Consider this reaction:H₂CO3 (aq) → H₂O (aq) + CO₂ (aq)At a certain temperature it obeys this rate law.rate = (0.126 s¯¹) [H₂CO3]SSuppose a vessel contains H₂CO3 at a concentration of 0.920M. Calculate the concentration of H₂CO3 in the vessel 8.70 seconds later. You may assume noother reaction is important.Round your answer to 2 significant digits.Mx10XŚ

Answered: Consider this reaction: H₂CO3 (aq) →…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Consider this reaction:
H₂CO3 (aq) → H₂O (aq) + CO₂ (aq)
At a certain temperature it obeys this rate law.
rate = (0.126 s¯¹) [H₂CO3]
S
Suppose a vessel contains H₂CO3 at a concentration of 0.920M. Calculate the concentration of H₂CO3 in the vessel 8.70 seconds later. You may assume no
other reaction is important.
Round your answer to 2 significant digits.
M
x10
X
Ś

Expert Solution

Step 1: Determine the concentration of carbonic acid remaining afeter 8.70 s by using given data:

Given,

The reaction:

$H subscript 2 C O subscript 3 space left parenthesis a q right parenthesis end subscript space rightwards arrow space H subscript 2 O subscript left parenthesis a q right parenthesis end subscript space plus space C O subscript 2 space subscript left parenthesis a q right parenthesis end subscript T h e space r a t e space l a w space o f space t h e space r e a c t i o n colon r a t e space equals space left parenthesis space 0.126 space s to the power of negative 1 end exponent space right parenthesis space open square brackets H subscript 2 C O subscript 3 close square brackets I n i t i a l space c o n c e n t r a t i o n space o f space H subscript 2 C O subscript 3 space equals space 0.920 space M t i m e space t a k e n space f o r space t h e space r e a c t i o n space equals space 8.70 space s e c o n d s.$

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