The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 70% No.200 = 30% Liquid Limit= 33 Plastic Limit = 12

The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 70% No.200 = 30% Liquid Limit= 33 Plastic Limit = 12

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: L 40 PL 30 Determine its classification using USCS.

A: soil is classified as MI

Q: ) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

Q: Considering the following measurements, calculate the quantity passing and % retained applicable for…

Q: Question: For a given soil, the following are known: Percentage passing No. 4 sieve = 100…

Q: Percent U.S. Sieve No. passing 4 100 10 90 20 64 40 38 80 18 200 13

A: The two important sieve numbers for classifying the soil is #200(0.075mm) and #4(4.75mm). Former…

Q: Classify the soil using AASHTO Method.

A: AASHTO SOIL CLASSIFICATION:

Q: The results of the sieve analysis done on a soil are shown below Sieve No. Diameter Soil A 4 4.760…

Q: Q2. The following are the results of a sieve and hydrometer analysis. 1- Draw the grain -size…

A: Data given Find: Draw the grain -size distribution curve Determine the percentages of gravel,…

Q: The results of the sieve analysis of a non plastic soil is tabulated below. Classify the soil…

Q: he given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables…

A: iLook at % passing through No 200 sieve =24%<35%so granular material A-1 or A-2

Q: CLAIS ri piots vCIow IIIme Elastic SIIL UJAL Liquid limit 50 LL (oven dried) ÷ LL (not dried)…

A: Given, SIEVE NO. DIAMETER SOIL A 4 4.760 88 6 2.380 69 10 2.000 62 20 0.840 51 40 0.420…

Q: ysis on a soil sample yields the following data. Plot the particle size distribution curve and…

A: Given:- Sieve No. and Sieve Size To find:- Plot the particle size distribution curve and classify…

Q: Given the gathered data in sieve analysis of a soil sample; 1. Classify the soil using USDA 2.…

A: Given Sieve number, sieve size, percentage Passing through each seive sizes. Liquid limit LL,…

Q: A soil sample following results: Standard sieve No: TOATE RE 4 10 20 40 100 200 was analyzed Pan…

A: IntroductionA sieve is a tool or equipment used in soil engineering to measure the particle size of…

Q: 7. Following details regarding the particle size distribution and other index properties pertinent…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: The sieve analysis of 3 soils and the liquid and plastic limits of the fraction passing a no. 40…

Q: b. The following data was obtained from Sieve Analysis conducted at a Soil Lab. Using the data given…

Q: Classify the soil using AASHTO Method.

A: AASHTO CLASSIFICATION:

Q: he given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables…

A: iLook at the % passing through the sive 200=33<35% so granular soil

Q: A sample of soil has a plastic limit of (25) % and a liquid limit of (55) % Soil sample was tested…

A: Draw the figure.

Q: The given data shows a sieve analysis of the soil sample. Classify the soil according to AASHTO…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: following table of data from sieve analysis is given:

Q: For a given soil, the following are known: Percentage passing 75 mm sieve = 100 Percentage passing…

Q: For an inorganic soil the data of grain size analysis is as follows Sieve No. 4 10 20 40 80 200…

A: Liquid limit, Plastic limit, To find: The classification of soil using (a) AASHTO (b) USCS methods.

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: The classification of soil is based on the index properties of the soil such as grain size…

Q: Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand…

A: To Determine Soil classification according to AASHTO soil classification system. Given Sieve number.…

Q: Classify the soil according to Unified soil classification Sieve No. 4 10 20 40 60 80 100 200 Pan…

A: Mass retained in each sieve is given. From that, we can find that how much percentage retained and…

Q: .a. Determine coefficient of uniformity and coefficient of gradation b. Determine the soil…

A: To Determine: (a): The coefficient of uniformity and coefficient of gradation. (b): The soil…

Q: A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve…

A: Asked: To classify the soil using the given results of particle size analysis based on AASHTO…

Q: The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method.…

A: Given, Sieve analysis data

Q: Subject: soil mechanics Please help me. Urgent This is not an assignment question Thank you

A: size(mm) cumulative percentage finer %finer 2.00 100 100-74=26 0.075 74 74-60=14 0.05 60…

Q: The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760…

A: Given Seive size and Percentage Passing through each seive. To Determine Classification of soil…

Q: Question 2 The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil…

A: Given Sieve No, seive diameter, Percentage Passing of soil A through each seive sizes. To Determine…

Q: Question 1 The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil…

Q: a) Plot the grain size curve b) Calculate the coefficient of uniformity and the coefficient of…

A: For the given data, the particle size distribution curve is plotted below: a.

Q: General classification Granular materials (35% or less of total sample passing No. 200) A-2 A-1…

A: iLook at % passing through No 200 sieve =60%>35%so silt-clay

Concept explainers

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems:

Question

100%

The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System.

Sieve analysis % passing by weight is as follows:

No.4 = 100%

No. 40 = 70%

No.200 = 30%

Liquid Limit= 33

Plastic Limit = 12

Branch of science that deals with the stationary and moving bodies under the influence of forces.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The results of the sieve analysis of soil A is tabulated below. Classify the soil according to AASHTO classification system and unified soil classification systems (USCS). Diameter (mm) 4.75 2.0 0.85 0.425 0.150 0.075 LL PL % Passing 100 93 85 80 55 50 18 70
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 Determine its classification using USCS. ML MH None of the above CL CH
Please solve number 3. Thank youu
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
Following details regarding the particle size distribution and other index properties pertinent to the classification of soil. Choose three soils and classify each soil according to USCS and AASHTO classification systems. When necessary, assume Cu = 4.48 and Cc = 1.22.
2. The following data were recorded during particle size analysis tests in the laboratory. Plot the grading curve and determine the grading characteristics. Using the information, classify the soil according to BSCS. Soil 1 Fine-Mesh dry sieve analysis data: Sieve Size 425 (mm or um) Mass 1.18 600 300 212 150 63 retained 1.9 3.2 8.1 10.4 22.7 126.1 (g) Total sample = 212.0 g
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 89% No.200 = 65% Liquid Limit= 44 Plastic Limit = 23
SG is 2.66 and temperature is 18 degrees celcius
Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan U.S. Sieve N Mass of Soil Retained (g) Problem 5: Repeat problem 4 with the following data. 4 6 10 20 40 60 100 200 Pan 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 Mass of Soil Retained (g) 0 0 0 9.1 249.4 179.8 22.7 15.5 23.5
2.8 2.7 The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer Analysis Sieve 40 80 170 200 0.04 mm 0.02 mm 0.01 mm 0.005 mm 0.0015 mm Hydrometer Sieve number/ grain size Percent finer than a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. Repeat Problem 2.7 with the following data: 20 30 40 60 80 200 0.05 mm 0.03 mm 0.015 mm 0.006 mm 0.004 mm 0.0015 mm 100 96 85 80 59 39 26 15 8 Cengage Learning 2014 Percent finer than 100 96 90 76 65 34 27 19 11 7 6 5 Ⓒ Cengage Learning 2014
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 88 6 2.380 69 10 2.000 62 20 0.840 51 40 0.420 39 60 0.250 31 100 0.149 18 200 0.074 14 LL 60 PL 20 Determine its classification using USCS. SC SM ML None of the above. CL