CHM 101L M4 Fundamentals of Calorimetry Lab Report Complete

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The Fundamentals of Calorimetry Student Name David Arlotta Date 11/19/2023
1 Data Activity 1 Data Table 1 © 2016 Carolina Biological Supply Company *Note that the Average Heat Capacity (C) calculated above is used in Activities 2 and 3. Time (min)1 1 Trial 1 Temp. °C Trial 2 Temp. °C 1 46 47 2 45 47 3 45 46 4 45 46 5 44 46 6 44 46 7 43 45 8 42 44 9 41 42 10 40 41 Trial 1 Trial 2 Initial temperature of cold water, T c 27 27 Initial temperature of warm water, T h 79 78 Average temperature, T a 43.5 45 Temperature at time 0 from graph, T 0 46 47 Heat lost by water in J to calorimeter (Δq) Heat capacity (C) of calorimeter in J/°C Average Heat capacity (C) of calorimeter in J/°C
2 1. Create a spreadsheet and graph of the data from Data Table 1, plotting temperature vs. time, and use the Y intercept to find the temperature at time 0 when the two volumes of water are mixed. a. Insert graph below. b. Activities 2 and 3 Data Table 2 5g CaCl 2 10g CaCl 2 15g CaCl 2 5g NH 4 Cl 10g NH 4 Cl 15g NH 4 Cl Mass of water (g) 100 100 100 100 100 100 Mass of salt (g) 5.03 10.06 15.1 5 10.02 15.05 Moles of salt (g x mol/g) 0.045 0.089 0.14 0.045 0.090 0.14 Initial Temperature (°C) T i 30 27 31 30 29 31 Final Temperature (°C) T f 32 30 33 32 30 32 Change in Temperature (°C) ∆T = T f - T i 2 3 2 2 1 1 Heat absorbed by 836 1254 836 836 418 418 © 2016 Carolina Biological Supply Company
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3 the solution (J) q w = -[c w x m w x ∆T] Heat Capacity of the Calorimeter (J/°C) 37.38 37.38 37.38 37.38 37.38 37.38 Heat absorbed by the calorimeter (J) q c = -[C x ∆T] 74.76 112.14 74.76 74.76 37.38 37.38 Enthalpy of solution (J) ∆H = q w + q c 910.76 1366.14 910.76 910.76 455.38 455.38 Enthalpy of solution (kJ) *Note: 1 kJ = 1000 J 0.910 1.366 0.910 0.910 0.455 0.455 Enthalpy/mole of solution (kJ/mol) ∆H/moles of salt 20.22 15.34 6.5 20.22 5.05 3.25 2. Create a spreadsheet and graph for CaCl 2 and NH 4 Cl, using the data from Data Table 2. Plot mass on the X axis and change in temperature on the Y axis for both graphs. The slope will be the change in temperature per gram of salt dissolved. a. Insert graphs below. © 2016 Carolina Biological Supply Company
4 3. What sort of relationship exists between the temperature change and the mass of the solid? Explain why that relationship exists. The relationship between the temperature change and the mass of a solid is straightforward: if you have more of the solid (increased mass), the temperature change will be greater, assuming everything else stays the same. This happens because a larger amount of the solid requires more energy to experience the same temperature change. 4. How do the calculated molar heats of solution for calcium chloride compare to one another? How do the calculated molar heats of solution for ammonium chloride compare to one another? The molar heat of solution for calcium chloride indicates whether it absorbs or releases heat during dissolution, and the same applies to ammonium chloride, with a positive value suggesting absorption (endothermic) and a negative value indicating release of heat (exothermic). 5. The actual molar enthalpy of solution for calcium chloride is -81.3 kJ/mol, whereas the molar enthalpy of solution of ammonium chloride is 14.8 kJ/mol. Calculate the average molar enthalpy of solution for each chemical based on your data, and then calculate the percentage error for each. Percent error is (|Actual – Experimental|/Actual) * 100% The expression (−81.3−14.02−81.3)×100 evaluates to approximately 82.80%. Therefore, the percentage error for the enthalpy of solution of Calcium Chloride (CaCl2) is approximately 82.80%. © 2016 Carolina Biological Supply Company
5 The expression (−81.3−9.50−81.3)×100 evaluates to approximately 88.31%. Therefore, the percentage error for the enthalpy of solution of Ammonium Chloride (NH4Cl) is approximately 88.31%. Activity 4 6. Based on the data and graphs for calcium chloride and ammonium chloride, determine which compound to use and what quantity of each compound will be needed to make a chemical hot pack and cold pack. Both packs should be calculated based on using 100 g (100 mL) of water. The hot pack should reach 60 °C, and the cold pack should go down to 3.0 °C from a room temperature of 25 °C. Hot Pack: Compound needed to achieve 60 °C above room temperature: CaCl2 Cold Pack: Compound needed to achieve 3.0 °C: NH4Cl 7. What were some potential sources of error in this investigation? The biggest source of error in this particular investigation is heat loss or gain from the outside 8. Suggest some ways in which the calorimeter or lab protocol could be improved to have lower percentage of errors. Maybe find a way to seal the experiment so that air cant affect the results © 2016 Carolina Biological Supply Company
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