at most 6 hours. The accompanying datawas read from a comparative boxplot in the article“Fatal Excited Delirium Following Cocaine Use” (J.of Forensic Sciences, 1997: 25–31). ED 0 0 0 0 .1 .1 .1 .1 .2 .2 .3 .3.3 .4 .5 .7 .8 1.0 1.5 2.7 2.83.5 4.0 8.9 9.2 11.7 21.0Non-ED 0 0 0 0 0 .1 .1 .1 .1 .2 .2 .2.3 .3 .3 .4 .5 .5 .6 .8 .9 1.01.2 1.4 1.5 1.7 2.0 3.2 3.5 4.14.3 4.8 5.0 5.6 5.9 6.0 6.4 7.98.3 8.7 9.1 9.6 9.9 11.0 11.512.2 12.7 14.0 16.6 17.8 a. Determine the medians, fourths, and fourth spreadsfor the two samples.b. Are there any outliers in either sample? Any extremeoutliers?c. Construct a comparative boxplot, and use it as abasis for comparing and contrasting the ED andnon-ED samples.