1. Which of the following is not considered when finalizing the location of substationb) Nearness to load c) Cost of thea) Availabilityof Spaced) Cost of thesubstationcentresLand

To finalize the location of the substation various factors must be considered.

Answered: .Which of the following is not…

.Which of the following is not considered when finalizing the location of substation b) Nearness to load centres a) Availability of Space c) Cost of the d) Cost of the Land substation

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.47P: Consider the oneline diagram shown in Figure 3.40. The three-phase transformer bank is made up of...

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1. Which of the following is not considered when finalizing the location of substation
b) Nearness to load c) Cost of the
a) Availability
of Space
d) Cost of the
substation
centres
Land

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b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…
Consider the oneline diagram shown in Figure 3.40. The three-phase transformer bank is made up of three identical single-phase transformers, each specified by X1=0.24 (on the low-voltage side), negligible resistance and magnetizing current, and turns ratio =N2/N1=10. The transformer bank is delivering 100 MW at 0.8 p.f. lagging to a substation bus whose voltage is 230 kV. (a) Determine the primary current magnitude, primary voltage (line-to-line) magnitude, and the three-phase complex power supplied by the generator. Choose the line-to-neutral voltage at the bus, Va as the reference Account for the phase shift, and assume positive-sequence operation. (b) Find the phase shift between the primary and secondary voltages.
I need an expert. I previously sent a request, and the expert divided the time periods equally for both areas A and B. I did not understand how and why this was done. Please explain to me with a diagram why we do this. A generation station of 3 MW supply a two regions A & B .The line losses are neglected and the load variation of these regions is as follow: Region A (Time) 11 a.m From midnight to From 5 am to From 8 a.m to From 11 a.m to Load (kw) Region B (Time) 5 a.m No-load 8 a.m 1200 800 6 p.m No-load From From From midnight to 6 a.m to 3 p.m to 7 p.m to 6 a.m 3 p.m 7 p.m Load (kw) 400 900 No-load 9 p.m 1800 From From 6 p.m to midnight 600 From 9 p.m to midnight 200 1-Plot The daily load curve of the total system.
b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. V₁ = 120° p.u. V₂ = 120° p.u. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) j0.1X p.u. - 0 jX(1) = j0.2 p.u. 1JX(2) = 0.2 p.u. 2 jX1(0) = j0.25 p.u. jX2(1) j0.2 p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V₂ = 120° p.u. jXT(1) j0.1X p.u. jXT(2) j0.1X p.u. JX3(1) j0.1Y p.u. JX3(2)=j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0- = 3 = Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. 4 (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii)…
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1.a. To create usable voltages for 120-volt loads, _______ are usually installed.A. photovoltaic arraysB. transformersC. wind power turbinesD. generators1.b. Which grounding method is typically required of higher-voltage systems?A. Grounding through a high-impedance deviceB. Grounding through a low amount of resistanceC. Grounding through inductorsD. Grounding through surge arresters
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ignore X and Y values
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What is matching impedance? What does short circuit with matching impedance mean?