Problem 2.The sieve analysis of ten soils and the liquid and plastic limits of the fraction pass-ing through the No. 40 sieve are given below. Classify the soils using the AASHTOclassification system and give the group indexes.SollNo.567699AWN.4810No. 1098100100859248879010092Sleve analysis(percent finer)No. 4080928855752862767874No. 200508065456263034832Liquidlimit3856372843323744Plasticlimit2923222028NP2425NP35

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The sieve analysis of ten soils and the liquid and plastic limits of the fraction pass- ing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. Soll No. 1 2 3 5 6 7 8 9 10 No. 10 98 100 100 85 92 48 87 90 100 92 Sleve analysis (percent finer) No. 40 80 92 88 55 75 28 62 76 78 74 No. 200 50 సకరంనిఉ 88 80 65 45 62 30 34 8 32 Liquid limit £153168588 37 28 43 32 37 44 Plastic limit 29 23 22 20 28 NP 24 25 NP 35

The sieve analysis of ten soils and the liquid and plastic limits of the fraction pass- ing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. Soll No. 1 2 3 5 6 7 8 9 10 No. 10 98 100 100 85 92 48 87 90 100 92 Sleve analysis (percent finer) No. 40 80 92 88 55 75 28 62 76 78 74 No. 200 50 సకరంనిఉ 88 80 65 45 62 30 34 8 32 Liquid limit £153168588 37 28 43 32 37 44 Plastic limit 29 23 22 20 28 NP 24 25 NP 35

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter5: Classification Of Soil

Section: Chapter Questions

Problem 5.10P

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Question 3 The sieve analysis of soil and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 48 % Passing No. 40: 28 % Passing No. 200: 6 LL = - %3D PL = NP Group classification: Blank 1 Group index: Blank 2
The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-ML
Question 5 The sieve analysis of soil and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 98 % Passing No. 40: 80 % Passing No. 200: 50 LL = 38 %3D PL = 29 Group classification: Blank 1 Group index: Blank 2
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. Sieve Analysis Sieve Diameter, Percent Passing Number mm. A В C 4 4.76 2.38 90 100 100 8 84 90 100 10 2 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 63 LL 42 46 47 PL 23 29 24 What is the classification of Soil A? What is the classification of Soil B? What is the classification of Soil C? EDI
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Given the following Sieve Analysis and Atterberg limits results. Answer the following questions: 1- What is the effective diameter of this soil? 2- Calculate the uniformity coefficient and coefficient of gradation 3- Determine the percentage of Gravel, Sand, Fine soils according to USCS. 4- Classify the soil using AASHTO (with GI) & USCS (with group name). Diameter Sieve # % Passing 100 (тm) 90 4 4.75 96 80 3.35 90 70 10 78.8 60 20 0.85 56.8 50 40 0.425 37.8 40 60 0.25 23.6 30 100 0.15 13 20 200 0.075 4.6 10 Рan LL 10 10 0.1 0.01 Diameter PL 5 Percent Passing (%) 2.
Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil classification system. Give the group symbols and the group names. Table 1. Sample 1 Grain Size Results (ASTM D422). Table 2. Atterberg Limits Results (ASTM D4318). Sleve No. Dia. (mm) % Passing Sample PL LL % in 12.7 100 G0 40 14 4.75 97 #10 2 94 #20 0.85 84 # 40 0.425 57 #60 0.25 32 140 0.106 15 #200 0.075 100 90 Atterberg Limit Results: LL = 60%, PL = 40% E 80 * 70- 60 - 50 40 30- a 20 10 1 30 a40 100 0.1200 10 80 0.01 Particle Diameter (mm) Answer ALL Questions Time: 2 Hours 70 CH or OH 60 A-line PI = 0.73(LL - 20) Or 50 40 30 CL MH OL 20 or CL-ML OH ML 10 - or OL 10 16 20 30 40 50 60 70 80 90 100 Liquid limit Figure 5.3 Plasticity chart Percent (%) Finer by Weight Plasticity index U-line PI = 0.(LL - 8) O Cengage Learning 2014
Classify the given soils using the Unified Soil Classification System (USCS). Give the group symbols and group names. (Show the path of the classification.) Sieve Analysis (percent finer) Soil No. No. 4 No. 200 LL PL Comments A 94 3 NP Cy = 4.48 and C = 1.22 - В 100 77 63 25 B.
SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
% Finer • Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure 100 90 80 70 60 50 40 30 Clay 20 10 0 0.001 + Silt 0.01 Soil A Sand Soil B 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A LL 26 (oven-dried; assume same for not dried) B Nonplastic 1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam? PL 18
The sieve analysis of ten soils and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 92 % Passing No. 40: 75 % Passing No. 200: 62 LL = 43 PL = 28 Group classification: Blank 1 Group index: Blank 2 Blank 1 Add your answer Blank 2 Add your answer
A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58. The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by AASHTO system.Justify your answer. provide fbd a.A-6 (5) b.A-5 (6) c.A-4 (5) d.A-7-6 (20)