Classify the soil according to the USCS1. Percent passing No. 4 Sieve = 70Percent passing No. 200 Sieve = 30Liquid Limit = 33Plasticity Index = 122. Percent passing No. 10 Sieve = 100Percent passing No. 40 Sieve = 80Percent passing No. 200 Sieve = 58Liquid Limit = 30Plasticity Index = 10Classify the soil according to AASHTODescriptionSOIL ASOIL BSOIL CPercent finer than No. 10 Sieve1009588Percent finer than No. 40 Sieve8075Percent finer than No. 200 Sieve5834Liquid Limit306039Plasticity Index104012

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Classify the soil according to the USCS 1. Percent passing No. 4 Sieve = 70 Percent passing No. 200 Sieve = 30 Liquid Limit = 33 Plasticity Index = 12 2. Percent passing No. 10 Sieve = 100 Percent passing No. 40 Sieve = 80 Percent passing No. 200 Sieve = 58 Liquid Limit = 30 Plasticity Index = 10 %3D

Classify the soil according to the USCS 1. Percent passing No. 4 Sieve = 70 Percent passing No. 200 Sieve = 30 Liquid Limit = 33 Plasticity Index = 12 2. Percent passing No. 10 Sieve = 100 Percent passing No. 40 Sieve = 80 Percent passing No. 200 Sieve = 58 Liquid Limit = 30 Plasticity Index = 10 %3D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Data Sieve Sieve No. Opening (mm) 4 4.750 10 2.000 20 0.850 30 0.600 40 0.425 60 0.250 140 0.106 200 0.075 Pan Mass of soil retained on each sieve, W (grams) 0 40.2 84.6 50.2 40.0 106.4 108.8 59.4 8.7 Percent of mass retained on each sieve. R Cumulative percent retained, Σ Rn Percent finer, 100 – Σ Rn
4. Classify the following soil by the Unified Soil Classification System: Percent passing No.4 sieve = 82 Percent passing No.10 sieve = 71 Percent passing No.40 sieve = 64 Percent passing No. 200 sieve = 41 Plasticity index = 12 Liquid limit = 31
Classify the following soil by the Unified Soil Classification System. Percent passing No. 4 sieve = 82Percent passing No. 10 sieve = 71Percent passing No. 40 sieve = 64Percent passing No. 200 sieve = 41Liquid limit = 31Plasticity index = 12
Classify each soil according to ASSHTO classification system. Description Percent finer than No.10 Sieve SOIL A SOIL B SOIL C 83 100 48 Percent finer than No.40 Sieve 48 92 28 Percent finer than No.200 Sieve 20 86 6. Liquid Limit Plasticity Index N/A Non plastic 20 70 5 32
3- Ninety-five percent of a soil passes through the No. 200 sieve and has a liquid limit of 60 and plasticity index of 40. Classify the soil by the AASHTO system.
Question 3 A sieve analysis was performed Sieve # 4 10 20 40 100 200 Pan Opening size (mm) 4.75 2 0.85 0.425 0.15 0.075 % Finer 80% For the soil passing # 40 sieve, Atterberg limits were measured as follows: Plastic Limit=29 and Liquid Limit = 36. (a) Fill the blanks in the table. (b) Plot the grain size distribution curve on the following semi-log graph. 100% 60% 40% 20% on a soil sample and the results are given below. Mass of soil retained (g) 0 43.4 80.6 124 186 124 62 0% 10.000 % Retained 1.000 E% Retained 0.100 % Finer 0.010 Grain Size (mm) (c) Extract the percentages of gravel, sand, and fine-grained soil (silt and clay). (d) Determine (1) the effective size (D10), (11) the Uniformity Coefficient (Cu), and (iii) the Coefficient of Curvature (Cc).
Classify the group symbol of the soil by USCS using the data given below: Percent passing the #4 sieve 68 Percent passing the #200 sieve 22 Liquid Limit 34 Plastic Limit 17 Group of answer choices SM SW SP SC
The following table shows the sieve analysis data on the left and hydrometer test data on the right for the minus No. 200 sieve material for a given soil. (a) Compute Cu and Cc. (b) Report the percentage gravel, sand, silt, and clay according to AASHTO. (c) Classify the soil according to AASHTO.
Problem D: For problems 14 to 17. Classify the following soils by the AASHTO classification System. Description A D Percent finerthan No. 4 sieve 100 | 92 100 94 Percent finerthan No. 10 sieve 100 85 80 80 Percent finerthan No. 40 sieve 96 71 78 51 Percent finerthan No. 200 sieve 72 56 59 15 Liquid Limit Plasticity Index 16) Soil A is ? 58 35 42 26 23 19 13 12 a) A-7-5(19) b) A-2-6 (0) c) A-7-6 (18) d) A-7-5 (18) 17) Soil Bis ? a) A-6(13) b) A-7-5(0) c) A-6 (7) d) A-6 (8) 18) Soil Cis ? a) A-7-6(5) 19) Soil D is ? a) A-2-6(2) b) A-7-6 (8) c) A-7-6 (7) d) A-7-6(6) b) A-3 (0) c) A-2-6 (0) d) A-2-6 (2)
IL Test sample weight= احتمان Sieve size Weight retained (g) Calculations: Sieve size in. (mm) 3/8" 9.5 mm No.4 4.75 mm No.8 2.36 mm No.16 1.18 mm No.30 0.6 mm No.50 0.3 mm No.100 0.15 mm Pan gm 3/8" No.4 No.8 No.16 No.50 No.100 0.15 mm 9.5 mm 4.75 mm 2.36 mm 1.18 mm mm 0.3 mm 0.0 од 1597 21419 від 50д 3589 174д Weight retained (g) Percent retained Beitel 15-11-2021 Fineness modulus отсивно о u 4/8²/00 = 5.3 15 діни з 2141-44871.3 61-448203 Божнизис 1.66 50 78.63 21.3 80.29 19.71 35 84421 23 92.22 7.78 174448518 98.02 1.98 чудд 4 /100 = Cumulative = No.30 Percent cumulative 0 53 94.7 766 23-4 Percent passing loo 222 Sieve deviation = 262 (5) ASTM Limit 100 95 100 80 100 50_85 25 60 10_30 2_10
For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5