15 g of solid MgCl2 is mixed with 30 g of water in a calorimeter that absorbs no heat. Which equation calculates the temperature change? Question 16 options: (15 g / 53.49 g mol–1 × –159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) (15 g / 53.49 g mol–1 × 159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) –(15 g / 53.49 g mol–1 × –159850 J mol–1) / (45 g × 4.184 J g–1 °C–1)
15 g of solid MgCl2 is mixed with 30 g of water in a calorimeter that absorbs no heat. Which equation calculates the temperature change? Question 16 options: (15 g / 53.49 g mol–1 × –159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) (15 g / 53.49 g mol–1 × 159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) –(15 g / 53.49 g mol–1 × –159850 J mol–1) / (45 g × 4.184 J g–1 °C–1)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
15 g of solid MgCl2 is mixed with 30 g of water in a calorimeter that absorbs no heat. Which equation calculates the temperature change?
Question 16 options:
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(15 g / 53.49 g mol–1 × –159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) |
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(15 g / 53.49 g mol–1 × 159850 J mol–1) / (30 g × 4.184 J g–1 °C–1) |
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–(15 g / 53.49 g mol–1 × –159850 J mol–1) / (45 g × 4.184 J g–1 °C–1) |
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