A new metal alloy was created in the laboratory for use in applications where a strong but light metal is required. An experiment was done to determine the specific heat of the new alloy. 31.37 grams of the alloy was heated to 99.8 °C in a hot water bath and then placed into 98.83 grams of water at 20.4 °C. The temperature of the alloy + water combined reached a temperature of 25.9. Determine the specific heat (in (J/g°C) of the alloy based on this experiment. • The specific heat of water is 4.184 J/g°C. • Assume that no heat is lost to the surroundings. • Round your answer to the 1000th place (3 decimal places) Type your answer.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A new metal alloy was created in the laboratory for use in applications where a strong but light metal is required. An experiment was done to determine the specific heat of the
new alloy. 31.37 grams of the alloy was heated to 99.8 °C in a hot water bath and then placed into 98.83 grams of water at 20.4 °C. The temperature of the alloy + water
combined reached a temperature of 25.9.
Determine the specific heat (in (J/g°C) of the alloy based on this experiment.
• The specific heat of water is 4.184 J/g®C.
• Assume that no heat is lost to the surroundings.
• Round your answer to the 1000th place (3 decimal places)
Type your answer.
Transcribed Image Text:A new metal alloy was created in the laboratory for use in applications where a strong but light metal is required. An experiment was done to determine the specific heat of the new alloy. 31.37 grams of the alloy was heated to 99.8 °C in a hot water bath and then placed into 98.83 grams of water at 20.4 °C. The temperature of the alloy + water combined reached a temperature of 25.9. Determine the specific heat (in (J/g°C) of the alloy based on this experiment. • The specific heat of water is 4.184 J/g®C. • Assume that no heat is lost to the surroundings. • Round your answer to the 1000th place (3 decimal places) Type your answer.
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