ASCP BOC EXAM Study Guide Questions Solved (26)
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ASCP BOC EXAM Study Guide Questions Solved
Correctly (Attained Score A+) 135 Questions
Routine screening of urine samples for glycosuria is performed primarily to
detect: -
correct answers
✅
glucose
DNA-based testing for the presence of MRSA uses PCR with primers specific
for which gene? -
correct answers
✅
mecA
The following data were calculated on a series of 30 determinations of
serum uric acid control: mean=5.8 mg/dL, 1 standard deviation=0.15 mg/dL.
If the confidence limits are set at +or-2 SD, which of the following represents
the allowable limits for the control? -
correct answers
✅
5.50-6.10 mg/dL
A fluid sample waas collected by throcentesis. A serum sample was collected
immediately afterward. The LD fluid to serum ratio was 0.9. there were
5,000 WBC/uL, with 75% PMNs Which of the following describes this fluid. -
correct answers
✅
Plural effusion exudate
What is the MCV if the hematocrit is 20%, the RBC is 2.4 x 10^6/uL and the
hemoglobin is 5 g/dL? -
correct answers
✅
83 pg
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100
20
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bound drug/free drug (%)
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0
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Scatchard Plot of Drug Binding
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a)What is affinity chromatography and what is it used for?
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+Protein
Mr
pl
А
12,000
28,000
42,000
66,000 (a;)
103,000 (a2)
111,000
3
8.4
C
7.2
9
E
5
F
4.2
Predict how the proteins listed above will behave in a variety of separation and
characterization procedures.
For each chromatographic technique (you may assume that the protein remains
“native," or non-denatured), list the order in which the proteins will elute (come of
the end of the column):
Size Exclusion Chromatography, pH 6.8
First
Last
Anion Exchange Chromatography, pH 9, using a salt gradient to elute
First
Last
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EQD₂ = nd*
α
Assume a/B
(d+(a/B))
(2+(a/B))
BED:= (nd)*(1+
α
=2 for late effects and a/B 10 for acute effects
1. Using the Equivalent Dose in 2 Gy Fractions equation, compare the following protocols. Which would have better
tumor control? Which would have worse late effects?
42 Gy delivered in 12 fractions; 30 Gy delivered in 5 fractions.
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Please just answer this question, I answered the others already
Calculate the standard error of regression (SER) for the Lineweaver–Burk slope and the Eadie–Hofstee slope to compare the precision of each.
Eadie–Hofstee SER: it is not 0.128, 0.028, 0.136, or 0.1362 or 0.013.
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Heparin is used as an anti-coagulant. A risk of heparin use is thrombocytopenia, or low platelet
count. This risk is minimized with the use of low molecular weight heparins (LMWH), therefore it is
desirable to separate LMWH from higher molecular weight heparins. The method of choice to do
this is molecular exclusion chromatography. Below is a chromatogram from a molecular exclusion
chromatographic run. Peaks ranging from A to J are clearly distinguishable. The heparin mixture
that was analyzed had anywhere from 6 to 30 repeat units of monomer (where the heparin with 30
repeat units would be roughly five times the size of the heparin with six repeat units).
a. Which letter most likely represents the peak with 6 repeat units given these heparin polymers
were separated with molecular exclusion chromatography?
b. Explain your reasoning describing the mechanism of retention in molecular exclusion
chromatography.
100
80
60
60
Relative Abundance
40
40
E
GH
20
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B
A
36 38 40 42 44 46 48 50
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For what purpose Biuret test is used?
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- Do not give handwriting solution.arrow_forwardPlease just answer this question, I answered the others already Calculate the standard error of regression (SER) for the Lineweaver–Burk slope and the Eadie–Hofstee slope to compare the precision of each. Eadie–Hofstee SER: it is not 0.128, 0.028, 0.136, or 0.1362 or 0.013.arrow_forwardHeparin is used as an anti-coagulant. A risk of heparin use is thrombocytopenia, or low platelet count. This risk is minimized with the use of low molecular weight heparins (LMWH), therefore it is desirable to separate LMWH from higher molecular weight heparins. The method of choice to do this is molecular exclusion chromatography. Below is a chromatogram from a molecular exclusion chromatographic run. Peaks ranging from A to J are clearly distinguishable. The heparin mixture that was analyzed had anywhere from 6 to 30 repeat units of monomer (where the heparin with 30 repeat units would be roughly five times the size of the heparin with six repeat units). a. Which letter most likely represents the peak with 6 repeat units given these heparin polymers were separated with molecular exclusion chromatography? b. Explain your reasoning describing the mechanism of retention in molecular exclusion chromatography. 100 80 60 60 Relative Abundance 40 40 E GH 20 20 B A 36 38 40 42 44 46 48 50 50…arrow_forward
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