A local manufacturer will qualify a new machine if the percentage of its serviced product does not exceed 2%. In a random sample of 250 product contains 6 defectives. Using test of hypothesis, determine if the new machine can be qualified using an a =0.05. Compute for the P-value. Identify the appropriate hypotheses test. O a. Test on Population Proportion O b. Test on Mean, Variance Unknown O c. Test on Variance and Standard Deviation O d. Test on Mean, Variance Known
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![A local manufacturer will qualify a new machine if the percentage of its serviced product does not exceed 2%. In a random
sample of 250 product contains 6 defectives. Using test of hypothesis, determine if the new machine can be qualified using
an a =0.05. Compute for the P-value.
%3D
Identify the appropriate hypotheses test.
a. Test on Population Proportion
b. Test on Mean, Variance Unknown
c. Test on Variance and Standard Deviation
d. Test on Mean, Variance Known](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3bff435-eb0f-43cb-ba6a-05dbaec5981d%2F42873f68-4fca-4e10-8605-e8df8e3808ef%2F9wf34et_processed.png&w=3840&q=75)
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- Write complete and legibly.Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 27 27 0.79037 lb 0.80399 lb 0.00449 lb 0.00756 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? O A. Ho: H1 = H2 OB. Ho: H1#H2 Hq: HyUse the data and table below to test the indicated claim about the means of two populations. Assume that the two samples are independent simple randor samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…Got stuck, and wasn’t sure what to do.A sample mean is 94, sample size is 27, and population standard deviation is 14 are given. Ho: p=89, Hl: μ#89 and a significance level is 0.10. Use the P-value approach to test the hypothesis. O a z=186; P-value = 0.0314; reject null hypothesis O b. z 186, P-value = 0.0628; reject null hypothesis O c. z=0.36; P-value = 0.7188, do not reject null hypothesis Od. z=0.36, P-value = 0.3594; do not reject null hypothesis0. A high school principal claims that the variance in the GPA of students in the graduating class is Tess than 0.39. You test this claim by sampling 31 seniors and find their GPA have a variance or 0.21. Ho:o? Ha:o2 < 0.39 (Claim) = 0.39 Is there enough evidence to reject Ho and support the principal's claim at a 0.10 level of significance? ohs A. No, the test statistic x? B. No, the test statistic x2 = 16.154 is not in the rejection region with critical value 40.256 C. Yes, the test statistic x? D. No, the test statistic x2 = 21.434 is not in the rejection region with critical value 20.599 E. Yes, the test statistic x? = 16.154 is in the rejection region with critical value 20.599 = 20.599 is not in the rejection region with critical value 21.434 %3D 20.599 is in the rejection region with critical value 16.154 %DDo men talk less than women? The table shows results from a study of the words spoken in a day by men and women. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. At the 0.05 significance level, test the claim that the mean number of words spoken by men is less than the mean number of words spoken by women. Men Women n1 = 212 n2 = 218 xˉx̄1 = 15706.4 words xˉx̄2 = 15683.2 words s1 = 1595.44 words s2 = 1597.54 words What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer μ₁ μ σ₁² x̄₂ p x̄₁ s₁² p̂₁ μ(men) p₂ p₁ μ₂ ? ≤ > ≥ = ≠ < Select an answer μ₁ p₁ μ₂ x̄₂ σ₁² p̂₁ μ s₁² μ(women) p x̄₁ p₂ H1: Select an answer p̂₂ p s₂² σ₂² μ(men) μ μ₂ x̄₂ x̄₁ p₂ μ₁ p₁ ? < > = ≠ ≥ ≤ Select an answer μ₂ μ p₂ s₁² p₁ x̄₁ σ₁² p̂₁ p μ₁ x̄₂ μ(women) Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the…Suppose that we have disjoint normal populations A and B and we want to find the standard error estimate for estimating the difference in their means. We have an IRS from A of size 9 and an IRS from B of size 4. The POOLED variance is 18.72. What is the MARGIN OF ERROR for the 99 percent confidence interval for the difference of population means if we assume both populations have the same population variance? Group of answer choicesA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ OC. Ho: H₁ H¹/₂ H₁: H₁Please answer each item with the same format as the examples given. Thank you.A researcher wants to measure average cardiovascular health of university students and compare those scores to the average scores in the general population. Assuming that population variance is known, what statistical test is most appropriate for this study? independent-samples t-test single-sample t-test z-test for sample mean related-samples t-testData on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 26 26 0.79911 Ib 0.81326 Ib S 0.00445 Ib 0.00759 Ib ..... a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? A. Ho: Hy =H2 H1: 41> H2 B. Ho: H1 = H2 H1: 41Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. 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