1. The iron core in the following magnetic device has a cross section of 4 cm by 5 cm. The coil has 500 turns and carries a current of 4 A. What is the flux density in the air gap b if μ00 (or the reluctance of iron core can be neglected). A. OT B. 0.25 T 10 cm 10 cm C. 0.5 T 1 cm) Gap a 0.5 cm: Gap b 10 cm D. 1.0 T
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- A magnetic circuit with a cross-sectional area of 20 cm? is to be operated at 50 Hz from a 120 V rms supply. The number of turns required to achieve a peak magnetic flux density of 1.8 T in the core isA ferromagnetic core is shown in Figure PI-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 1000. -10 cm- - 20 cm- 15 cm 400 turns 15 cm 15 cm Core depth 5 cmA toroidal core with a mean circumference of 100 cm and a cross-sectional area of 10 cm2 is wound with 500 turns of wire. What current would be required to generate a flux of 1 mWb in the core. Assume the core has a relative permeability of 800
- An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm², and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (ur = 800 for iron).It's urgent please solve asapA ferromagnetic core is shown in Figure Pl-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 800. 1-5. 10 cm- 5em 20 em 15 cm 15 cm 15 cm Coe depth - Scm SOLUTION There are three regions in this core. The top and bottom form one region, the left side forms a second region, and the right side forms a third region. If we assume that the mean path length of the flux is in the center of each leg of the core, and if we ignore spreading at the corners of the core, then the path lengths are I, = 2(27.5 cm) = 55 cm, I, = 30 cm, and /, = 30 cm. The reluctances of these regions are:
- thank u no rushA ferromagnetic core is shown below. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.003 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 1000. 1. - 10 cm--- - 20 cm - 15 cm 500 tums 15 cm 15 cm [1.21 A, 0.4 T, 1.2 T]Question 1 A ferromagnetic core with a relative permeability of 1500 is shown in Figure 2. The dimensions are as shown in the diagram, and the depth of the core is 7 cm. The air gaps on the left and right sides of the core are 0.070 and 0.020 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 400 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what is a) the flux in each of the left, center, and right legs of the core? b) the flux density in each air gap? 7 cm ст ст 30 cm 30 cm 7 cm 400 turns 0.05 cm 30 cm 0.07 cm 7 cm Core depth = 7 cm Figure 2
- A flux of 0.0016 Wb flows in a silicon sheet steel coil/core. The arrangement appears as shown below with the following dimensions: Ac = 0.0025 m? Core/gap area: Flux path length: le = 0.350 m lg = 0.0015 m N = 500 Air gap length: Number of turns: %3D A. What is the current, I, through the winding? B. What is the energy stored in the inductance? C. Assume that the current is given by i =9.75 sin (3147) A. What is the RMS voltage that would appear across the winding? D. Assume that the gap is removed from the arrangement with the flux path remaining at 0.350 m. For a flux of 0.0016 Wb, what is the inductance of the arrangement? E. What is the energy stored in the inductance with the gap removed?1.Consider the magnetic core below.All dimensions are shown on the figure. The core is made up of legs with 2 different cross-sectional areas.The depth of core is 10cm.The relative permeability of the core is 2000. The current in the magnetising coil is 1 A. The number of turns of the coil is 2000.Calculate: (i)the reluctances and draw the magnetic circuit (ii)the flux in the core (iii)Flux densities B and field intensities H in legs having different cross-sectional areas. (iv)Verify Ampere's Law. Depth: 10 cm I=1A 20cm 2000 Turns 65cm 15cm 15cm 50cm 15cm ndo un ofA certain magnetic circuit may be regarded as consisting of three parts, A, B and C in series, each one of which has a uniform cross-sectional area. Part A has a length of 300 mm and a cross- sectional area of 450 mm². Part B has a length of 120 mm and a cross-sectional area of 300 mm². Part C is an airgap 1.0 mm in length and of cross-sectional area 350 mm². The flux in the airgap is 0.35 mWb. Neglect magnetic leakage and fringing. The magnetic characteristic for parts A and B is given by: H (A/m) 400 560 800 1280 1800 B (T) 0.7 0.85 1.0 1.15 1.25 Calculate: i. The reluctance of each part, that is, of Part A, Part B, and Part C ii. The total reluctance of the magnetic circuit. iii. The total m.m.f.