Vapor Pressure Lowering The vapor pressure of a pure solvent is REDUCED when a nonvolatile solute is added. This is summarized by Raoult's Law: Psolution = Xsolvent Posolvent Where: Psolution is the vapor pressure of the solution Xsolvent is the mole fraction of the solvent in the solution = (mol solvent)/(mol solvent + mol solute) Pºsolvent is the vapor pressure of the pure solvent As more solute particles are added, the mole fraction of the solvent goes down, and the vapor pressure is reduced.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.85QE
icon
Related questions
Question
Vapor Pressure Lowering
The vapor pressure of a pure solvent is REDUCED when a nonvolatile solute is added.
This is summarized by Raoult's Law:
Psolution = Xsolvent Posolvent
Where:
Psolution is the vapor pressure of the solution
Xsolvent is the mole fraction of the solvent in the solution = (mol solvent)/(mol solvent + mol solute)
Pº solvent is the vapor pressure of the pure solvent
As more solute particles are added, the mole fraction of the solvent goes down, and the vapor pressure is reduced.
Transcribed Image Text:Vapor Pressure Lowering The vapor pressure of a pure solvent is REDUCED when a nonvolatile solute is added. This is summarized by Raoult's Law: Psolution = Xsolvent Posolvent Where: Psolution is the vapor pressure of the solution Xsolvent is the mole fraction of the solvent in the solution = (mol solvent)/(mol solvent + mol solute) Pº solvent is the vapor pressure of the pure solvent As more solute particles are added, the mole fraction of the solvent goes down, and the vapor pressure is reduced.
The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in
chloroform is aspirin.
Calculate the vapor pressure of the solution at 25 °C when 12.85 grams of aspirin, C9Hg04 (180.1 g/mol), are
dissolved in 186.9 grams of chloroform.
chloroform =
VP(solution)
=
CHCl3 = 119.40 g/mol.
mm Hg
Transcribed Image Text:The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in chloroform is aspirin. Calculate the vapor pressure of the solution at 25 °C when 12.85 grams of aspirin, C9Hg04 (180.1 g/mol), are dissolved in 186.9 grams of chloroform. chloroform = VP(solution) = CHCl3 = 119.40 g/mol. mm Hg
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Solutions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:
9781938168390
Author:
Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning