Table 7E.3 Data for Exercise 7.7 Number of Sample Nonconforming Sample Number of Nonconforming Number Assemblies Number Assemblies 1 7 11 6 2 4 12 15 3 1 13 0 4 3 14 9 5 6 15 6 8 16 7 10 17 8 9 10 10 527 18 6145 5 19 7 20 12 m D; = 117; p = n = 100; m = 20; Σ D₁ = i=1 ΣΤΟ mn p(1 − p) UCL₂ = p +3 LCL₂ = p-3 n |p(1 − p) n
Table 7E.3 Data for Exercise 7.7 Number of Sample Nonconforming Sample Number of Nonconforming Number Assemblies Number Assemblies 1 7 11 6 2 4 12 15 3 1 13 0 4 3 14 9 5 6 15 6 8 16 7 10 17 8 9 10 10 527 18 6145 5 19 7 20 12 m D; = 117; p = n = 100; m = 20; Σ D₁ = i=1 ΣΤΟ mn p(1 − p) UCL₂ = p +3 LCL₂ = p-3 n |p(1 − p) n
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 92E
Related questions
Question
The data in Table 7E.3 give the number of nonconforming bearing and seal assemblies in samples of size 100. Construct a fraction nonconforming control chart for these data. If any points plot out of control, assume that assignable causes can be found and determine the revised control limits.
n=100;" " m=20;" " ∑_(i=1)^m▒D_i =117;" " p ̄=(∑_(i=1)^m▒D_i )/mn
"UC" "L" _p=p ̄+3√((p ̄(1-p ̄))/n)
"LC" "L" _p=p ̄-3√((p ̄(1-p ̄))/n)
Draw x-bar control chart and R chart
Remove the data that are not in control and recalculate UCL, CL, LCL and redraw control chart.

Transcribed Image Text:Table 7E.3 Data for Exercise 7.7
Number of
Sample
Nonconforming
Sample
Number of
Nonconforming
Number
Assemblies
Number
Assemblies
1
7
11
6
2
4
12
15
3
1
13
0
4
3
14
9
5
6
15
6
8
16
7
10
17
8
9
10
10
527
18
6145
5
19
7
20
12
m
D; = 117; p =
n = 100; m = 20; Σ D₁ =
i=1
ΣΤΟ
mn
p(1 − p)
UCL₂ = p +3
LCL₂ = p-3
n
|p(1 − p)
n
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