Using the emu8086 program, I need to solve two points and explain the difference in the solutions between them. Question: Compute the physical address for the specified each of the following instructions. The register contents and as follows: (CS)=0A00H, (DS)=0B00Н, (DI)=00BOH, (BP)=00EAH and BX-2500H. 1) Destination operand of the instruction 2) Source operand of the instruction (IP)-0000H, (SS)=0D00H, LIST=00FOH, MOV LIST [BP+DI], AX MOV CL, [BX+200H] operand in variable are (SI)=OFFOH, AX=4020H,
Using the emu8086 program, I need to solve two points and explain the difference in the solutions between them. Question: Compute the physical address for the specified each of the following instructions. The register contents and as follows: (CS)=0A00H, (DS)=0B00Н, (DI)=00BOH, (BP)=00EAH and BX-2500H. 1) Destination operand of the instruction 2) Source operand of the instruction (IP)-0000H, (SS)=0D00H, LIST=00FOH, MOV LIST [BP+DI], AX MOV CL, [BX+200H] operand in variable are (SI)=OFFOH, AX=4020H,
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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![Using the emu8086 program, I need
to solve two points and explain the
difference in the solutions between
them.
Question: Compute the physical address for the specified
each of the following instructions. The register contents and
as follows: (CS)=0A00H, (DS)=0B00Н,
(DI)=00BOH, (BP)=00EAH and
BX-2500H.
1) Destination operand of the instruction
2) Source operand of the instruction
(IP)-0000H,
(SS)=0D00H,
LIST=00FOH,
MOV LIST [BP+DI], AX
MOV CL, [BX+200H]
operand in
variable are
(SI)=OFFOH,
AX=4020H,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b19ce3c-fe16-4709-842a-81c9b6a55d91%2F0bb8200d-3136-4ac9-bc06-65c4ab417772%2Fip88sd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using the emu8086 program, I need
to solve two points and explain the
difference in the solutions between
them.
Question: Compute the physical address for the specified
each of the following instructions. The register contents and
as follows: (CS)=0A00H, (DS)=0B00Н,
(DI)=00BOH, (BP)=00EAH and
BX-2500H.
1) Destination operand of the instruction
2) Source operand of the instruction
(IP)-0000H,
(SS)=0D00H,
LIST=00FOH,
MOV LIST [BP+DI], AX
MOV CL, [BX+200H]
operand in
variable are
(SI)=OFFOH,
AX=4020H,
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