A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('heavy water,' specific heat capacity = 4.211 J/°C g) at 25.5°C. The final temperature of the platinum and deuterium oxide mixture is 29.1°C. The density of platinum is 21.45 g/ cm³ and the density of deuterium oxide is 1.11 g/mL. What is the edge length of the cube of platinum, in centimeters?
A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('heavy water,' specific heat capacity = 4.211 J/°C g) at 25.5°C. The final temperature of the platinum and deuterium oxide mixture is 29.1°C. The density of platinum is 21.45 g/ cm³ and the density of deuterium oxide is 1.11 g/mL. What is the edge length of the cube of platinum, in centimeters?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Heat Transfer and Density Calculations
A cubic piece of platinum metal, with a specific heat capacity of 0.1256 J/°C·g, is initially at a temperature of 200.0°C. When submerged into 1.00 L of deuterium oxide ('heavy water'), which has a specific heat capacity of 4.211 J/°C·g, the system's initial temperature is 25.5°C. Upon reaching thermal equilibrium, the final temperature of the platinum and deuterium oxide mixture is 29.1°C.
#### Given Data
- **Platinum Metal:**
- Initial Temperature = 200.0°C
- Specific Heat Capacity = 0.1256 J/°C·g
- Density = 21.45 g/cm³
- **Deuterium Oxide:**
- Volume = 1.00 L
- Initial Temperature = 25.5°C
- Specific Heat Capacity = 4.211 J/°C·g
- Density = 1.11 g/mL
#### Problem
Calculate the edge length of the cube of platinum, expressed in centimeters.
### Calculation Approach
1. **Calculate the Mass of Deuterium Oxide:**
\[
\text{Mass} = \text{Density} \times \text{Volume} = 1.11 \, \text{g/mL} \times 1000 \, \text{mL} = 1110 \, \text{g}
\]
2. **Energy Transfer (Heat Balance):**
The heat lost by platinum equals the heat gained by deuterium oxide:
\[
(m_{\text{Pt}} \cdot c_{\text{Pt}} \cdot \Delta T_{\text{Pt}}) = (m_{\text{D2O}} \cdot c_{\text{D2O}} \cdot \Delta T_{\text{D2O}})
\]
where:
- \( \Delta T_{\text{Pt}} = 200.0°C - 29.1°C \)
- \( \Delta T_{\text{D2O}} = 29.1°C - 25.5°C \)
3. **Calculate the Mass of Platinum:**
Use the formula above to find \( m_{\text{Pt}} \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38543b38-0ca2-4898-a226-639f5edfcbc9%2F0a369a23-0a1e-4bc8-a644-baf9d30f1fef%2Fehbujij_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Heat Transfer and Density Calculations
A cubic piece of platinum metal, with a specific heat capacity of 0.1256 J/°C·g, is initially at a temperature of 200.0°C. When submerged into 1.00 L of deuterium oxide ('heavy water'), which has a specific heat capacity of 4.211 J/°C·g, the system's initial temperature is 25.5°C. Upon reaching thermal equilibrium, the final temperature of the platinum and deuterium oxide mixture is 29.1°C.
#### Given Data
- **Platinum Metal:**
- Initial Temperature = 200.0°C
- Specific Heat Capacity = 0.1256 J/°C·g
- Density = 21.45 g/cm³
- **Deuterium Oxide:**
- Volume = 1.00 L
- Initial Temperature = 25.5°C
- Specific Heat Capacity = 4.211 J/°C·g
- Density = 1.11 g/mL
#### Problem
Calculate the edge length of the cube of platinum, expressed in centimeters.
### Calculation Approach
1. **Calculate the Mass of Deuterium Oxide:**
\[
\text{Mass} = \text{Density} \times \text{Volume} = 1.11 \, \text{g/mL} \times 1000 \, \text{mL} = 1110 \, \text{g}
\]
2. **Energy Transfer (Heat Balance):**
The heat lost by platinum equals the heat gained by deuterium oxide:
\[
(m_{\text{Pt}} \cdot c_{\text{Pt}} \cdot \Delta T_{\text{Pt}}) = (m_{\text{D2O}} \cdot c_{\text{D2O}} \cdot \Delta T_{\text{D2O}})
\]
where:
- \( \Delta T_{\text{Pt}} = 200.0°C - 29.1°C \)
- \( \Delta T_{\text{D2O}} = 29.1°C - 25.5°C \)
3. **Calculate the Mass of Platinum:**
Use the formula above to find \( m_{\text{Pt}} \
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