A cubic piece of platinum metal (specific heat capacity = 0.1256 J/ °C g) at 200.0 °C is dropped into 1.00 L of deuterium oxide ('heavy water,' specific heat capacity = 4.211 J/ °C g) at 25.5 °C. The final temperature of the platinum and deuterium oxide mixture is 40.9 °C. The density of platinum is 21.45 g/cm³ and the density of deuterium oxide is 1.11 g/mL. What is the edge length of the cube of platinum, in centimeters? 1 4 7 +/- 2 5 8 ● cm 3 6 9 O X C x 100

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**Physics Problem: Heat Transfer and Density**

**Problem Statement:**

A cubic piece of platinum metal, with a specific heat capacity of 0.1256 J/(°C·g), is initially at a temperature of 200.0 °C. This cube is then immersed in 1.00 L of deuterium oxide (also known as 'heavy water'), which has a specific heat capacity of 4.211 J/(°C·g), initially at 25.5 °C. Upon reaching thermal equilibrium, the final temperature of both the platinum and deuterium oxide is 40.9 °C.

Given:
- Density of platinum: 21.45 g/cm³
- Density of deuterium oxide: 1.11 g/mL

Question: Determine the edge length of the cube of platinum in centimeters.

**Approach:**

This is a heat transfer problem where you'll use the principle of conservation of energy. The heat lost by the platinum will equal the heat gained by the deuterium oxide, allowing you to calculate the mass of the platinum cube, and thus its volume and edge length.
Transcribed Image Text:**Physics Problem: Heat Transfer and Density** **Problem Statement:** A cubic piece of platinum metal, with a specific heat capacity of 0.1256 J/(°C·g), is initially at a temperature of 200.0 °C. This cube is then immersed in 1.00 L of deuterium oxide (also known as 'heavy water'), which has a specific heat capacity of 4.211 J/(°C·g), initially at 25.5 °C. Upon reaching thermal equilibrium, the final temperature of both the platinum and deuterium oxide is 40.9 °C. Given: - Density of platinum: 21.45 g/cm³ - Density of deuterium oxide: 1.11 g/mL Question: Determine the edge length of the cube of platinum in centimeters. **Approach:** This is a heat transfer problem where you'll use the principle of conservation of energy. The heat lost by the platinum will equal the heat gained by the deuterium oxide, allowing you to calculate the mass of the platinum cube, and thus its volume and edge length.
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