2每張試題卷得必填寫(學號)、(姓名) The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00 ml sample 20.00 ml portion of the dilution was was refluxed with 40.00 mL. of 0,04672 M KOH: CHCOOCH, + OH CH;COO + CHOH [+] After cooling, the excess OH was back-titrated with 3,4I ml, of 0.05042 M H;SO.Calculate the number of grams of eth acetate (FM 88.11 g/mol) per 100 ml. of the original sample 11. The amount of Na:S;O) consumed in the back-titration is (a) 0.3439 mmole (b) 0.2625 mmole (c) 0.1874 mmole (c 0.0928 mmole 12. The number of grams of ethyl acetate is (a) 0.4305 g (b) 0.5655 g (c) 0.6718 g (d) 0.7288 g
2每張試題卷得必填寫(學號)、(姓名) The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00 ml sample 20.00 ml portion of the dilution was was refluxed with 40.00 mL. of 0,04672 M KOH: CHCOOCH, + OH CH;COO + CHOH [+] After cooling, the excess OH was back-titrated with 3,4I ml, of 0.05042 M H;SO.Calculate the number of grams of eth acetate (FM 88.11 g/mol) per 100 ml. of the original sample 11. The amount of Na:S;O) consumed in the back-titration is (a) 0.3439 mmole (b) 0.2625 mmole (c) 0.1874 mmole (c 0.0928 mmole 12. The number of grams of ethyl acetate is (a) 0.4305 g (b) 0.5655 g (c) 0.6718 g (d) 0.7288 g
Chemistry
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Chapter1: Chemical Foundations
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![2每張試題春務必填寫(學號)、 (姓名)。
The etnyl acetate concentration in an alcoholic solution was determined by diluting a 10.00 ml. sample to 100.00 ml. A
20.00 ml portion of the dilution was was refluxed with 40.00 mL of 0,04672 M KOH:
CHCOOCHs+OH CHCOO+CH,OH
After cooling, the excess OH was back-titrated with 3.41 ml of 0.05042 M H,SO.Calculate the number of grams of ethyl
acetate (FM 88.11 g/mol) per 100 ml. of the original sample
11. The amount of Na:S:Os consumed in the back-titration is (a) 0.3439 mmole (b) 0.2625 mmole (c) 0.1874 mmole (d)
0.0928 mmole
12. The number of grams of ethyl acetate is (a) 0.4305 g (b) 0.5655 g (c) 0.6718 g (d) 0.7288 g](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdba417f5-a4d2-4d92-bcc4-12015dcf226e%2F843b0ff0-bb55-4d01-9554-6fda83c74c79%2Fgb1026k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2每張試題春務必填寫(學號)、 (姓名)。
The etnyl acetate concentration in an alcoholic solution was determined by diluting a 10.00 ml. sample to 100.00 ml. A
20.00 ml portion of the dilution was was refluxed with 40.00 mL of 0,04672 M KOH:
CHCOOCHs+OH CHCOO+CH,OH
After cooling, the excess OH was back-titrated with 3.41 ml of 0.05042 M H,SO.Calculate the number of grams of ethyl
acetate (FM 88.11 g/mol) per 100 ml. of the original sample
11. The amount of Na:S:Os consumed in the back-titration is (a) 0.3439 mmole (b) 0.2625 mmole (c) 0.1874 mmole (d)
0.0928 mmole
12. The number of grams of ethyl acetate is (a) 0.4305 g (b) 0.5655 g (c) 0.6718 g (d) 0.7288 g
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