ECOR1043_ Circuits Lab 2 - Group 14 (1)

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Lab #2: Introduction to Circuit Simulation ECOR1043: Circuits 5.2 7.
15. 16. V R1 = 1.3750 V 18.
19. V R2 = 625 mV 20. Voltage drop across R1 V R1 + V R2 - V 1 = 0 V 1 = V R1 + V R2 2 V = V R1 + 625 mV V R1 = 1.3750 V V R1 = 1.3750 V
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22. 5.3 7. 9. I R1 = 754.56 μA I R2 = 339.97 μA I R3 = 414.59 μA
10. 5.4 1. Power calculated across R1 P R1 = I 2 R P R1 = (754.56μA) 2 (2.2kΩ) P R1 = 1.25 mW Power calculated across R2 P R2 = I 2 R P R2 = (339.97μA) 2 (1kΩ) P R2 = 0.116 mW Power calculated across R3 P R3 = I 2 R P R3 = (414.59μA) 2 (820Ω) P R3 = 0.141 mW P R1 = 1.25 mW P R2 = 0.116 mW P R3 = 0.141 mW
2. Power calculated using Method 1 0 = P V1 + P R1 + P R2 + P R3 -P V1 = P R1 + P R2 + P R3 -P V1 = 1.25 mW + 0.116 mW + 0.141 mW P V1 = -1.51 mW Power calculated using Method 2 P V1 = V I P V1 = (2 V)(754.56 μA) P V1 = -1.51 mW Method 1: P V1 = -1.51 mW Method 2: P V1 = -1.51 mW 5.5 1. a) b)
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R1 R2 R3 V1 V2 i 928.57 μA 142.86 μA 785.71 μA -928.57 μA 142.86 μA v 9.2857 V 0.7143 V 15.714 V -25.0 V 15.0 V P 0.862 mW 0.102 mW 12.3 mW -23.2 mW 2.14 mW Calculations: V R1 = I R V R1 = (928.57 μA) (10 kΩ) V R1 = 9.2857 V V R2 = I R V R2 = (142.86 μA) (5 kΩ) V R2 = 0.7143 V V R3 = I R V R3 = (785.71 μA) (20 kΩ) V R3 = 15.7142 V P R1 = I 2 R P R1 = (928.57 μA) 2 (10 kΩ) P R1 = 0.862 mW P R2 = I 2 R P R2 = (142.86 μA) 2 (5 kΩ) P R2 = 0.102 mW P R3 = I 2 R P R3 = (785.71 μA) 2 (20 kΩ) P R3 = 12.3 mW P V1 = V I P V1 = (25 V) (-928.57 μA) P V1 = -23.2 mW P V2 = V I P V2 = (15 V) (142.86 μA) P V2 = 2.14 mW Discussion Questions: 1. In your Pre-Lab, you used a voltage divider to calculate the voltage drops across R1 and R2 of the circuit in Fig. 2. You did the same in step 20 and 19 of section 5.2 using simulation. Compare these values and comment on the difference. The voltage values across R1 and R2 remain consistent in both circuits due to their shared resistance values, with identical 2V voltage sources. The pre-lab circuit mirrors the one utilized in section 5.2 of the lab. 2. For the circuit of Fig. 7 you measured values of currents (IR1, IR2 and IR3) using simulations. In the previous lab (Lab 1), you calculated the same currents using voltage measurements using DMM. List them side by side in a table and calculate the difference between the measured and simulated values. (Note: The circuit of Fig. 7 is exactly the same three resistor circuit that you analyzed in Lab 1 but here it has been redrawn differently.)
Lab 1 current Lab 2 current Difference 1.97A 0.00075456A 1.969 0.00088A 0.00033997A 5.4003 0.0011A 0.00041459 6.8541 3. Using the MultisimLive software, generate the netlist of the circuit in Fig. 8 (Note that this is the same circuit as Fig. 3 of Pre-Lab). Take a screenshot. Compare it with the netlist you made in step 3 of Pre-Lab and comment on similarities and differences between the two. For this part just use the online help and software documentation. Multisim Netlist Our netlist V_V1 N1 0 25 V_V2 N3 0 15 R_R1 N1 N2 10k R_R2 N2 N3 5k R_R3 N2 0 20k Both of the displayed Netlists share a common structure. They exhibit identical numbers and component orientations with respect to the nodes. Unlike the multisim netlist, which doesn't employ 'N' to denote nodes or 'k' for units, we can infer node representation based on the resemblance between the two netlists. In the multisim netlist, component details are explicitly presented in a header before their descriptions.
4. From the powers calculated for the elements in circuit of Fig. 8, prove that total power dissipated in the circuit is equal to the total power delivered to the circuit. Show your calculation steps. P(delivered) = 0.862mW + 0.102mW +12.3mW - 23.3mW +2.14mW = 7.89601mW P(dissipated) = -7.896mW P(delivered) = P(dissipated) P(delivered) + P(dissipated) = 0 -7.896mW + 7.89601mW = -1.005mW The decimal place can be attributed to a rounding error, or lack of digits
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