1 L1 L2 L3 1 2 3 3 M 6 HH 6 OL 9 9 2 M 5 HH 5 OL 8 8 Motor 1M4 4017 7 HH 10 14 3 Control transformer Stop 10 11 Start 1112 OL 12 1313 14 M *14 1112
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Assume that when the start button is pressed, the M starter does not energize. List 7 possible causes for this problem.
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- 5a. What is E2=? 5b. What is E3=? 5c. What is the potential difference of b relative to point a (V_ba)?b) Use the ALU 74181 in the figure below and the tables (one is enough; second maybe, need to check the new kit) to implement : A + B, A – B, A. B. (MSB) (LSB) 10 (MSB) F3 F2 F1 FO S3 Cn+4 16 s2 20 U14 15 S1 14 so A3 A2 A1 AO B3 B2 B1 B0 M Cn 24 23 22 21 28 27 T26 25 (LSB) (MSB) (LSB)(MSB) (LSB) And given that under M = 1 the circuit performs the following arithmetic and logic functions according to Table 11.1. Input selection S3 Output M-H S2 SI Cn=L. F3 F2 F1 FO A 1 -A В -B A&B AxB 1 A'B 1 Ax(-B) (-A)xB (-A)x(-B) 1 1 ACTIVE HIGH DATA M-L: ARITHMETIC OPERATIONS SELECTION M-H LOGIC s3 s2 s1 so Ino carry) (with carry) F-A PLUS 1 F- LA + B) PLUS 1 F- (A + BI PLUS 1 FUNCTIONS L L F-A F-A+B F-AB F-A H FA+B F-A+T F- MINUS 1 12s COMPL) F-A PLUS AB F- IA + BI PLUS AB L L L L F-0 F-ZERO F- AB F-A PLUS AB PLUS 1 F- (A + BI PLUS AB PLUS 1 L L L H L F-AOB F- AB L L F-A MINUS B MINUS 1 F-A MINUS B F- AB MINUS 1 F- A F-A PLUS AB PLUS1 F-A PLUS B PLUS 1 F- IA + B PLUS AB PLUS 1 L H L F-A PLUS AB…The circle is below(for D1-1N4148 is 1N4148 Diode). and also there have a table(. Note that the first 3 rows of measurement are obtained when the diode is reverse-biased) Vout_dc (V) VD (V) ID (μA) 0.51 -0.51 0.0 0.23 -0.20 0.0 0.10 -0.08 0.0 0.00 0.00 0.0 0.05 0.04 0.0 0.11 0.09 0.0 0.17 0.15 0.1 0.19 0.20 0.1 0.27 0.25 0.4 0.32 0.30 1.6 0.36 0.34 3.1 0.42 0.40 8.2 0.46 0.42 14.3 0.52 0.47 28.0 Questions: 1) plot the diode’s I-V characteristics on a linear scale (ID on the y-axis and VD on the x-axis) 2) [RP4] 3) [RP5]
- Quèstion 14 Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to L-Dc こosA 22V rmsら 50H2 RL VL-DC =20V 7. 0.01 F 0.02 F 0.0167 F None of the aboveFor the following circuit if the secondary voltage of the transformer is 20V rms, the PIV of the diodes are ZV +1H +1 C3 D₂ D₁ 000 000000000 + C₁ O 55 V O 61.61 V 33 V O56.56 V C₂ HE 2V + m D3 + Ca H 2Vquestion 1
- Please answer all subpart either dislike is ready Please Asap for likeI need answer ASAP If you solve it i will give you one big likeR1 = 1 kohms R2 = 1.4 kohms R3 = 6.8 kohms E = 8V D1: Si, rB = 2 ohms, rR = 215 kohms D2: Si, rB = 7 ohms, rR = 590 kohms Apply each of the diode approximations and determine: a) Current through D1 b) Voltage across D_2 c) Voltage across R_3
- Post-lab Questions If the diode D3 is damaged (as short) draw the output voltage waveform in this case. D1 D2 V1 F1 220Vrms n 50HZ T1 0° 220v:40v D3 D4 transformerPlease help. You are going to draw arrows that indicates the flow of the given 5 actions (a,b,c,d,e). You can draw arrows for all of them in the picture above, or make separate drawing for each letter. Please help me this is about CARRIER ACTION/FLOW OF CARRIERS in a semiconductor. It is also about Ferni Level.For the given circuit below, it operates on a peak-to-peak input voltage of 347.1 V, F = 60 Hz household supply through a step- down transformer with turns N1 = 10 and N2 = 1. Silicon diodes are used with a 1 Kiloohms load. Determine the output peak voltage (in volts). D1 D2 AC Input Vsec B (source) D3 D4 Load 24.30 15.96 12.40 O 18.75