7. Explain how the performance of induction motor can be predicted by circle diagram. Draw the circlediagram for a 3-phase, mesh-connected, 22.38 kW, 500-V, 4-pole, 50-Hz induction motor. The databelow give the measurements of line current, voltage and reading of two wattmeters connected tomeasure the input :No loadShort circuit500 V100 V8.3 A32 A2.85 kW- 0.75 kW- 1.35 kW2.35 kWFrom the diagram, find the line current, power factor, efficiency and the maximum output.[83 A, 0.9, 88%, 50.73 kW] (Electrical Machines-II, Vikram Univ. Ujjan 1977)

To solve this problem step by step, we'll use the circle diagram approach for a 3-phase induction…

Answered: 7. Explain how the performance of…

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter32: Three-phase Motors

Section: Chapter Questions

Problem 6RQ: Name three factors that determine the torque produced by an induction motor.

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A three –phase, 440V, 50 Hz, 6 – pole induction motor running at 950 rpm takes 50 kW at certain load. The friction and windage loss is 1.5 kW and the stator losses = 1.2 kW. Determine the output from the rotor. (a). 42.68 kW (b). 46.48 kW (c). 48.80 kW (d). 44. 86 kW
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2) A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a current of 385 A/phase. The total active power at the stator input terminals is 2344 kW, when operating at full load. The corresponding speed is accurately measured and found to be 709.2 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a) The power factor at full load b) The active power supplied to the rotor c) The total 1²-R losses in the rotor d) The load mechanical power (kW), torque (kN•m), and efficiency. S = Va· V3 - I S- Vy·3•I
2) A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a current of 385 A/phase. The total active power at the stator input terminals is 2344 kW, when operating at full load. The corresponding speed is accurately measured and found to be 709.2 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a) The power factor at full load b) The active power supplied to the rotor c) The total 12.R losses in the rotor d) The load mechanical power (kW), torque (kN-m), and efficiency. S = Va• V3- I S= Vy 3•I %3D
A three phase 6000 V alternator has the following O.C.C. at normal speed: Field current : 14 18 23 30 43 Terminal voltage: 4000 5000 6000 7000 8000 With armature short circuit and fall load current flowing the field current is 17 A And when the machine is suppling fall-load of 2000KVA at zero-power factor the field current is 42.5 A, and the terminal voltage is 6000 V. Determine the field current that required when the machine is supplying the fall-load current at 0.7 p.f. lagging.
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