2. Determine the Unified Soil Classification System (USCS) classification for the followinginorganic soil. [Ans. CH].A. Grain Size Distribution Test.PercentSieveNo.410204060100200Passing (%)1001009995938886B. Plastic Limit TestTare NumberWt. Wet Soil + Tare (g)Wt. Dry Soil + Tare (g)Wt. of Tare (g)C. Liquid Limit TestDeterminationNumber of BlowsWater Content (%)126.547.245.40 5.951.17118691.172276433461

Unified soil classification system(USCS): (1) Classify the soil whether it is coarse or fine grained…

2. Determine the Unified Soil Classification System (USCS) classification for the following inorganic soil. [Ans. CH]. A. Grain Size Distribution Test. Percent Passing (%) 100 100 99 95 93 88 86 Sieve No. 4 10 20 40 60 100 200 B. Plastic Limit Test Tare Number Wt. Wet Soil + Tare (g) Wt. Dry Soil + Tare (g) Wt. of Tare (g) C. Liquid Limit Test Determination Number of Blows Water Content (%) 1 2 6.54 7.24 5.40 5.95 1.17 1 18 69 1.17 2 27 64 3 34 61

2. Determine the Unified Soil Classification System (USCS) classification for the following inorganic soil. [Ans. CH]. A. Grain Size Distribution Test. Percent Passing (%) 100 100 99 95 93 88 86 Sieve No. 4 10 20 40 60 100 200 B. Plastic Limit Test Tare Number Wt. Wet Soil + Tare (g) Wt. Dry Soil + Tare (g) Wt. of Tare (g) C. Liquid Limit Test Determination Number of Blows Water Content (%) 1 2 6.54 7.24 5.40 5.95 1.17 1 18 69 1.17 2 27 64 3 34 61

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Classify the following soils by the Unified (USCS) and AASHTO methods. Where necessary, assume CU = 7 and Cc=2.5. Soil No. 2 62 % Passing Soil No. 1 # 4 95 41 #10 88 # 40 33 11 81 2676 #200 65 21 LL 53 12 PL 36 USCS AASHTO Usily
Percentage Passing®o No. 200 | No.40 | No. 10 | No.4 | Ce Cu PL. LL :Classify the soil by A: The UscS give the name and symbol group. B: AASHTO classiflication system Give the group index for each soil. 2.6 16 61 | 64 66
Classify the following soils by the Unified soil classification system. Give the group na soil Soil 1 2 Sieve analysis (percentage finer) Liquid Plastic No. 4 No. 200 limit limit 98 28.5 33.2 22.6 95 10 30 22 D10 D30 8 D60 0.085 0.12 0.135 Q1)
Problem D: For problems 14 to 17. Classify the following soils by the AASHTO classification System. Description Percent finerthan No. 10 sieve A B C 83 100 48 90 Percent finerthan No. 40 sieve 48 92 28 76 Percentfinerthan No. 200 sieve 20 86 34 Liquid Limit Plasticity Index 20 70 37 12 plastic 32 Non- 14) Soil A is? a) A-2-4(0) b) A-2-6 (0) c) A-2-7 (1) d) A-1-b (0) 15) Soil Bis ? a) A-7-5(13) b) A-1-b(0) c) A-7-5 (16) d) A-7-5 (33) 16) Soil Cis ? a) A-6(5) b) A-7-6 (8) c) A-6 (2) d) A-1-a (0) 17) Soil D is ? a) A-6 (2) b) A-1-a (0) c) A-7-6 (4) d) A-2-6 (0)
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Percentage finer by weight 100% 80% 60% 40% 20% 0% 0.001 (c) Soil J (d) Soil L H 0.010 Ma 1.000 Soil Sample ID H I J #200 L 0.100 Particle size (mm) 46 37 #4 Liquid Limit Plastic Limit 60 26 Non plastic 34 18 10.000 AASHTO Classification: Classify the following soils using AASHTO criteria. (a) Soil H (b) Soil I 3° 100.00
Problem D: For problems 14 to 17. Classify the following soils by the AASHTO classification System. Description A D Percent finerthan No. 4 sieve 100 | 92 100 94 Percent finerthan No. 10 sieve 100 85 80 80 Percent finerthan No. 40 sieve 96 71 78 51 Percent finerthan No. 200 sieve 72 56 59 15 Liquid Limit Plasticity Index 16) Soil A is ? 58 35 42 26 23 19 13 12 a) A-7-5(19) b) A-2-6 (0) c) A-7-6 (18) d) A-7-5 (18) 17) Soil Bis ? a) A-6(13) b) A-7-5(0) c) A-6 (7) d) A-6 (8) 18) Soil Cis ? a) A-7-6(5) 19) Soil D is ? a) A-2-6(2) b) A-7-6 (8) c) A-7-6 (7) d) A-7-6(6) b) A-3 (0) c) A-2-6 (0) d) A-2-6 (2)
Classify soil B using USCS. LL-46%, PL=28%. Group symbol is and Group name is Grarel Sard Clay Coerse Med'um Fme 100 90 70 B 50 20 10 A 10 I 0.420 0.10 075 O 01 4.75 2 Particle Diameter (mm)
The sieve analysis of (2) soils and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given in the folllowing table. 1. Classify the soils according to Unified soil classification system (USCS) given the group symbol and name 2. Classify the soils according to AASHTO sistem and find the group index (GI) D10 Soil A B 4 98 100 Seive No % passing 20 40 50 28 100 99 10 86 100 60 100 200 18 14 10 95 90 73 Attereberg limits L.L P.L N.P 27 55 D30 D60 1.5 0.075 0.43 0.001 0.003 0.053
A sieve analysis test was performed for a dry soil sample with a total weight (490 gm). Sieve Mass of Sieve & Sieve Mass of Opening Retained Soil No. Sieve (gm) (mm) (gm) #4 4.75 512.38 538.25 #10 2.00 464.38 520.68 #20 0.85 411.99 538.21 #40 0.43 368.57 536.42 #60 0.25 528.66 593.34 #200 0.075 340.89 385.07 Pan 374.07 378.97 Calculate the Cc and Cu O a. 1.25 and 3.47 b. 1.1 and 3.6 C. 1.7 and 4.3 O d. 2.1 and 2.3 Ое. 2.4 and 5.3
Subject: Soil Mechanics A. Classify the Soil Using USCS (with explanation/ justification) Given data: D10 = ? D30= 0.0023mm D60= 0.032mm Liquid Limit= 49% Plastic Limit= 24% CHOICES: a. CL (lean clay with gravel) b. CL ( lean clay with sand) c. ML (silt with gravel) d. ML (Silt with sand)