, The reactance data for the power system shown in Figure 10.30 in per unit on a common base is as follows: X2 0.10 0.10 0.05 Item G1 G2 0.10 0.10 0.05 0.25 0.25 0.25 T2 Line 1-2 0.30 0.25 0.25 0.25 0.30 0.50 3 T1 1 2 T2 4 G1 to -마머 G2 Obtain the Thévenin sequence impedances for the fault at bus 2 and compute the fault current in per unit for the following faults: 5.

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b) A bolted line-to-line fault at bus 2.

c) A bolted double line-to-ground fault at bus 2.

5.
, The reactance data for the power system shown in Figure 10.30 in per unit
on a common base is as follows:
Item
X²
G1
G2
0.10 0.10 0.05
0.10 0.10 0.05
0.25
0.25
0.25
T2
0.25 0.25 0.25
0.30
Line 1-2
0.30
0.50
3
T1
1
2
T2
4
G1
G2
Obtain the Thévenin sequence impedances for the fault at bus 2 and compute the fault
current in per unit for the following faults:
Transcribed Image Text:5. , The reactance data for the power system shown in Figure 10.30 in per unit on a common base is as follows: Item X² G1 G2 0.10 0.10 0.05 0.10 0.10 0.05 0.25 0.25 0.25 T2 0.25 0.25 0.25 0.30 Line 1-2 0.30 0.50 3 T1 1 2 T2 4 G1 G2 Obtain the Thévenin sequence impedances for the fault at bus 2 and compute the fault current in per unit for the following faults:
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