1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550and a standard deviation of 170. A batch of wire is made by a new process, and a random sampleconsisting of 25 measurements gives an average strength of 1316. Assume that the standarddeviation does not change. Is there evidence at the 1% level of significance that the new processgives a larger mean strength than the old? To answer this question, the null hypothesis could bestated asA. μ= 1550 psiB. μ> 1550 psiC.µ + 1550 psiD. μ< 1550 psi

The Hypothesis of a test is an assertion (or) statement about the population parameter. The Example…

Answered: 1. The strength of steel wire made by…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that for a random sample of 250 firms that revalued their fixed assets, the mean ratio of debt to tangible assets was 0.629, and the sample standard deviation was 0.177. For an independent random sample of 450 firms that did not revalue their fixed assets, the mean ratio of debt to tangible assets was 0.599, and the sample standard deviation was 0.163. Assuming that the population distributions are normal with equal variances, find a 95% confidence interval for the difference between the two population means. E Click the icon to view a table of upper critical values of Student's t distribution. A 95% confidence interval for the difference between the two population means is (Round to four decimal places as needed.)
The ages of a group of 139 randomly selected adult females have a standard deviation of 17.2 years. Assume that the ages of female statistics students have less variation than ages of females in the general population, so let o = 17.2 years for the sample size calculation. How many female statistics student ages must be obtained in order to estimate the mean age of all female statistics students? Assume that we want 98% confidence that the sample mean is within one-half year of the population mean, The required sample size is (Type a whole number.)
A very large company is interested in its employees' productivity. The company reports from its historical data that its employees spend a mean of 164 minutes per employee (on a typical day) dealing with email. To test this claim, an independent consultant chooses 26 employees at random and finds that those employees spend a sample mean of 172 minutes dealing with email, with a sample standard deviation of 21 minutes. Assume that the population of amounts of time employees spend dealing with email is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that u, the mean number of minutes employees spend dealing with email, is equal to 164. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. Ho: I H: OSO D=D (b) Perform at test and find the p-value. Here is some information to help you with your t test.
A chain of restaurants has historically had a mean wait time of 5 minutes for its customers. Recently, the restaurant added several very popular dishes back to their menu. Due to this, the manager suspects the wait time, μ, has increased. He takes a random sample of 35 customers. The mean wait time for the sample is 5.1 minutes. Assume the population standard deviation for the wait times is known to be 1.1 minutes. Can the manager conclude that the mean wait time is now greater than 5 minutes? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho: O H₁:0 μ X 0° OO 20ם ローロ OO × 5 (b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other information to help you with your test. 0.10 is the value that cuts off an area of 0.10 in the right tail. *-μ ⚫ The test statistic has a normal distribution and the value is given by z=- σ √n Standard Normal…
An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-temperature performance. A sample of 60 transistors of type A were tested and were found to have a mean lifetime of 1827 hours and a standard deviation of 174 hours. A sample of 180 transistors of type B were tested and were found to have a mean lifetime of 1658 hours and a standard deviation of 231 hours. Let ux represent the population mean for transistors of type A and µy represent the population mean for transistors of type B. Find a 95% confidence interval for the difference uy – µy . Round the answers to three decimal places. The 95% confidence interval is
4. Past experience indicates that the time required for high school seniors to complete a standardized examination is a normal random variable with a mean of 35 minutes. If a random sample of 20 high school seniors took an average of 33.1 minutes to complete the examination with a standard deviation of 4.3 minutes, test the hypothesis at 5% level of significance that µ = 35 minutes, against the alternative µ< 35 minutes.

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