#2 SCH3U Lesson

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Lakehead University *

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SCH3U

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Chemistry

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Feb 20, 2024

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SCH3U: University Preparation Chemistry Lesson # 2
Lesson # 2 1. Which of the following bonds is the most polar? SbF 2. What type of intermolecular force is found between: a) F2 and Cl2   F2 + Cl2 dispersion forces (London forces) b) 2 water molecules   2 water Hydrogen Bonding 3. Which ONE of the following substances is LEAST ionic? SbCl4 – Least Ionic 4. Calculate the difference in electronegativity for the bonds that would form between the groups of atoms listed below.  State whether the bond would be ionic, polar covalent or non-polar covalent. a) N and Cl 3.16 - 3.04 = 0.12 (< 0.4 = non-polar covalent)                        b) B and Br 2.96 – 2.04 = 0.92 (0.4-2.0 polar covalent)                         c) B and F 3.98 - 2.04 = 1.94 ( > 1.67 = ionic)                      d) Al and O 3.44 - 1.61 = 1.83 (> 1.67 = ionic)                      e) N and F 3.98 – 3.04 = 0.94 (0.4-2.0 = polar covalent)                            f) C and H 2.55-2.20 = 0.35 (< 0.4 = non-polar covalent)                          g) Mg and I 2.66-1.31 = 1.35 (0.4-2.0 polar covalent)                         h) Li and S 2.58 - 0.98 = 1.6 (< 1.67 = polar covalent)                         i) C and F 3.98-2.55 = 1.43 (0.4-2.0 polar covalent)                             j) Na and N 3.04 - 0.93 = 2.11 ( > 1.67 = ionic)                        5. Explain why HBr is a polar molecule, but H2and Br2 are not. HBr is a polar molecule because a dipole can be formed, this is because bromine has greater electronegativity. Which means that electrons in this covalent bond will stay towards bromine. However H2 and Br2 are compounds with no polarity as dipoles cannot form. The elements in each compound are the same which makes it so they have the same attraction to electrons when bonded.
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