Ch4 physcis 2010Assignment Print View

pdf

School

South College *

*We aren’t endorsed by this school

Course

2010

Subject

Physics

Date

Jan 9, 2024

Type

pdf

Pages

34

Uploaded by ProfessorPanther3435

Report
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 1/34 Score: 25/25 Points 100 % A train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the train slows down with a constant acceleration of magnitude 1.40 m/s 2 . References Section Break Learning Objective: Analyze position vs. time and velocity vs. time graphs when the acceleration is constant Learning Objective: Determine the acceleration from a motion diagram Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 2/34 1. Award: 0.96 out of 0.96 points Which of the following is a graph of v x vs. t where the x -axis points up the incline? ✓
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 3/34 The graph will be a line with a slope of − 1.40 m/s 2 . References Multiple Choice Difficulty: Medium Learning Objective: Analyze position vs. time and velocity vs. time graphs when the acceleration is constant
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 4/34 2. Award: 0.96 out of 0.96 points Which of the following motion diagrams shows the train’s position at 2.00-s intervals? When t = 0, 2.00, 4.00, 6.00, 8.00 s, find x f by using Δ x = v i x Δ t + 1 2 a x Δ t ) 2 . References Multiple Choice Difficulty: Medium Learning Objective: Determine the acceleration from a motion diagram ✓ (
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 5/34 3. Award: 0.96 out of 0.96 points What is the speed of the train after 6.50 s on the incline? 12.90 m/s References Numeric Response Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration What is the speed of the train after 6.50 s on the incline? 12.9 ± 3% m/s Explanation: Since the train slows down, the acceleration is negative. Use Δ v x = v f x − v i x = a x Δ t.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 6/34 4. Award: 0.96 out of 0.96 points How far has the train traveled up the incline after 6.50 s? 110 m References Numeric Response Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration How far has the train traveled up the incline after 6.50 s? 113 ± 3% m Explanation: Use Δ x = v i x Δ t + 1 2 a x Δt ) 2 to find the distance the train traveled up the incline. (
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 7/34 A train is traveling south when the brakes are applied. It slows down with constant acceleration to a speed of 6.00 m/s in a time of 9.00 s. References Section Break Learning Objective: Analyze position vs. time and velocity vs. time graphs when the acceleration is constant Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 8/34 5. Award: 0.96 out of 0.96 points Which of the following is the correct graph of v x vs. t for a 12-s interval (starting 2 s before the brakes are applied and ending 1 s after the brakes are released) if the train is traveling south at 24.0 m/s when the brakes are applied and slows down with constant acceleration to a speed of 6.00 m/s in a time of 9.00 s? (Take north as the + x -direction.)
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6I… 9/34 Between 0 to 2 s the velocity is –24.0 m/s, and between 11 and 12 s the velocity is –6.00 m/s. Since the acceleration is constant between 2 and 11 s, draw a straight line between the two horizontal lines of constant speed. References Multiple Choice Difficulty: Medium Learning Objective: Analyze position vs. time and velocity vs. time graphs when the acceleration is constant ✓
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 10/34 6. Award: 0.96 out of 0.96 points What is the acceleration of the train during the 9.00-s interval if the train was traveling at 45.2 m/s? If the acceleration is toward north, enter a positive value. If the acceleration is toward south, enter a negative value. 4.36 m/s 2 References Numeric Response Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration What is the acceleration of the train during the 9.00-s interval if the train was traveling at 45.2 m/s? If the acceleration is toward north, enter a positive value. If the acceleration is toward south, enter a negative value. 4.36 ± 3% m/s 2 Explanation: Let north be the + x -direction. Use Δ v x = v f x − v i x = a x Δ t to find the acceleration of the train between 2 and 11 s. Before 2 s and after 11 s, the acceleration is zero.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 11/34 7. Award: 0.96 out of 0.96 points How far does the train travel during the 9.00 s if the train was traveling at 45.2 m/s? If the displacement is toward north, enter a positive value. If the displacement is toward south, enter a negative value. -223.34 m References Numeric Response Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration How far does the train travel during the 9.00 s if the train was traveling at 45.2 m/s? If the displacement is toward north, enter a positive value. If the displacement is toward south, enter a negative value. -230 ± 3% m Explanation: Use ∆ x = v i x ∆ t + 1 2 a x ∆ t ) 2 . (
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 12/34 In a cathode ray tube, electrons are accelerated from rest by a constant electric force of magnitude 6.40 × 10 − 17 N during the first 5.20 cm of the tube’s length; then they move at essentially constant velocity another 45.0 cm before hitting the screen. References Section Break Learning Objective: Recall the kinematic equations of motion Difficulty: Medium Learning Objective: Solve problems using Newton's laws of motion
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 13/34 8. Award: 0.96 out of 0.96 points Find the speed of the electrons when they hit the screen. 2704493. m/s References Numeric Response Learning Objective: Recall the kinematic equations of motion Difficulty: Medium Learning Objective: Solve problems using Newton's laws of motion Find the speed of the electrons when they hit the screen. 2.70E6 ± 3% m/s Explanation: Use kinematic equation and Newton’s second law.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 14/34 9. Award: 0.96 out of 0.96 points How long does it take them to travel the length of the tube? 204.85 ns References Numeric Response Learning Objective: Recall the kinematic equations of motion Difficulty: Medium Learning Objective: Solve problems using Newton's laws of motion How long does it take them to travel the length of the tube? 205 ± 3% ns Explanation: Use the relationship for displacement, initial and final velocities, constant acceleration, and time interval.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 15/34 10. Award: 0.96 out of 0.96 points An airplane starts from rest on the runway. The engines exert a constant force of 78.0 kN on the body of the plane (mass 9.20 × 10 4 kg) during takeoff. How far down the runway does the plane reach its takeoff speed of 64.1 m/s? 2424.9 m References Numeric Response Difficulty: Medium Learning Objective: Solve problems using Newton's laws of motion An airplane starts from rest on the runway. The engines exert a constant force of 78.0 kN on the body of the plane (mass 9.20 × 10 4 kg) during takeoff. How far down the runway does the plane reach its takeoff speed of 64.1 m/s? 2.42E3 ± 3% m Explanation: Use Newton’s second law and an equation of motion with constant acceleration.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 16/34 11. Award: 0.96 out of 0.96 points While an elevator of mass 783 kg moves downward, the tension in the supporting cable is a constant 7730 N. Between t = 0 and t = 4.00 s, the elevator’s displacement is 5.00 m downward. What is the elevator’s speed at t = 4.00 s? 1.105 m/s References Numeric Response Difficulty: Medium Learning Objective: Recall the kinematic equations of motion While an elevator of mass 783 kg moves downward, the tension in the supporting cable is a constant 7730 N. Between t = 0 and t = 4.00 s, the elevator’s displacement is 5.00 m downward. What is the elevator’s speed at t = 4.00 s? 1.11 ± 3% m/s Explanation: Find the net force on the elevator and determine the (constant) acceleration from it. Then use kinematic equations to find the final speed. We cannot assume the elevator starts from rest.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 17/34 12. Award: 0.96 out of 0.96 points Grant jumps 2.50 m straight up into the air to slam-dunk a basketball into the net. With what speed did he leave the floor? 7.00 m/s References Numeric Response Difficulty: Medium Learning Objective: Apply the kinematic equations of motion to objects in free fall Grant jumps 2.50 m straight up into the air to slam-dunk a basketball into the net. With what speed did he leave the floor? 7.00 ± 3% m/s Explanation: The final speed is zero. Use v f x 2 - v i x 2 = 2 a x ∆ x with the references made to the y -axis.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 18/34 A 55.0-kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. References Section Break Learning Objective: Apply the kinematic equations of motion to objects in free fall Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 19/34 13. Award: 0.96 out of 0.96 points How far does the ball fall in the first 1.60 s of its flight? 12.51 m References Numeric Response Learning Objective: Apply the kinematic equations of motion to objects in free fall Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration How far does the ball fall in the first 1.60 s of its flight? 12.5 ± 3% m Explanation: Use ∆ x = v i x ∆ t + 1 2 a x ( ∆ t ) 2 with the subscripts changed to y . Let the + y -direction be down.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 20/34 14. Award: 0.96 out of 0.96 points What is the speed of the ball after it has traveled 2.40 m downward? 6.72 m/s References Numeric Response Learning Objective: Apply the kinematic equations of motion to objects in free fall Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration What is the speed of the ball after it has traveled 2.40 m downward? 6.86 ± 3% m/s Explanation: Use v f x 2 - v i x 2 = 2 a x ∆ x with the subscripts changed to y . Let the + y -direction be down.
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 21/34 15. Award: 0.96 out of 0.96 points What is the speed of the ball 1.60 s after it is released? 15.70 m/s References Numeric Response Learning Objective: Apply the kinematic equations of motion to objects in free fall Difficulty: Medium Learning Objective: Apply the kinematic equations of motion with constant acceleration What is the speed of the ball 1.60 s after it is released? 15.7 ± 3% m/s Explanation: Use ∆ v x = v f x - v i x = a x ∆ t with the subscripts changed to y . Let the + y -direction be down.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 22/34 16. Award: 0.96 out of 0.96 points A baseball is thrown horizontally from a height of 9.60 m above the ground with a speed of 28.3 m/s. Where is the ball after 1.40 s have elapsed? The ball is above the ground at a horizontal distance of 39.62 m from the launch point. References Numeric Response Difficulty: Easy Learning Objective: Apply the kinematic equations of motion with constant acceleration A baseball is thrown horizontally from a height of 9.60 m above the ground with a speed of 28.3 m/s. Where is the ball after 1.40 s have elapsed? The ball is above the ground at a horizontal distance of 39.6 ± 3% m from the launch point. Explanation: Use the definition of average velocity to determine horizontal position of the baseball after 1.40 s have elapsed.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 23/34 When salmon head upstream to spawn, they may encounter a waterfall. If the water is not moving too fast, the salmon can swim right up through the falling water. Otherwise, the salmon jump out of the water to get to a place in the waterfall where the water is not falling so fast. When humans build dams that interrupt the usual route followed by the salmon, artificial fish ladders must be built. They consist of a series of small waterfalls with still pools of water in between them (see the photo). Suppose the salmon can swim at 8.50 m/s with respect to the water. References Section Break Difficulty: Medium Learning Objective: Identify the acceleration components for projectile motion
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 24/34 17. Award: 0.96 out of 0.96 points What is the maximum height of the waterfall up which the salmon can swim without having to jump? 3.77 m References Numeric Response Difficulty: Medium Learning Objective: Identify the acceleration components for projectile motion What is the maximum height of the waterfall up which the salmon can swim without having to jump? 3.69 ± 3% m Explanation: Find h = −Δ y by using v 2 f x - v 2 i x = 2 a x ∆ x .
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 25/34 18. Award: 0.96 out of 0.96 points If a waterfall is 3.93 m high, how high must the salmon jump to get to water through which it can swim? Assume that they jump straight up. 0.244 m References Numeric Response Difficulty: Medium Learning Objective: Identify the acceleration components for projectile motion If a waterfall is 3.93 m high, how high must the salmon jump to get to water through which it can swim? Assume that they jump straight up. 0.240 ± 3% m Explanation: The salmon can only swim through water that has fallen maximum height of a waterfall up or less.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 26/34 19. Award: 0.96 out of 0.96 points If a waterfall is 3.93 m high, what initial speed must a salmon have to jump the height to get to water through which it can swim? Assume that they jump straight up. 2.18 m/s References Numeric Response Difficulty: Medium Learning Objective: Identify the acceleration components for projectile motion If a waterfall is 3.93 m high, what initial speed must a salmon have to jump the height to get to water through which it can swim? Assume that they jump straight up. 2.17 ± 3% m/s Explanation: Find v f x by using v 2 f x - v 2 i x = 2 a x ∆ x .
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 27/34 20. Award: 0.96 out of 0.96 points For a 1.00-m-high waterfall, how fast will the salmon be swimming with respect to the ground when it starts swimming up the waterfall? 4.073 m/s References Numeric Response Difficulty: Medium Learning Objective: Identify the acceleration components for projectile motion For a 1.00-m-high waterfall, how fast will the salmon be swimming with respect to the ground when it starts swimming up the waterfall? 4.073 ± 3% m/s Explanation: Consider the motion of the salmon (s) and water (w) relative to the ground (g). v sg y = v sw y + v wg y .
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 28/34 You are designing a high-speed elevator for a new skyscraper. The elevator will have a mass limit of 2400 kg (including passengers). For passenger comfort, you choose the maximum ascent speed to be 18.0 m/s, the maximum descent speed to be 10.0 m/s, and the maximum acceleration magnitude to be 4.60 m/s 2 . Ignore friction. References Section Break Difficulty: Medium Learning Objective: Determine an object's apparent weight
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 29/34 21. Award: 0.96 out of 0.96 points What is the maximum upward force that the supporting cables exert on the elevator car? 34.584 kN References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the maximum upward force that the supporting cables exert on the elevator car? 34.6 ± 3% kN Explanation: Apply Newton’s second law to the elevator car and separately to the passenger. For the maximum force, consider the car accelerating up.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 30/34 22. Award: 0.96 out of 0.96 points What is the minimum upward force that the supporting cables exert on the elevator car? 12.48 kN References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the minimum upward force that the supporting cables exert on the elevator car? 12.5 ± 3% kN Explanation: Apply Newton’s second law to the elevator car and separately to the passenger. For the minimum force, consider the car accelerating downward.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 31/34 23. Award: 0.96 out of 0.96 points What is the minimum time it will take the elevator to ascend from the lobby to the observation deck, a vertical displacement of 640 m? 39.565 s References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the minimum time it will take the elevator to ascend from the lobby to the observation deck, a vertical displacement of 640 m? 39.5 ± 3% s Explanation: Find the time by applying equations for motion with constant acceleration to the ascent, taking each apart into sections with constant acceleration.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 32/34 24. Award: 0.96 out of 0.96 points What is the maximum value of a 60.0-kg passenger’s apparent weight during the ascent? 864.0 N References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the maximum value of a 60.0-kg passenger’s apparent weight during the ascent? 864 ± 3% N Explanation: Apply Newton’s second law. Maximum apparent weight is the normal force on the passenger when accelerating upward.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 33/34 25. Award: 0.96 out of 0.96 points What is the minimum value of a 60.0-kg passenger’s apparent weight during the ascent? 312 N References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the minimum value of a 60.0-kg passenger’s apparent weight during the ascent? 312 ± 3% N Explanation: Apply Newton’s second law. For the minimum force, consider the car accelerating downward.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
9/22/23, 5:05 AM Assignment Print View https://ezto.mheducation.com/api/caa/activity/C15Print?jwt=eyJhbGciOiJSUzI1NiJ9.eyJlbnZpcm9ubWVudCI6InByb2QiLCJpc3MiOiJlenQiLCJwcmludFVSTCI6… 34/34 26. Award: 1 out of 1.00 point What is the minimum time it will take the elevator to descend to the lobby from the observation deck, a vertical displacement of 640 m? 65.923 s References Numeric Response Difficulty: Medium Learning Objective: Determine an object's apparent weight What is the minimum time it will take the elevator to descend to the lobby from the observation deck, a vertical displacement of 640 m? 66.2 ± 3% s Explanation: Find the time by applying equations for motion with constant acceleration to the descent, taking each apart into sections with constant acceleration.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help

Related Documents

EXAM 1.docx
A.Origins Lecture.docx
prelab activites_ lab 5 session 1.pdf
NSCI LAB Investigation 3 Appendix B .pdf
5AL Lab 6 Assignment Submission Template - W23.pdf
EXP 16 copy.docx
Lab 3 Momentum .pdf
Lab4_activity.pdf
Projectile Motion Lab.docx
Wave Effects lab.pdf
_Physics Fall Final Exam Review.pdf
IMG_4180.jpg
Recommended textbooks for you
Text book image
Horizons: Exploring the Universe (MindTap Course ...
Physics
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
The Solar System
Physics
ISBN:9781337672252
Author:The Solar System
Publisher:Cengage
Text book image
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
SEE MORE TEXTBOOKS
Recommended textbooks for you
Text book image
Horizons: Exploring the Universe (MindTap Course ...
Physics
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
The Solar System
Physics
ISBN:9781337672252
Author:The Solar System
Publisher:Cengage
Text book image
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
SEE MORE TEXTBOOKS