Act B2_STOC-GILabReport.Mina_S2023 (1)
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Chemistry
Date
Jan 9, 2024
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Last Name, First Name
Lab Instructor
10/07/23
9/22 & 9/29
2:30 pm
Date
Lab Day
Lab Start Time
Relationships in Chemical Reactions F2016
Lab Report STOC-GI
1. Create a scatter plot to examine the relationship between the independent and dependent variables, Mass of CuSO
4
and Mass of Precipitate. Paste a copy of the scatterplot that you created in Excel here.
0.0000
0.1000
0.2000
0.3000
0.4000
0.5000
0.6000
0.7000
0.0000
0.0500
0.1000
0.1500
0.2000
0.2500
0.3000
Mass of CuSO4
Mass of Precipitate
1a)
For the graph above, over what range of data values for Mass of CuSO
4
does a linear relationship exist with Mass of Precipitate?
Mass of CuSO
4 (Start of
range) grams
Mass of CuSO
4
(End of range)
grams
Range of Mass of CuSO
4
with
linear relationship:
0.0676
0.5083
1b)
Provide the value for the slope and the y-intercept of the trendline for the relationship between Mass of CuSO
4 and Mass of Precipitate using the data in Series 2.
Slope
Y-Intercept
Trendline Values
0.3771x
0.0597
Part II: Heating A Substance
2a)
For the set of variables given below, identify the independent variable and the dependent variable
for the experiment conducted in Part II
.
Type of
Variable
Mass of
MgCO
3
Temperature
of Flame
Mass of
Residue
Number of
Heat-Cool-
Weigh Cycles
Independent Variable
Dependent Variable
2b
) For the set of four variables given below, identify any controlled or ancillary variables
for the experiment conducted in Part I. Check all, if any, that apply.
Type of Variable
Mass of MgCO3
Temperature of
Flame
Mass of
Residue
Number of Heat-
Cool-Mass
Cycles
Controlled Variable
Ancillary Variable
Part III: Isolation and Analysis of Data Set
3. Create a scatter plot to examine the relationship between the independent and dependent variables. The scatterplot should be embedded on the Part II worksheet with the data. Insert Graph From Excel Here. 2
0.00
00
20.0
000
40.0
000
60.0
000
80.0
000
100.
0000
120.
0000
140.0000
160.0000
0.0000
0.0500
0.1000
0.1500
0.2000
0.2500
0.3000
0.3500
0.4000
Mass of MgCO3
Mass of Residue
3a
) Which of the statements could be used to describe the pattern in the graph? Check all that
apply.
Statement 1
Statement 2
Statement 3
Pattern in Graph of
Independent and
Dependent Variables
Part II
3b
) For the graph above, over what range of data values for the independent variable does a linear relationship exist with the dependent variable?
Start of range of Mass
Independent Variable (grams)
End of range of Mass
Independent Variable (grams)
Range of Mass of Independent
Variable with linear
relationship to dependent
variable
0.0390
0.5048
3c
) Provide the value for the slope and the y-intercept of the trendline for the relationship between the independent and dependent variable.
Slope
Y-Intercept
Trendline Values
0.4636x
0.0068
3
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4a) Do the data in Part I indicate a directly proportional relationship in theory? Yes
No
I Don’t
Know
Do the data in Part I indicate a directly proportional relationship in theory?
Explain your reasoning
I think the data in Part I does not indicate a directly proportional relationship because the y-intercept is not 0. 4b) Do the data in Part II indicate a directly proportional relationship in theory?
Yes
No
I Don’t
Know
Do the data in Part II indicate a directly proportional relationship in theory?
Explain your reasoning
I also do not think the data in part II indicate proportional relationship for the same reason. 4c)
Examine the graphs constructed for Part I and Part II data. Briefly describe any similarities and differences between the two graphs. Compare/Contrast
Description
How are the two graphs
similar?
Both show linear trend
How are the two graphs
different?
Part II data is more accurate compared to its trendline than part I, part II data has one extreme outlier, and part I data had this slight curve with the data distribution
4d)
Indicate the range of values, smallest to largest, for the independent variable
over which the graphs from Part I and II display a similar and/or a different relationship.
Compare/Contrast
Part I: Range of Independent Part II: Range of Independent 4
Variable (X-Axis)
Variable (X-Axis)
Regions of graphs from Part I and II that display a similar relationship between the variables
0.2000
0.3000
Regions of graphs from Part I and II that display a different relationship between the variables
0.3000
0.3000
5. The data in Part I are based upon the formation of a precipitate from a double replacement reaction between two ionic compounds dissolved in a solution. 5a)
Write a balanced chemical equation for this reaction. Na2CO3 + CuSO4 = Na2SO4 + CuCO3
5b)
Which product of the reaction is the solid precipitate? CuCO3
5c)
Based on the design of the experiment in Part I, why is there a linear relationship between Mass of CuSO
4
and Mass of Precipitate only over a range of values for Mass of CuSO
4
?
The more CuSO4 that is being used, the more there is precipitate that comes out of it.
5d)
What part of the experiment design in Part I explains why the pattern changed to a constant relationship between the variables at higher values for Mass of CuSO
4
? The amount of Na2CO3 that was incorporated. 5
5e)
Describe how the pattern in the graph for Part I would change if the mass of Na
2
CO
3
was held “constant” at 0.15 grams instead of 0.20 grams.
The constant relationship between variables would be much early on, on the graph.
The data in Part II are based upon the decomposition reaction of solid magnesium carbonate.
5f)
Write a balanced chemical equation for this reaction. MgCO3 = MgO + CO2
5g)
Is there a limiting reactant for the decomposition reaction in Part II? Yes, MgCO3
5h)
How does the pattern displayed in the graph for Part II support your answer?
The pattern of the data is pretty much constant and almost as accurate as the trendline which would mean there had have to be a limiting reactant to create the pattern it has.
6a)
Complete the table below using data that you collected in Part II.
Mass of MgCO
3
Before Heating
(+/-0.0001 g)
Moles MgCO
3
Before Heating
Mass of MgCO
3
Residue
(+/-0.0001 g)
Moles MgCO
3
Residue
Ratio Moles MgCO
3
to Moles MgCO
3
Residue
Sample Calculations
0.3233
3.834 x 10^-3
0.3010
3.570 x 10^-3
1.074
0.1751
2.077 x 10^-3
0.0780
9.250 x 10^-4
2.245
6b
) Compare your mole ratio to the slope of the line for class data in the graph prepared for question #3. Explain why the two values are the same or not the same. 6
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Neither of the two mole ratios are the same as the slope of the data from question #3 because this
is just what I got while the graph consists of multiple data from multiple students which is a big factor for the slope. 7.
Consider the data that you personally
collected for Part I.
7a
) Copy the graph for the class data for Part I prepared for question #1. On this graph, plot the points for the data that you collected. Number the points, P1, P2, P3, P4. Paste edited graph here.
7b
. For each point identify the limiting reactant as Sodium carbonate or Copper (II) sulfate. For each point, insert an X into the cell correctly identifies the limiting reactant for each row.
Limiting Reactant
Point
Copper (II) sulfate
Sodium Carbonate
P1
P2
P3
P4
Consider the following models of the solution that resulted when the solution of CuSO
4
and Na
2
CO
3
were combined to form the precipitate. Model A
Model C
Model B
Model D
8a)
For each data point, select the model which best illustrates the solution that would have formed when the precipitate was prepared. Select all that apply.
7
Data point
Model #A
Model #B
Model #C
Model #D
P1
x
P2
x
8b)
Explain your reasoning for the models you selected.
Data point
Reasoning
P1
It created a significant amount of CuCO3
P2
It created a significant amount of CuCO3
8
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tile. Do not combine terms.
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[0.229]
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☑
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8.85
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Station V: Heating Cu with Atmospheric O₂
Chemical equation:
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Net ionic equation:
General reaction type:
Station VI: Reacting CuSO4 Solution with Steel Wool (Fe)
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The thermodynamic driving force AG – A,Gª + RT lnQ of a reaction for a given
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✪ True
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tile. Do not combine terms.
Ka
=
= 1.8 × 10-5
[500.0]
[0.200]
RESET
[5.00]
[1.0 × 10-9]
[1.0 × 10-9]
[1.8 × 10-5]
[x + 5.00]
[x + 1.0 × 10] [x-1.0 x 10 x + 1.0 × 10-] [x-1.0 × 10-] [x+1.8 × 10] [x-1.8 × 10%]
[0]
[x-5.00]
< PREV
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2
3
Based on your ICE table (Part 1) and the equilibrium expression, Ka (Part 2), determine
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0
0.360
30
21
43
11
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43 x 105
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59
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RESET
[0]
(0.13]
[0.37]
(0.010]
[0.040]
[0.10]
[0.40]
[x]
[2x]
[0.13 + x)
[0.13-x]
[0.010+x]
[0.010-x]
[0.040 + x] [0.040 - x]
[0.10+x]
[0.10-x]
[0.40+x]
[0.40-x]
PREV
2
Based on your ICE table (Part 2) and the equilibrium expression for Ka (Part 3),
determine the pH of solution.
pH =
RESET
0
7.3 × 10*
5.86
18.74
1.4 × 10+
0.13
8.14
0.89
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Calculating the capacity of electron subshells
subshell
3s
5s
Explanation
4p
2
Some electron subshells
principal quantum
number n
0
0
0
Check
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angular momentum
quantum number /
▬▬
0
0
0
Q Search
FO
maximum number of
electrons
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The student added 1.20 g of 4-aminobenzoic acid and 12.0 mL of ethanol together in
the presence of sulfuric acid. The reaction mixture was heated to reflux for a period
of 45 minutes.
H₂N
OH
4-aminobenzoic acid
MM 137.14 g/m ol
A
+ CH3CH₂OH
ethanol
MM 46.10 g/mol
B
ethyl 4-aminobenzoate
ethanol
H+
4-aminobenzoic acid
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H₂N
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H₂N
OH
4-aminobenzoic acid
MM 137.14 g/m ol
2.44 g
1.21 g
3.24 g
1.45 g
+ CH3CH₂OH
ethanol
MM 46.10 g/mol
B
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H₂N
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1
Drag the tiles into the numerator or denominator to form the expression.
Ko
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[Nij*
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Temperature (Celsius)
Initial Rate (kPa/s)
1
10 ml 3% H2O2 = 5ml 0.5M KI
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0.0798
2
5ml 3% H2O2 = 5ml 0.5 M KI
23.0
0.0391
3
5ml 3% H2O2 + 10ml 0.5 M KI
23.0
0.0794
Run
Initial Rate (mol/L*s)
[H2O2] after mixing
[I-] after mixing
1
3.24 x 10^-5
0.147 M
0.0417 M
2
1.59 x 10^-5
0.0733 M
0.417 M
3
3.23 x 10^-5
0.0733 M
0.0833 M
Calculate the rate law for the reaction
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Which of the following diagrams correctly illustrates the reaction mixture after the reaction goes to
completion?
000
00
00
000
(A)
(C)
00
000
000 000
000
000
000
00
00
000
000 000
000
(D)
000 000
(B)
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F3
F4
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80
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G
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2
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10:05 PM Tue May 31
<
AA
Welcome to Student P.
KREACTIONS REACTIONS IN SOLUTION
▸
LABORATORY SIMULATION
INTRODUCTION
Lab Data
Displacement Reactions Involving Acids
Observations
Reaction
(Before mixing)
Na₂CO3(aq) + H₂SO4 (aq)
NaOH(aq) + H₂SO4 (aq)
NaCl(aq) + HC₂H3O2 (aq)
splacement Reactions Involving Metals
Reaction
Observations
(Before mixing)
a(s) + H₂SO4 (aq)
newconnect.mheducation.com
R Gradebook
R Gradebook
Observations
(After mixing)
Observations
(After mixing)
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+
Chemistry - Reactions...
SUBMIT
- X
Classify Reaction
(Select all that apply)
0 Items
0 Items
br
0 Items
Classify Reaction
(Select all that apply)
0 Items
ch
ur
D
ion
ord
in
= 3
n
es
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1
2
3
NEXT
Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb in
order to determine the unknown. Each reaction participant must be represented by one
tile. Do not combine terms.
Kb =
[0]
[0.50]
(x)
[x +4.20]
[x - 4.20]
[x+6.3 x 10
< PREV
1
[2x]
=
3.8 × 10-10
RESET
[4.20]
[6.3 x 10-5]
[1.6 × 10-19]
[3.8 × 10-19]
[x-6.3 x 10] [x+1.6 × 10-9] [x-1.6 x 10-19 [x+3.8 x 10-9] [x-3.8 x 10-19
2
3
Based on your ICE table (Part 1) and the equilibrium expression for Kb (Part 2),
determine the original concentration of C6H5NH3+.
[C6H5NH3+]
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0
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Review I Constants i Perlodic Table
As a food chemist for a major potato chip company, you are responsible for determining the salt content of new potato
chip products for the packaging label. The potato chips are seasoned with table salt, NaCl. You weigh out a handful
of the chips, boil them in water to extract the salt, and then filter the boiled chips to remove the soggy chip pieces. You
then analyze the chip filtrate for Cl- concentration using the Mohr method.First you prepare a solution of silver
nitrate, AGNO3, and titrate it against 0.500 g of KCl using the Mohr method. You find that it takes 64.5 mL of
AgNO3 titrant to reach the equivalence point of the reaction. You then use the same silver nitrate solution to analyze
the chip filtrate in a Mohr reaction, finding that the solution yields a rusty brown precipitate when 45.4 mL of titrant is
added.
Part A
If the sample of chips used to make the filtrate weighed 76.5 g , how much NaCl is present in one serving (105 g )
of chips?…
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How do I make the graphs find the equation and slope?
I am learning from my mistakes to prepare for the final
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MISSED THIS? Watch KCV 13.4; Read Section 13.4. You can click on
the Review link to access the section in your e Text.
Review | Constants | Periodic lable
100
Part A
90
A KCl solution containing 44 g of KCl per 100.0 g of water is cooled from 70 °C to 0 °C. What happens during cooling?
80 -
NaNO
70
O At 70 °C the solution is unsaturated, but by 0 °C the solution is saturated; therefore a precipitate will form.
60 -
NaSO4
O At 70 °C the solution is supersaturated, but by 0 °C the solution is unsaturated; therefore no precipitate will form.
50 -
KCI
At 70 °C the solution is supersaturated; therefore a precipitate will form upon cooling.
40 -
O At 70 °C the solution is unsaturated, and at 0 °C the solution is also unsaturated; therefore no precipitate will form.
NaCl
30-
Request Answer
KdO,
Submit
20 -
10 -
0-
Provide Feedback
10
20
30
40
50
60
70
80
90
100
Next >
Temperature (°C)
Solubility (g solute in 100 g H¿O)
CaCl
Pb(NO,)2
KNO3
KCrzO,
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- In any manufacturing process, reaction monitoring ensures that a chemical reaction proceeds as expected. Table 1 shows the monitoring data for the formation of chlorohexane, collected using a technique called gas chromatography. Note that the concentrations of the chlorohexane solutions are given in millimoles per litre (mmol l–1). The abbreviation mM (millimolar) is frequently used. Plot a graph of the data in Table 1. The graph should be drawn on graph paper or use fine grid if it’s drawn on Excel. Elapsed Time/Hours Concentration of Chlorohexane/mM 0 0 2 40 4 65 6 80 8 90 10 95 12 99arrow_forwardBased on your ICE table (Part 2) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ка = = 3.2 × 10-9 RESET [0] [0.110] [0.220] [0.101] [0.229] [0.106] ☑ (x)] [2x] [0.110+x] [0.110-x] [0.220 + x] [0.220-x] [0.101 + x] [0.101 - x] [0.229 +x] [0.229-x] [0.106 + x] [0.106 - x] < PREV 2 3 Based on your ICE table (Part 2) and the equilibrium expression for Ka (Part 3), determine the pH of solution. pH = RESET 0 20.3 2.03 8.85 5.15 1.41 × 10-* 7.09 × 10-€ 0.110 0.958 1.96arrow_forwardIdentify the reaction type for reactions #1, #2, and #3. Large Element Element #: %232: Hydrocarbon punodwo) B. CO2(g) (6)2) Element → CO, Large Element (6)o°H + +. # 3: B. punodwom Tap below to toggle through answer options and to identify the reaction type for each of the three reactions. The type of reaction for Reaction #1 The type of reaction for reaction for The type of Reaction #2 Reaction # 3 is Decomposition Combustion Tap here to select answer. +.arrow_forward
- Lab 6: Chemical Reactions Post-Lab Questions Station V: Heating Cu with Atmospheric O₂ Chemical equation: Complete ionic equation: Net ionic equation: General reaction type: Station VI: Reacting CuSO4 Solution with Steel Wool (Fe)arrow_forwardThe concentrations of three gaseous chemicals are measured over time (see figure, below). Choose two different significant points in time for this reaction and explain what is happening at the chosen times. Support claims with evidence from grade 12 chemisty concepts.arrow_forwardAnswer all of themarrow_forward
- in Progress The thermodynamic driving force AG – A,Gª + RT lnQ of a reaction for a given composition of the system (e.g. concentration of reactants and products) depends on the definition of standard states. ✪ True False Q Search M **** Yo LO 4 hparrow_forwardplz help with the last three (ksp, average ksp,solubility)arrow_forwardBased on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = = 1.8 × 10-5 [500.0] [0.200] RESET [5.00] [1.0 × 10-9] [1.0 × 10-9] [1.8 × 10-5] [x + 5.00] [x + 1.0 × 10] [x-1.0 x 10 x + 1.0 × 10-] [x-1.0 × 10-] [x+1.8 × 10] [x-1.8 × 10%] [0] [x-5.00] < PREV 1 2 3 Based on your ICE table (Part 1) and the equilibrium expression, Ka (Part 2), determine the original mass of solid CH3COONa added to create this buffer solution. MNACH3COO g 0 0.360 30 21 43 11 15 36 x 10' 59 x 105 43 x 105 RESET 59 50arrow_forward
- Based on your ICE table (Part 2) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = 2.9 × 10-8 RESET [0] (0.13] [0.37] (0.010] [0.040] [0.10] [0.40] [x] [2x] [0.13 + x) [0.13-x] [0.010+x] [0.010-x] [0.040 + x] [0.040 - x] [0.10+x] [0.10-x] [0.40+x] [0.40-x] PREV 2 Based on your ICE table (Part 2) and the equilibrium expression for Ka (Part 3), determine the pH of solution. pH = RESET 0 7.3 × 10* 5.86 18.74 1.4 × 10+ 0.13 8.14 0.89arrow_forwardWhat is the role of sodium and chloride ions in this experimentarrow_forwardLa unch Meeting -Zoom X 7th Grade Science Unit 4 - Edge X core.learn.edgenuity.com/Player/ come to Renais O Earlimart School Di. Illuminate Home C.. A classroom A to Z Index of Ani. 6 ERS Library and ER. C Clever | Log in 2 Miss Spears 2016-2. * Plants ar Jnit 4 English Yaneli Loren Identifying Reaction Types Identify the reaction type shown and describe the clues that were used to identify it. Fe2O3 + 2SIO2 - Fe,Si,07 VDone O Tutoring Help leam uty oom/Comeven/fameChan/vye Ov0 1037 m alt ctrlarrow_forward
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