Ether has a Vapor Pressure of 385 torr at 20.0 °C. You dissolve 1.57 moles of a non-volatile compound (non-electrolyte) into 5.00 moles of Ether. What is the Vapor Pressure of Ether (in torr) above this solution at 20.0°C?

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Constants:
- \( c = 2.9979 \times 10^8 \, \text{m/s} \)
- \( h = 6.626 \times 10^{-34} \, \text{J s per one photon} \)
- \( R = 8.314 \, \text{J/(K mol)} = 0.08206 \, \text{L atm/(K mol)} \)
- \( N_A = 6.022 \times 10^{23} \, \text{particles/mol} \)
- \( R_H = 1.097 \times 10^7 \, \text{m}^{-1} = 2.178 \times 10^{-18} \, \text{J} \)

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**Given Problem:**

Ether has a Vapor Pressure of 385 torr at 20.0 °C.

You dissolve 1.57 moles of a non-volatile compound (non-electrolyte) into 5.00 moles of Ether.

**Problem Statement:**
What is the Vapor Pressure of Ether (in torr) above this solution at 20.0 °C?

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**Answer:**
\[ \_\_\_\_\_\_\_\_\_\_\_\_ \]
Transcribed Image Text:### Constants: - \( c = 2.9979 \times 10^8 \, \text{m/s} \) - \( h = 6.626 \times 10^{-34} \, \text{J s per one photon} \) - \( R = 8.314 \, \text{J/(K mol)} = 0.08206 \, \text{L atm/(K mol)} \) - \( N_A = 6.022 \times 10^{23} \, \text{particles/mol} \) - \( R_H = 1.097 \times 10^7 \, \text{m}^{-1} = 2.178 \times 10^{-18} \, \text{J} \) --- **Given Problem:** Ether has a Vapor Pressure of 385 torr at 20.0 °C. You dissolve 1.57 moles of a non-volatile compound (non-electrolyte) into 5.00 moles of Ether. **Problem Statement:** What is the Vapor Pressure of Ether (in torr) above this solution at 20.0 °C? --- **Answer:** \[ \_\_\_\_\_\_\_\_\_\_\_\_ \]
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