(IN SAS) Again, consider the text file called muscle which consists of paired data of individual'smuscle mass and age. We want to examine this relationship. Pick up where you left off in thelast topic.a. In the last lab, you should have decided a simple linear regression model was a goodway to model this data. Write a code to fit a Model.b. What does the slope mean?C.Predict the muscle mass for a 66-year-old person.d. Calculate a 98% CI for the muscle mass for a 40-year-old. mass age82.0 71.091.0 64.0100.0 43.068.0 67.087.0 56.073.0 73.078.0 68.080.0 56.065.0 76.084.0 65.0116.0 45.076.0 58.097.0 45.0100.0 53.0105.0 49.077.0 78.0

a. SAS Code to Fit a Simple Linear Regression Model The dataset contains muscle mass and age. Here's…

Answered: (IN SAS) Again, consider the text file…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Latitude Mortality 34 215 33.5 168 33 173 40.5 185 36 146 43.8 153 41 194 40 181 31 203 30 223 45.5 117 43 116 41.2 127 43.2 124 41.5 170 36.8 146 30.2 181 45.2 127 40 159 42.2 152 44.5 121 43 113 34.8 214 40.5 140 46 100 39.5 121 40 189 46.8 135 43.2 168 37 135 40 153 76.5 52 34.5 200 39.2 136 38.5 176 45 137 38.8 125 38.8 146 35.8 177 47.8 89 35 186 32.5 232 37.5 146 42 144 35.5 175 44.5 122 38.8 128 46.5 103 43 136
Week Job Sat Score 1 It is 6% higher It is 12% higher It is 43% higher They are the same 2 3 4 5 6 7 8 3.40 3.60 3.70 3.80 3.90 4.20 4.00 4.10 Absence Rate 0.05 0.04 0.06 0.03 0.04 0.03 0.04 0.05 Quality Score 0.88 0.89 0.90 0.92 0.83 0.91 0.92 0.83 How does the job satisfaction score for weeks 5-8 compare to weeks 1-4? It is 43% lower Output Score 8 10 9 10 8 10 9 Weekly Goals: Job Satisfaction Score ≥ 4.50, Absence Rate ≤ 0.03, Quality Score ≥ 0.95, Output Score ≥ 9 9
Monthly Sales 6267.19 7058.06 7119.5 7147.18 7198.52 7298.09 7325.7 7335.68 7355.97 7481.05 7490.23 7530.08 7616.09 7682.69 7684.14 7704.12 7704.98 7779.28 7798.23 7815.15 7844.16 7890.21 7977.6 7993.16 8021.03 8028.37 8068.86 8082.42 8096.17 8119.25 8129.21 8190.68 8255.28 8282.44 8376.31 8392.4 8400.95 8451.16 8456.66 8505.35 8539.25 8543.65 8573.05 8641.78 8667.48 8751.08 8777.97 8800.08 8888.65 8907.03 9096.87 9241.74 9411.68 9450.73 9484.62 9514.57 9521.4 9524.91 9733.44 10123.24 Given the company’s performance record and based on the empirical rule of normal distribution (also known as the 68%-95%-99.7% rule), what would be the lower bound of the range of sales values that contains 68% of the monthly sales? What would be the upper bound of the range of sales values that contains 68% of the monthly sales?
Cyclic Consumer 12.9 0.9 Full data set Industrial -29.3 47.2 5.9 49.5 -22 18.1 23.6 15.9 3.8 -1.3 -2.7 33.5 8.3 -8.9 9.1 -9.3 13.9 7.3 22.7 9.6 45.4 -6.5 - 18.8 -5.6 41.6 -3.5 0.6 29.3 15.7 -9.7 4.8 4.9 -5.9 32.9 27.2 4.5 11.6 11.3 4.3 34.8 16.7 - 22.3 2.9 - 27.8 43.2 7.1 - 12.9 13.6 39.5 -27.1 3.3 7.7 32.8 6.7 36.6 24.8 11.3 -0.9 222 -23 29.5 - 16.8 -3.9 16.3 66 26.5 11.4 0.1 20.5 72.8 26.8 27.9 222 2.6 -8.2 -9.5 10.2 - 15.2 7.3 -4.7 6.3 49.7 - 26.7 9.6 20.7 -4.5 16.1 3.7 21.9 23.1 16.7 8.9 -0.4 4.5 27.9 20.9 24 18.4 5.6 21.4 8.9 9.2 -6.7 4.8 - 3.3 -6.4 27.1 -9.3 36.2 -1.7 -0.4 44.7 15.2 51.2 -8.7 31.1 5.9 0.7 19.2 15.6 1.9 94 6.8 9.5 26.7 -7.2 -8.3 -6.3 73.4 5.9 - 16.2 18.7 87.5 - 10.4 -9.5 21.4 -2.9 -5.2 2.1 21.2 12.8 11.7 22.1 23.3 1.2 9.8 - 19.9 9.3 30.5 6.8 55.7 - 11.7 16.9 13.6 -3.6 3.2 2.8 -3.1 5.6 4.4 79.5 16.4 38.2 9.1 - 26.6 -9.8 8.9 6.4 26.4 67.6 -41.8 44.3 - 17.4 -2.8 5.1 14.3 -55 -6.9 11.7 -8.6 14.3 13.8 17.1 - 8.2 -0.9 -9.6 9.2 129.3 -3.3 27.1 28.7 - 39.8 36 4.4 28.3…
The mean age of two people in a room is 20 years. A 50 year old person enters the room. What is the mean age of the 3 people in the room now 20 30 33.3 35 none of the above
Age 1950 Population 1950 Mortality Rate per 100,000 1990 Population 1990 Mortality Rate per 100,000 2000 Population 2000 Mortality Rate per 100,000 < 20 15,541,000 11.6 18,926,000 10.5 22,335,000 10.1 20 – 29 18,789,000 23.5 22,335,000 17.8 25,465,000 16.9 30 – 39 11,435,000 43.2 13,123,000 38.7 17,438,000 40.2 40 – 49 8,586,000 115.6 10,809,000 98.8 13,789,000 94.5 50 – 59 6,234,000 310.8 9,120,000 385.8 11,983,000 401.0 60+ 3,749,000 435.0 6,890,000 567.9 9,387,000 785.7 Calculate the direct adjusted mortality rate for both 1950 and 1990 using the 2000 information as the standard. (Hint: Make a table to show the expected number of deaths for each year). Also include the ratio of 1990 mortality rate to 1950 mortality rate.
Identify the following values. Consider the function shown with a graphical depiction of limƒ ( x = L , including the roles XC of & and d. 201 1.8- 1.6 1.4- 1.2- Y 1.0- 0.8- 0.6- 0.4 0.2- 0.0+T 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 1. 1.6 2. 1.0 E = 3. 0.4 = %3D 4. 0.6 >
Calculate my average exam 1=35 exam 2= 47 exam 3=67 exam 4= 80.625 homework 1b = 95.14 homework 2a= 98.42 homework 2b= 98.36 homework 3a = 97.15 homework 3b= 97.94 homework 4a= 99.49 homework 4b = 97.54 homework 5a= 92.35 homework 5b=92.80 homework 6= 95.71 homework 7a = 94.70 homework 7b = 94.84 homework 8a = 84.86 homework 8b = 94.02 homework 9a= 79.06 Achieve practice 1a= 100 achieve practice 1b= 100 achieve practice 2a =100 achieve practice 2b= 100 achieve practice 3a =100 achieve 3b = 100 achieve practice 4a= 100 achieve practice 5a= 100 achieve practice 5b = 100 achieve practice 6 = 100 achieve practice 7a = 100 achieve practice 7b = 100 achieve practice 8a= 100 achieve practice 8b = 100 achieve practice 9a= 100 achieve practice 9b = 0 recitation= 93
Arsenic Amounts Arkansas 4.80 4.90 5.02 5.37 5.43 5.37 5.60 5.61 5.57 5.91 5.97 6.12 California 1.50 3.71 3.95| 4.45| 4.94| 5.12 5.33 5.35 5.41 5.49 5.56 5.61 Texas 5.57 5.82 6.62 6.90 6.85 6.88 | 7.05 7.34 7.48| 7.58 7.71 | 7.73 I
Year Change_Over_Five_Days Change_For_Entire_Year1 0.2 -0.22 0.2 -0.13 0.2 1.84 -0.4 1.25 -0.1 -0.36 0.2 -0.67 -0.1 0.88 -0.9 1.89 0.2 -0.710 0.1 -1.011 0.2 -1.0
A researcher wanted to explore whether scores showed improvement based on the hours of practice. The data includes the increase in scores for a specific task and the corresponding number of hours each participant spent practicing that task. What is the predicted score for 130 hours of practice? Please provide your answer using whole numbers; decimals are not necessary.
Time Spent Studying and Social Media

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