C,H,Cl, Doublet at 1.70 ppm (3H) Multiplet at 4.32 ppm (1H) Doublet at 5.85 ppm (1H)

Chemistry
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Chapter1: Chemical Foundations
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I need help with the second part, C3H5Cl3. Thanks!

**Analyzing NMR Spectral Data for Molecular Structure Determination**

In order to determine the structure of the given compounds, we are provided with NMR spectral data. This information allows us to identify parts of the molecule and construct the complete molecular structure.

### Compound 1: C₁₅H₁₄O

- **Triplet at 2.1 ppm (2H):** Indicates the presence of a CH₂ group adjacent to a group such as a carbonyl or alkene.
- **Triplet at 2.4 ppm (2H):** Suggests another CH₂ group environment, possibly near an electronegative atom or functional group.
- **Multiplet at 7.2-7.9 ppm (10H):** A typical range for aromatic protons, suggesting the presence of a benzene ring or similar aromatic structure.

### Compound 2: C₃H₅Cl₃

- **Doublet at 1.70 ppm (3H):** The signal from a CH₃ group next to a CH group.
- **Multiplet at 4.32 ppm (1H):** Usually indicates a proton on a carbon adjacent to chlorine or another electronegative group.
- **Doublet at 5.85 ppm (1H):** Typically indicates vinyl protons, suggesting the presence of an alkene or conjugation with another group.

---

### Structure Identification Process

1. **Analyze Chemical Shifts:** Chemical shifts give insights into the local magnetic environment of protons in a molecule, influenced by electronegativity and functional groups.
   
2. **Integrate Proton Counts:** Use the integration values to confirm the number of hydrogen atoms represented by each signal, assisting in deducing molecular fragments.

3. **Determine Connectivity:** Consider the splitting patterns (doublets, triplets, multiplets) to determine how these fragments combine into a full molecular structure.

4. **Assign Pieces:** Place fragments together, using given shifts and splittings to assign functional groups and propose a molecular structure.

---

Use this information to build the structures of these compounds, corroborating data against known chemical environments and NMR patterns.
Transcribed Image Text:**Analyzing NMR Spectral Data for Molecular Structure Determination** In order to determine the structure of the given compounds, we are provided with NMR spectral data. This information allows us to identify parts of the molecule and construct the complete molecular structure. ### Compound 1: C₁₅H₁₄O - **Triplet at 2.1 ppm (2H):** Indicates the presence of a CH₂ group adjacent to a group such as a carbonyl or alkene. - **Triplet at 2.4 ppm (2H):** Suggests another CH₂ group environment, possibly near an electronegative atom or functional group. - **Multiplet at 7.2-7.9 ppm (10H):** A typical range for aromatic protons, suggesting the presence of a benzene ring or similar aromatic structure. ### Compound 2: C₃H₅Cl₃ - **Doublet at 1.70 ppm (3H):** The signal from a CH₃ group next to a CH group. - **Multiplet at 4.32 ppm (1H):** Usually indicates a proton on a carbon adjacent to chlorine or another electronegative group. - **Doublet at 5.85 ppm (1H):** Typically indicates vinyl protons, suggesting the presence of an alkene or conjugation with another group. --- ### Structure Identification Process 1. **Analyze Chemical Shifts:** Chemical shifts give insights into the local magnetic environment of protons in a molecule, influenced by electronegativity and functional groups. 2. **Integrate Proton Counts:** Use the integration values to confirm the number of hydrogen atoms represented by each signal, assisting in deducing molecular fragments. 3. **Determine Connectivity:** Consider the splitting patterns (doublets, triplets, multiplets) to determine how these fragments combine into a full molecular structure. 4. **Assign Pieces:** Place fragments together, using given shifts and splittings to assign functional groups and propose a molecular structure. --- Use this information to build the structures of these compounds, corroborating data against known chemical environments and NMR patterns.
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