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An average human weighs about 650 N For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Force between two point charges. ▼ Part A If two such generic humans each carried 1.5 C coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650 N weight? Express your answer in kilometers. ΠΡΑΣΦ T= Submit Request Answer Constants km

IAH and IGH are not the answer.

Part B The seventh ionization energy of manganese. Express your answer as a chemical equation. Identify all of the phases in your answer. ΑΣφ OA chemical reaction does not occur for this question. Submit Request Answer < Return to Assignment Provide Feedback Ма Word B. amazon U田

In the Millikan oil-drop experiment , the tinyoil drops are observed through the viewing lens as rising,stationary, or falling, as shown here. (a) What causes theirrate of fall to vary from their rate in the absence of an electricfield? (b) Why do some drops move upward?The following exercises are divided into sections that deal with specific topics in the chapter. The exercises are grouped in pairs, with the answers given in the back of the book to the odd-numbered exercises, as indicated by the red exercise numbers. Those exercises whose numbers appear in bracketsare more challenging than the nonbracketed exercises.

4. In addition to finding the right answer can you explain what is Determinate error (I think the correct answer is the 3rd option here but not sure if right)

Why is 4d10 not the answer? That is not the third row

Hello, Can you help me with this correcting me this questions below. Here I leave the comments to correct: In 3b, you didn't convert the Ea's to J/mol (also, why "45" and "76"? I don't see where those numbers came from). Also, the 298 should be in the denominator. It should end up that it's roughly 10^30 times faster. In 3c, NO. Try a higher temperature with the same Ea you used in 3b. The k should go down at a higher temperature. In 3d, NO. Mention that H2 is a product, and that this is an example of product inhibition.

Can you show how to out this calculation in the calculator? Everytime I do it, I get a different answer.

Hw.62.

The heat of formation at 25°C of liquid acetone, CH,C(0)CH,(1) is -247.5 kJ/mol. Which of the following is the correct heat of formation reaction for CH,C(O)CH,() )?

The first image has the question, and the second has an answer I tried that got marked incorrect. I'd gotten it from here, so just an FYI that the correct answer isn't that.

*CO 11 of 16 (> Review Constants | Periodic Table Part A HN-HO-HƆ Spell out the full name of the compound. Submit Request Answer Part B H. N. Spell out the full name of the compound. P Pearson Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy Permissions | Contact Us / 12:14 AM xp ジ 10/29/2020 Delete LEGO Backspace 6.

Fill in the blanks. Since you cannot input superscripts and subscripts directly, please follow this format: e.g. H20 should be written as H>2O; Fe3+ should be written as Fe^3+; Cr,0,2- should be written as Cr>20>7^2- *> to denote subscript, ^to denote superscript *This is just implemented in our class, for canvas to recognize your answers. You must still understand that superscripts and subscripts are the proper way of writing chemical formulas Please take note of the numbers in the answer box. Formula of Formula of Chemical Formula Name of Compound Cation Anion of Compound K+ Cr20,2- Mg2+ CN Ca2+ PO43-

Ff.257.

Find f'(x). Do NOT simplify your answer. f(x) = 6 cos(tan(x))

I need help with my reasoning for my claim and evidence which I have already done. I need help coming up with a thorough reasoning from what I wrote and the article attached.

I'm very confused. I didnt knew that 3 subtopics could be answered, so I uploaded one subtopic at the time. After gerting teh answers back, I uploaded the entire question and got the answer for the first 3 subtopics ( I'll call this A). However, a few of the single questions previously uploaded were answered and they are different from A. I'll upload the entire document again and please answer subtopics c, . If possible please confirm the write answer!   Given the data: 1. Mass of test tube + MNO² = 21.5403g                       21.5403g 2. Mass of the test tube + MnO² + KClO³ + KCl             22.5518g 3. Constant mass of test tube + reaction product          22.3514g  a. Mass of O2 released:  Answers by an expert of bartleyby:  1) 0.078 moles 2) 0.2004g  b. Moles of O2 released: 1) 0.00243 moles 2) 0.0063 mol c. Moles of KClO3 required by the moles 1) 0.00163 moles d. Mass of KClO3 required:  1) 0.5116g g KClO3  d. Mass KClO3 & KCl mixture: 1) 1.0115g e. Percent composition of…

Each sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. -2 ?

Each sketch below shows three objects with an electric charge. In each case, decide whether there is a net force acting on the object outlined in green. If there is a net force, decide whether it pushes the green-ring object to the left or right. Then select the appropriate button under the sketch. For example, if there is a net force pushing the green-ring object in the first sketch to the left, select the left button under the first sketch. If there is no net force on the green-ring object in the second sketch, select the middle button under the second sketch. And so on. +2 +2 +2 X +2 +2