If 2.00 moles of propanol, C3H;O, needed to absorb 110.0 kJ of heat to be vaporized at 97.0 °C (the boiling point), then what was the initial temperature of the propanol? C3H§O(1) → C3H&O(g) AH°, = +47.5 kJ/mole vap C,(C3H&O) = 2.40 J/g•°C

Chemistry: Matter and Change
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Chapter15: Energy And Chemical Change
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Problem 78A: Alloys When a 58.8-g piece of hot alloy is placed in125 g of cold water in a calorimeter, the...
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If 2.00 moles of propanol, C3H;O, needed to absorb 110.0 kJ of heat to be vaporized at
97.0 °C (the boiling point), then what was the initial temperature of the propanol?
C3H§O(1) → C3H&O(g)
AH°,
= +47.5 kJ/mole
vap
C,(C3H&O) = 2.40 J/g•°C
Transcribed Image Text:If 2.00 moles of propanol, C3H;O, needed to absorb 110.0 kJ of heat to be vaporized at 97.0 °C (the boiling point), then what was the initial temperature of the propanol? C3H§O(1) → C3H&O(g) AH°, = +47.5 kJ/mole vap C,(C3H&O) = 2.40 J/g•°C
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