obtain the admittan Paraineters for the two-part Network I 20022 ww 0.2v 5-2 25-22 لأم + ↓) 0.5V V₂ Find&Z12, Z21, h21, h21), (Y21 = 5, 411 = 3.5)
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- Saved Messages Shared media A premaccs = Pinned message fr12345@notavaaq.ga - 10 u unl@notavaad 77 videos 10 un SOLD CH A dc voltage E is applied across an RL circuit at t=0. at what time after, is the voltage across the resistor equal to that of the inductor. Photo Saved Me A 0.693TC You: Albur avaaa 0.673TC Channel p proof 0.707TC & LF BU 0.779TC Spotify & TG SC ySpotify E DWAR tli || mov I sebby Photo, vo A SEARCH FOR BUYERS SELLERS AND MAKERS bambeemo ts | 1M GC SH @65: LF BUYER CHE UNIQUE MARKET Photo 316 of 317 ava today at 11:56 AM Upload Docu. Media viewerThe manimum value of the altenating wotaye and curent are 400 U and 20A respectvely s a cieritoanected to a svita supply . The ristantanerus values of the veltnge and current are 283V and 10 A respectvely of fime t=0, beth icreasing pesitively. 4) Write dan the gapressom for vwltaga and curend at pmet. b). Defermaned tha prver omsumed in the cranit. Take the velye and cunent to be ginusrida). fie P= VI end\ P = YI (PF)Hi ! I need some one know about LTspice and help me to do this by LTSpice and give me the LT spice simulations The correct answer for question 1 is 2,67 run on Tlspice Make sure the simulations get the same answer
- 5. Suppose the following circuit is left open for a long time. 5000 22 24 V (a) What is the facial curren What is the carte II What is the ches What is the not the pos 80mF when we close thei 90s after we close the switch? dissipe the resistor 90s arter ene capacitor ons after we close the suit Close the switchi difference across the spacitor 008 after we close the switch across the resisto we close the swit 12 the potential (g) What is the energy stored in the capacitor 90s after we close the switch? (h) What is the energy dissipated by the resistor during the first 90s since the switch is closed?QUESTION 4 A 1kO resistor, a 5mH ideal inductor, and a 1nF capacitor are connected in parallel. Find the total impedance if a 12kHz voltage is applied across the circuit. O 1.26KNL79.9* O 1.890412.4° O 1.61kQ<-74.4° O 3620268.8°A circuit is designed with an AC source of max voltage 12 and frequency 60 Hz. The circuit has a resistance of 1050 Ohms, an inductance of 0.06 Henrys, and a capacitance of 0.009 coulombs per volt. - omega for source in rad/s? - omegaR for circuit? -XL? -XC? -phi in radians? -Z? -imax?
- л-pad attenuators are commonly used in radio frequency and microwave transmission lines and can be balanced or unbalanced designs. The unbalanced attenuator shown in figure 2 below is supplied by two DC sources, one at each end. You have been asked to calculate the current through R3 and R5 using the Superposition Theorem and the appropriate set of values from table 1 below. Show step by step working out. 5 R1 R2 50V 5 R5 R3 ㅋ Fig 2 7 R4 4 R6 30VI got 30419 how are they getting 345.9 hz?Ministry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25V
- electrnic circuits find vo1 and VoutSaved Messages Shared media A premaccs = pinned message fr1 2345@notavaaq.ga - 10 un eunl@notavaad 77 videos 10 un SOLD A series RL circuit connected across a dc source through a SPST switch, three (3) milliseconds after the switch is closed, the voltage across the inductor is 20V and drops to 5V after 20 ms. if R = 100 ohms, find the value of L. Assume that t=0, i =0 A 1.30H 1.22 H 1.59H D 1.25H & ELYSIAN MARKET kay @premsbyjisoo mag dm: AVAI 4 UNIQUE MARKET Photo 317 of 317 ava today at 11:56 AM Upload Docu. Media viewerSolve for Rc of Figure 42. 12 V Ic Rc RB VCE B=80 IB = 40 μA Reference: Boylestad, R. & Nashehky, L. (2013). Bectronic devices and circuit theory |11th ed.]. Upper Saddle River, New Jersey: Pearson Education Figure 42 1.5 k ohms 1.875 kohms 3.531 kohms 2.75 kohms Vc=6V

