18. The results for sieve analysis is shown in the following table: Sieve No. 4 10 20 40 60 100 200 % Passing 69.3 59.1 48.3 38.5 28.4 19.8 4.5 Liquid Limit Plastic Limit Non-Plastic (NP) Non-Plastic (NP) a. Determine the classification of soil according to AASHTO. b. Determine the classification of soil according to USCS.

18. The results for sieve analysis is shown in the following table: Sieve No. 4 10 20 40 60 100 200 % Passing 69.3 59.1 48.3 38.5 28.4 19.8 4.5 Liquid Limit Plastic Limit Non-Plastic (NP) Non-Plastic (NP) a. Determine the classification of soil according to AASHTO. b. Determine the classification of soil according to USCS.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
4. Classify the following soil by the Unified Soil Classification System: Percent passing No.4 sieve = 82 Percent passing No.10 sieve = 71 Percent passing No.40 sieve = 64 Percent passing No. 200 sieve = 41 Plasticity index = 12 Liquid limit = 31
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 89% No.200 = 65% Liquid Limit= 44 Plastic Limit = 23
Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan U.S. Sieve N Mass of Soil Retained (g) Problem 5: Repeat problem 4 with the following data. 4 6 10 20 40 60 100 200 Pan 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 Mass of Soil Retained (g) 0 0 0 9.1 249.4 179.8 22.7 15.5 23.5
The following table shows the sieve analysis data on the left and hydrometer test data on the right for the minus No. 200 sieve material for a given soil. (a) Compute Cu and Cc. (b) Report the percentage gravel, sand, silt, and clay according to AASHTO. (c) Classify the soil according to AASHTO.
Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5
The following data are the results of a sieve analysis. Determine the percentage of silt and clay combined using Unified Classification System. Mass of soil Sieve no. Opening retained (mm) on each sieve 4 4.75 21.5 10 2 18.5 20 0.85 53.2 40 0.425 90.5 60 0.25 81.8 100 0.15 92.2 200 0.075 58.5 Pan 26.5 Select one: а. 19 b. none of the choices С. 6 d. 17 e. 58
Question 5 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 100 %3D Percent passing the No. 40 sieve = 80 • Percent passing the No. 200 sieve = 38 The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 40 and 15, respectively. Compute the group index. A) 1.75 1.0 2.5 2.0
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 88 6 2.380 69 10 2.000 62 20 0.840 51 40 0.420 39 60 0.250 31 100 0.149 18 200 0.074 14 LL 60 PL 20 Determine its classification using USCS. SC SM ML None of the above. CL