The decomposition of dinitrogen pentoxide occurs by the following reaction. 2 N₂O5 4 NO2(g) + O2(g) - The experimentally determined rate law is Rate = k [N₂O5] and at this particular temperature, the rate constant has the value 0.200 min-¹. When the concentration of N₂O5 is 0.800 M, what is the rate of production of NO₂(g)? Report your answer im M min-¹ but do not enter any units. Use three significant digits. Your Answer: Your Answer

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The decomposition of dinitrogen pentoxide occurs by the following reaction.
2 N2O5 - 4 NO2(g) + O₂(g)
The experimentally determined rate law is Rate = k [N₂O5] and at this particular
temperature, the rate constant has the value 0.200 min-¹.
When the concentration of N2O5 is 0.800 M, what is the rate of production of
NO2(g)?
Report your answer in M min 1 but do not enter any units. Use three significant
digits.
Your Answer:
Your Answer
Transcribed Image Text:The decomposition of dinitrogen pentoxide occurs by the following reaction. 2 N2O5 - 4 NO2(g) + O₂(g) The experimentally determined rate law is Rate = k [N₂O5] and at this particular temperature, the rate constant has the value 0.200 min-¹. When the concentration of N2O5 is 0.800 M, what is the rate of production of NO2(g)? Report your answer in M min 1 but do not enter any units. Use three significant digits. Your Answer: Your Answer
273.15 K = 0 °C NA = 6.02,
RT/F = 0.025693 V (RT/F) In10 = 0.059160 V @ T = 298.15 K
R = 8.3145 J K-1 mol-¹ = 0.082057 L atm K-1 mol-1
F = 96,485.3 C/mol
1 atm = 1.01325 bar = 760 Torr = 101325 Pa
1023 mol-1
Transcribed Image Text:273.15 K = 0 °C NA = 6.02, RT/F = 0.025693 V (RT/F) In10 = 0.059160 V @ T = 298.15 K R = 8.3145 J K-1 mol-¹ = 0.082057 L atm K-1 mol-1 F = 96,485.3 C/mol 1 atm = 1.01325 bar = 760 Torr = 101325 Pa 1023 mol-1
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