The weight of plastic pellets for an injection molding process is a characteristic of interest. A random sample of 15 pellets is selected and gives the following weights in grams) 22770 17 19 22 21 222 2222 17 19 18 18 2220 21 222 20 21 ssuming the distribution of the weight of pellets to be normal, find a two-sided 95% atistical tolerance limits that contain 90% of the population.
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- To build a 86% CI for the mean of a population, you take a random sample of 31 values and find s = 18. What is the Margin of Error, E? Round the Critical Value and your answer to three decimals. Submit Question torA random sample of 100 4-oz packs of roasted peanuts yields an average weight of 3.91 oz. Assume that the s.d. of this brand of 4-oz packs of roasted peanuts is 0.35 oz. Does this sampling result suggest that the overall average weight of this brand of 4-oz packs of roasted peanuts is below 4 oz? Use an appropriate p-value to draw and explain your conclusionsA sample of 60 obese adults was put on a low carbohydrate diet for a year. The average weight loss was 11 Ibs. and the standard deviation was 9 Ibs. Calculate a 99% lower tolerance bound covering 95% of the proportion of amount of weight loss. O 8.3 O -8.8 O -10.1 O 8.9
- Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. Identify the test statistic and p-value. Right arm Left arm 144 167 OA.T-3.07, p-value = 0.037 OB. T = -2.32, p-value = 0.081 OC. T = -1.93, p-value = 0.127 OD. T = -4.01, p-value = 0.016 133 161 132 179 138 145 136 144The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Stance duration (ms) was measured in separate samples of younger and older adults. younger: n=22 mean=801 s=117 older: n=16 mean=780 s=81 Test the claim that the true average stance is different between younger and older adults. Let population 1= younger population 2= older a. What is the appropriate procedure to test the claim? b.What is the degrees of freedom? Use the conservative formula. c.At 0.05 significance level, what is/are the critical value/s? d.What is the value of the test statistic? Use 2 decimal places e.Construct a 95% confidence interval estimate, what is the margin of error? Use 2 decimal places.The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Stance duration (ms) was measured in separate samples of younger and older adults. younger: n=22 mean=801 s=117 older: n=16 mean=780 s=81 Test the claim that the true average stance is different between younger and older adults. Let population 1= younger population 2= older a. What is the appropriate procedure to test the claim? b.Construct a 95% confidence interval estimate, what is the margin of error? Use 2 decimal places.
- Listed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. ASsume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation. All measurements are in years. Click the icon to view the table of longevities of archbishops and monarchs. ....... What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs. OB. Ho H1 = H2 A. Ho: H1 H2 H1:H1 H2 O D. Ho: H1 #H2 H1:H1>H2 The test statistic is . (Round to two decimal places as needed.)Find the proportion of N.d. observations with a zz-score between z_1 =z1= -2.45 and z_2 =z2= 2.71. Give your answer to four decimal places.The screws to be used on a building construction have an average length of 20 cm withStd Dev of 0.9 cm, following a Normal Distribution.The specifications for the minimum and maximum lengths are 17.5 cm and 23 cmrespectively. If a batch of 100,000 screws is received, how many would be acceptedbecause they are inside the specifications?