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(a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. H: 0 (b) Perform a test and find the p-value. Here is some information to help you with your ! test. • The value of the test statistic is given by = The p-valun is two times the area under the curve to the right of the value of the test statistic. Student's t Distribution Step 1 Enter the nunber of degrees of freedom. Stup 2 Sadect one taled or two tailed. O One-taled O Two tailed Step a Enter the teut statiste. (Rnd to 3 decimal places.) Step 4 Shade the ara epresented by the pvalue Step S: Enter the pvalu (Round to a decimal places.) (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the company.

(a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. H: 0 (b) Perform a test and find the p-value. Here is some information to help you with your ! test. • The value of the test statistic is given by = The p-valun is two times the area under the curve to the right of the value of the test statistic. Student's t Distribution Step 1 Enter the nunber of degrees of freedom. Stup 2 Sadect one taled or two tailed. O One-taled O Two tailed Step a Enter the teut statiste. (Rnd to 3 decimal places.) Step 4 Shade the ara epresented by the pvalue Step S: Enter the pvalu (Round to a decimal places.) (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the company.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A very large company is interested in its employees' productivity. The company reports from its historical data that its employees spend a mean of 108 minutes per employee (on a typical day) dealing with email. To test this claim, an independent consultant chooses 14 employees at random and finds that those employees spend a sample mean of 117 minutes dealing with email, with a sample standard deviation of 21 minutes. Assume that the population of amounts of time employees spend dealing with email is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that H, the mean number of minutes employees spend dealing with email, is equal to 108. (a) State the null hypothesis H, and the alternative hypothesis A that you would use for the test. H: 0 H: 0 (b) Perform a I test and find the p-value. Here is some information to help you with yourI test. • The value of the test statistic is given by 1= • The p-value is two times the area under the curve to the right of the value of the test statistic. Student's t Distribution Step 1: Enter the mumber af degres af freedom. Step 2: Saledt ane-lailed or twa-tailed. O One-taled O Two-tailed Step 3: Enter the test statistic. (Round to 3 decimal places.) Step 4: Shade the area represented by the p-value Step 5: Enter the p-value. (Round to 3 decimal places.) (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the company. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is nat rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108 O since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal 108 8 會 回
Transcribed Image Text:A very large company is interested in its employees' productivity. The company reports from its historical data that its employees spend a mean of 108 minutes per employee (on a typical day) dealing with email. To test this claim, an independent consultant chooses 14 employees at random and finds that those employees spend a sample mean of 117 minutes dealing with email, with a sample standard deviation of 21 minutes. Assume that the population of amounts of time employees spend dealing with email is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that H, the mean number of minutes employees spend dealing with email, is equal to 108. (a) State the null hypothesis H, and the alternative hypothesis A that you would use for the test. H: 0 H: 0 (b) Perform a I test and find the p-value. Here is some information to help you with yourI test. • The value of the test statistic is given by 1= • The p-value is two times the area under the curve to the right of the value of the test statistic. Student's t Distribution Step 1: Enter the mumber af degres af freedom. Step 2: Saledt ane-lailed or twa-tailed. O One-taled O Two-tailed Step 3: Enter the test statistic. (Round to 3 decimal places.) Step 4: Shade the area represented by the p-value Step 5: Enter the p-value. (Round to 3 decimal places.) (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the company. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is nat rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108 O since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 108. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal 108 8 會 回
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