I need to solve the question in two ways using the mov instruction, with detailed steps. Q2: Write an 8086 microprocessor program to exchange 14 words block of data from the first memory locations which is started with offset address of 2000H with the second memory locations which is started with offset address of 3000H. (12.5 marks)
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- Solve in 8086 microprocessorQ3/(A) False OR True 1- A0-0 and BHE-1 are used as low bank-select signal: 2-AX is 2234 H after executing the following instruction: AAS. If AX-2234H. 3-IP register holds the offset address of the next instruction to be executed. 4- The XLAT instruction in 8086 assembly language is used to perform arithmetic operations between two memory operands. 5- Bus interface unit is responsible formCan you give me a simple example of each mistake in the Emu8086 program? Registers should be of the same size. One way to reduce memory usage is to use AX or AL. Explain.
- New SolutionThe numbers from 0-9 and a no characters is the Basic 1 digit seven segment display * .can show False True In a (CA) method of 7 segments, the anodes of all the LED segments are * "connected to the logic "O False True Some times may run out of pins on your Arduino board and need to not extend it * .with shift registers True FalseWrite an 8086 microprocessor program to transfer 20 words block of data from the first memory locations which is started with offset address of 2000H to the second memory locations which is started with offset address of 3000H. SI 1. The Intel 8086 microprocessor can read/write 16 bit data from or to a. I/O device b. register © memory d. processor 2. Which unit in the 8086 microprocessor is responsible for pre-fetching instructions from memory? a. EU b. ALU c. BIU 3. The memory of 1M byte size could be divided into a. twenty-one b. thirty-four d. CU Kbyte segments. d. sixty-four c. thirty-three 4. Which of the following programming statements is NOT a valid comparison operator in Arduino? a!(not equal to) b. < (less than) c. and (logical AND) d.=(equal to) 5. How many A/D converter inputs pins does port-E in the PIC16F877A ? a. 3-Pins b. 6-Pins c. 4-Pins d. 8-Pins d. 4Kx14 bits 5. How much the size of the program memory space in the PIC16F877A microcontroller? a. 32Kx8 bits b. 16Kx16…
- "I need proof in the solution and a supported source with the solution." Write a 8086 microprocessor program to clear (100) consecutive memory locations starting at offset address 8000H. Assume the data segment value equal to 3000H write an 8086 microprocessor program to add two numbers each of four bytes. The first number (least significant byte) starts at memory offset 0500H and the second number (least significant byte) start at offset memory address 0600H Assume the data segment value equal to 0100H.Store the result at memory offset starts 0800H write a program to move a block of 100 numbers consecutive bytes of data strings at offset address 8000 H in memory to another block of memory locations starting at offset address A000 H. assume that both blocks are in the same data segment value 3000H (25 Marks) Write a program to multiply AX by (10.5) using shift instructionI need the solution, expert, to be correct with clarification. a. Write an 8086-microprocessor program to perform the result of the logical expression: BP (X₁ X2) + (X₁. X2), where X₁-01FFH, X2=AD58H: b. There are 30 data bytes are stored in memory location with offset address 3100H to 311EH. Write 8086 microprocessor program to transfer the block of data to new location with offset address 4201H to 421FQ2. (a) Figure 2 shows the pinout diagram (and their functional description) of the 2114 Static RAM memory IC. Using a neat sketch show how such IC may be interfaced with an M68000 microprocessor to realise a system that needs 1K x 16 bits of RAM. [Note: 2114 is a 4-bit memory IC. You will need multiple ICs to make up the 16-bit address bus of M68000 processor.] Ao-Ag Pin Names Address Inputs A6 1 A5 2 A4 AO 5 A16 A2 7 CS 8 GND 9 -23456782 18 Vcc WE Write Enable 17 A7 CS Chip Select 16 A8 1/0₁-1/04 Data Input/Output A3 4 15 A9 VCC Power (+5V) GND Ground 14 I/O 1 13 I/O 2 Truth Table 12 1/03 CS WE Comments 11 I/O 4 H X Chip Deselected L L Write 10 WE L H Read Figure 2 (b) Design an address decoder circuit to realise the following memory map (shown below in hexadecimal notation). The unused address range should generate an active low signal to be connected to the BERR* input of the M68000 microprocessor. Use the partial address decoding technique for your design. ROM1 00 0000 03 FFFF…
- Q2. (a) Figure 2 shows the pinout diagram (and their functional description) of the 2114 Static RAM memory IC. Using a neat sketch show how such IC may be interfaced with an M68000 microprocessor to realise a system that needs 1K x 16 bits of RAM. [Note: 2114 is a 4-bit memory IC. You will need multiple ICs to make up the 16-bit address bus of M68000 processor.] Ao-Ag Pin Names Address Inputs A6 1 A5 2 A4 3 A3 4 AO 5 A1 6 A2 7 CS 8 GND 9 +23456700 18 Vcc WE Write Enable 17 A7 CS Chip Select 16 A8 1/01-1/04 Data Input/Output 15 A9 Vcc Power (+5V) GND Ground 14 I/O 1 13 I/O 2 Truth Table 12 1/03 CS WE Comments 11 1/04 Н Chip Deselected L L Write 10 WE L H Read Figure 2 (b) Design an address decoder circuit to realise the following memory map (shown below in hexadecimal notation). The unused address range should generate an active low signal to be connected to the BERR* input of the M68000 microprocessor. Use the partial address decoding technique for your design. ROM1 00 0000 03 FFFF…Using the emu8086 program, I need to solve two points and explain the difference in the solutions between them. Question: Compute the physical address for the specified each of the following instructions. The register contents and as follows: (CS)=0A00H, (DS)=0B00Н, (DI)=00BOH, (BP)=00EAH and BX-2500H. 1) Destination operand of the instruction 2) Source operand of the instruction (IP)-0000H, (SS)=0D00H, LIST=00FOH, MOV LIST [BP+DI], AX MOV CL, [BX+200H] operand in variable are (SI)=OFFOH, AX=4020H,Answer only 4 and 5