The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is TNT. Calculate the vapor pressure of the solution at 25 °C when 8.925 grams of TNT, C₂H5N306 (227.1 g/mol), are dissolved in 261.0 grams of benzene. benzene = C6H6 = 78.12 g/mol. VP(solution) = Submit Answer mm Hg Retry Entire Group 9 more group attempts remaining
The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is TNT. Calculate the vapor pressure of the solution at 25 °C when 8.925 grams of TNT, C₂H5N306 (227.1 g/mol), are dissolved in 261.0 grams of benzene. benzene = C6H6 = 78.12 g/mol. VP(solution) = Submit Answer mm Hg Retry Entire Group 9 more group attempts remaining
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.94QE
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![The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is
TNT.
Calculate the vapor pressure of the solution at 25 °C when 8.925 grams of TNT, C7H5N306 (227.1 g/mol), are
dissolved in 261.0 grams of benzene.
benzene = C6H6 = 78.12 g/mol.
VP(solution)
=
Submit Answer
mm Hg
Retry Entire Group 9 more group attempts remaining
Cengage Learning Cengage Technical Support
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Transcribed Image Text:The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is
TNT.
Calculate the vapor pressure of the solution at 25 °C when 8.925 grams of TNT, C7H5N306 (227.1 g/mol), are
dissolved in 261.0 grams of benzene.
benzene = C6H6 = 78.12 g/mol.
VP(solution)
=
Submit Answer
mm Hg
Retry Entire Group 9 more group attempts remaining
Cengage Learning Cengage Technical Support
Previous
Next>
Save and Exit
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