Hello, expert. Can you simplify integration and reach the same final result while explaining the steps in detail, please? If there are multiple methods, please include them. 0.5 CN = 2 fo·³ e−(1+j4πn)t dt Final product--> 0.79 CN == 1+j4πn
Hello, expert. Can you simplify integration and reach the same final result while explaining the steps in detail, please? If there are multiple methods, please include them. 0.5 CN = 2 fo·³ e−(1+j4πn)t dt Final product--> 0.79 CN == 1+j4πn
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter16: Inductance In Ac Circuits
Section: Chapter Questions
Problem 1PP: Inductive Circuits Fill in all the missing values. Refer to the following formulas:...
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Transcribed Image Text:Hello, expert.
Can you simplify integration and reach the
same final result while explaining the steps in
detail, please? If there are multiple methods,
please include them.
0.5
CN = 2 fo·³ e−(1+j4πn)t dt
Final product--> 0.79
CN
==
1+j4πn
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