Learning Activity Statistics Exercises Template

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Dec 6, 2023

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Learning Activity: Statistics Exercises Briauna A. Dobbs School of Education, Liberty University
EDLC 606 L EARNING A CTIVITY : S TATISTICS E XERCISES S TUDENT T EMPLATE Type your answers directly in the document in the spaces provided. Please consider highlighting, starring*, or changing the font color of answers for ease of instructor grading. You MUST show your work to be eligible for partial credit . 1. (20 Pts, 1 pt each ). Calculate the mean, median, mode, standard deviation, and range for the following sets of measurements (fill out the table): a. 20, 18, 17, 17, 19 b. 15, 10, 7, 6, 4 c. 28, 28, 28, 28, 28 d. 10, 10, 7, 6, 4, 79 x i ¿ ¿ s = 1 n 1 ¿ DISTRIB MEAN MEDIAN MODE SD RANGE a. 20+18+17+17+1 9 = 91/5 = 18.2 18 17 6.8/4 = 1.7 = 1.3 20-17 = 3 b. 15+10+ 7+6+ 4 = 42/5 = 8.4 7 none 73.2/4 = 18.3 = 4.27 15-4 = 11 c. 28 28 28 0 0 d. 10+10+ 7+ 6+4+79 = 116/6 = 19.33 7+10 = 17/2 = 8.5 10 4299.33/5 = 859.87 = 29.32 79-4 = 75 2. (20 Pts, 5 pts each ) Answer the following questions. a. Why is the SD in (d) so large compared to the SD in (b)? Because the data in set D deviates more from the mean than the data in set B b. Why is the mean so much higher in (d) than in (b)? The maximum value in set D data is 79, which is larger than the maximum value of 15 in set B data c. Why is the median relatively unaffected? Page 1 of 7
EDLC 606 The median is not affected by outliers because it only looks at the middle value of the dataset. Once the dataset has been sorted, the median is the value in the middle, regardless of the size of the other values. d. Which measure of central tendency best represents the set of scores in (d)? Why? Median best measures the central tendency the set of scores in set (d) because the value of mean is influences by outliers in the dataset. 3. ( 4 pts ) Determine the semi-interquartile range for the following set of scores. 92 95 89 65 99 100 85 67 72 99 85 100 Lower half: Median = (72 + 85)/2 = 78.5 Upper half: Median = (99 + 99)/2 = 99 Semi-interquartile range = (Upper median - Lower median)/2 =( 99 - 78.5 )/2= 10.25 4. (24 pts, 2 pts each ) Fill in the blanks on the table with the appropriate raw scores, z - scores, T-scores, and approximate percentile ranks. You may refer to the distribution curve below. Note: the Mean = 50, SD = 5. Page 2 of 7
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EDLC 606 RAW z T Percentile 40 -2 30 2.3% 62.5 2.5 75 99.4% 42.5 -1.5 35 6.7% 55 1 60 84.13 5. (6 pts, 3 pts each) The following are the means and standard deviations of some well- known standardized tests, referred to as Test A, Test B, and Test C. All three yield normal distributions. Test Mean Standard Deviation Test A 300 75 Test B 250 4 Test C 40 12 a. ( 3 pts ) A score of 275 on Test A corresponds to what score on Test B? -0.33x4 = -1.3 = 250 - 1.3 = 248.7 ____ b. ( 3 pts ) A score of 400 on Test A corresponds to what score on Test C? 1.33 x 12 = 15.96+40 = sc __ 6. (12 pts, 2 pts each) The Graduate Record Exam (GRE) has a combined verbal and quantitative mean of 1000 and a standard deviation of 200. Scores range from 200 to 1600 and are approximately normally distributed. For each of the following problems, indicate the percentage or score called for by the problem and select the appropriate distribution curve (from below) that relates to the problem. Page 3 of 7
EDLC 606 a. ( 2 pts ) What percentage of the persons who take the test score below 600? 2.28% b. ( 2 pts ) Type the curve best representing your answer: E c. ( 2 pts ) What percentage of the persons who take the test score below 1200? 84.13% d. ( 2 pts ) Type the curve best representing your answer: C e. ( 2 pts ) Above what score do the top 2.27% of the test-takers score? 1400 f. ( 2 pts ) Type the curve best representing your answer: B 7. (14 pts, varied) Refer to the following data and scatterplots to respond to questions 7a-e. Individua l Years of School Body Mass Index A 21 18 B 18 20 C 17 33 D 17 29 E 14 31 F 11 32 G 22 19 H 23 21 I 16 33 J 22 36 K 17 30 L 15 28 M 17 20 N 12 28 O 14 33 P 13 29 Page 4 of 7 10 12 14 16 18 20 22 24 0 5 10 15 20 25 30 35 40 Figure A Years of School Body Mass Index
EDLC 606 10 12 14 16 18 20 22 24 0 5 10 15 20 25 30 35 40 Figure B Years of School Body Mass Index Figure A represents a scatterplot constructed from the data; Figure B represents a regression line drawn through the scatterplot that “fits” the data points reasonably well; Figure C represents an ellipse drawn around the data points. a. ( 2 pts .) What is the overall direction of the correlation? Negative Page 5 of 7
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EDLC 606 b. ( 2 pts .) Estimate the strength of the correlation coefficient: Moderate Strength Consider Figure D (below). 10 12 14 16 18 20 22 24 0 5 10 15 20 25 30 35 40 Figure D Years of School Body Mass Index c. ( 2 pts .) Using only the data points associated with the years of school above 16; what effect does this have on the direction and strength of the correlation coefficient? Looking at the data point associated with years above 16, it shows a weak negative trend of BMI to years in school. The points are all scattered after year 16 versus years before 16. d. ( 4 pts .) Explain why this is the case. Due to the points being scattered away from the trend line it shows a weak correlation between BMI and years in school. e. ( 4 pts .) Identify how likely it is that a causal relationship has been indicated. It is not likely that a causal relationship has been identified by the data points. As students age they may join more sports, but they may also care more about appearance and health versus school. Other factors such as activity level, genetics, and diet would need to be taken into account. Page 6 of 7