Week 8 BIOL133 Instructions

Hi, I'm stuck on this review question for my upcoming exam, if someone could please explain the problem it would be a huge help! thank you!! "When a Manx cat, which is a breed that lacks a tail, is mated with a tailed cat, one half of the offspring have tails and one half have no tails. If two Manx cats are mated, 1/3 of the offspring have tails and 2/3 have no tails. Explain the inheritance pattern for both crosses, including the genotypes for each cross."

Pak Atan wants to know more! Since Pak Atan know about the testcross, this time he tries to determine the double trait of wool and eye of his beloved sheep, Topokki. It is a male sheep with white wool and brown eye. Help Pak Atan match Topokki with female sheep to confirm its genotype. Show your work to Pak Atan. (W = White wool ; w = Black wool) (B = Brown eyes; b= Blue eye) %3D Shinta Тоpokki Dolla Jajangmyeon 11-28 Copyright ©2019 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education.

Let us practice it again! Analyze the pedigree below to answer the questions that follow. Huntington's disease a disorder in which nerve cells waste away, or disintegrate, is passed down through families. certain parts of the brain Huntington's diseate llustration ereated in htps://pregenygenetion.com/ 1. What members of the family above are affected with the Huntington's disease? 2. Tnere are no carriers ior Huntungton's disease you either have it or you do not. Is Huntington's disease caused-by a dominant or recessive trait? 3. Identify the genotypes of the following individuals using the pedigree above. (homozygous dominant, homozygous recessive, heterozygous). I- 1 II -1: II -3: III - 4 : 4. How many children did individuals I-1 and I-2 have? 5. How many girls did II-1 and II-2 have? How many have Huntington's Disease? 6. How are individuals III-2 and II-4 related? I-2 and III-5?

My Courses D uizzes/4305259/take Question 2 O 0% x EBook - SRH - Go__ x X x Book Outline-SF X In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c). Heterozygotes may be single-coal colored (e.g., CWc) or multi-coat colored (CWCB). O 25% If a heterozygous black-coated rabbit and a homozygous white-coated rabbit mate, what is the likelihood that offspring rabbits will be spotted? O 50% O 75% Question 3 Quiz: M6 TYK - MX Q Search 1 pts Com L The next set of questions focus on the ABO blood typing system. What inheritance pattern(s) does the ABO blood type demonstrate? Select all that are correct. 0.5 pts Mail

Pak Atan wants to know more! Since Pak Atan know about the testcross, this time he tries to determine the double trait of wool and eye of his beloved sheep, Topokki. It is a male sheep with white wool and brown eye. Help Pak Atan match Topokki with female sheep to confirm its genotype. Show your work to Pak Atan. (W = White wool ; w = Black wool) (B = Brown eyes; b= Blue eye) Shinta Тоpokki Dolla Jajangmyeon 11-28

TOPIC : Genetics Example's for Question GENE = Hair Color ALLELE = Straight, Curly DOMINANCE = BB RECESSIVE = bb GENOTYPE = BB, Bb, bb PHENOTYPE = Blue, Black HOMOZYGOTE = BB (Blue eye), bb (Black eye) HETEROZYGOTE = Bb (Blue eye) MONOHYBRID = Aa DIHYBRID = AaBb TRIHYBRID = AaBbCc POLIHYBRID = AaBbCcDd MENDELLIAN GENETICS = Hair Color NON MENDELLIA = Blood Type QUESTIONS: Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!) 1. MONOHYBRID CROSS = ? DIHYBRID CROSS = ? 2. BACK CROSS = ? TEST CROSS = ?

PLEASE ANSWER 4 & 5   Below in Figure 1 is a pedigree for a family afflicted by a genetic disorder. In some populations, Cystic fibrosis has an incidence of 1 in 2500 newborns. The carrier frequency calculated from this is 1/25. Analyze the pedigree below assuming the disease is similar to cystic fibrosis in incidence and carrier frequency. However this disease may not have the same type of genetic transmission as cystic fibrosis. What type of genetic transmission is most consistent with the pedigree? Label all the individuals that you can determine, with hypothesized genotypes. Label the individuals that have unknown genotypes with possible genotypes. Assuming her father is known to NOT be a carrier, calculate the probability that IV1 is a carrier for disease. Use the Χ2 test to determine whether your proposed transmission fits this data.

PLEASE explain how to do this question step by tspe i am very confused! thank you! You have three independent mutant alleles in the Drosophila gene no legs (nlg): nlg1, nlg2, and nlg3. You assay the phenotype of Drosophila, which is an insect, that are heterozygous for the three allele (heterozygous for a wild-type and a mutant allele), and that are homozygous for the three alleles. Allele nlg1 nlg2 nlg3 heterozygous Wild-type Four pairs of legs Wild-type homozygous Stumpy legs Five pairs of legs No legs   nlg1 is a ___X___ allele, nlg2 is a ___Y___ allele, and nlg3 is a ___Z___ allele.     X Y Z A Gain of function Null Hypomorphic B Hypomorphic Gain of function Null C Null Gain of function Hypomorphic D Null Hypomorphic Gain of function E Hypomorphic Null Gain of function   Referencing the table above, select the correct answer:  1 : A  2 : B  3 : C  4 : D  5 : E Correct answer is B

E- Question 20/28 In chart 1, the offspring of the two pea plants are Aa. Use the diagrams below to answer the questions that follow. This is known as . Pea Plants A Homozygous Dominant Chart 1 Homozygous Recessive Punnett Square Heterozygous Dominant Heterozygous Recessive Aa Aa Aa Aa Chart 2 AaBb x AaBb AB Ab qe AaBb ав Key AB AABB AABB AABB AA-Green Ab AABB AAbb AaBb Aabb BB- Smooth aa - Yellow aB AABB AaBb aaBB aaBb ab AaBb y6noy - 99 Aabb aaBb aabb

The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?

W O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.

Agree or disagree with each of the five statements below and describe why the statement is or is not true. Number your answers so I know which statement you're talking about. Berdon syndrome is a recessive disorder in humans that is typically fatal shortly after birth. This disease will eventually be eliminated from the population because people with the disease die before they reproduce. Jalili syndrome is an extremely rare recessive disorder. A person with one normal allele and one disease allele will not suffer from this disorder. The ability to taste the chemical phenylthiocarbamide (PTC) is a dominant trait in humans. Therefore, the majority of the population must have this trait. An individual's phenotype is determined entirely by their DNA. All mutations are harmful.

Stil confused on part 3. 3. Use the chi-squared test to determine if these data fit the Hardy-Weinberg equilibrium model. The degrees of freedom for this test should be 1. Why is this appropriate? Is the hypothesis accpeted because the chi square value calulated is less than the critical value from the chart? And why do we use df=1? Is it because we're only looking at 2 alleles?

Questions: 1. Length of fur is also genetically determined. The allele L produces long fur and its corresponding allele, I, produces short fur. Long fur is dominant to short. a) You mate 2 hamsters. Both heterozygous for brown long fur. Would you expect any of the offspring to have black short fur? If so, what proportion would have black short fur? b) What proportion would have black long fur?

/d/1n5NtidRwTwUzcDkDPi5Z9P_SHPZ91A-XH-pfftLbhNc/edit (1) O pols Add-ons Help Last edit was seconds ago BIUA ミ: 12 + ext Calibri I|1 6 I 2 Section 5: Trihybrid cross and Laws of probability For a trihybrid cross, in which inheritance of alleles for three genes is tracked, drawing a Punnett square that combines all three genes may not be practical. Instead the laws of probability may be used. The product law of probabilities says that when alleles for separate genes segregate independently, we can figure out the probability of a particular combined genotype by multiplying the probability of the alleles for each gene. 13. We cross a homozygous tall pea plant with yellow, round seeds to a homozygous dwarf pea plant with green, wrinkled seeds. All the F1 offspring are all tall plants with yellow, round seeds. a. What are the expected F2 ratios (use fractions) of tall and dwarf plants? b. What are the expected F2 ratios (use fractions) of yellow and green seeds? C. What are the expected F2…

Choice 2: Black versus orange fur is determined by two alleles an X-linked gene (XⓇ, Xº), Suppose that a black male is mated with an orange female. a) Write the genotypes of the male and female cats. Male: Female: b) What genotypes & phenotypes are expected among the offspring (F1) of these parent cats? c) Suppose that a male and a female from part b mate. What offspring types will they produce?

Directions: Match the word on the left to the correct picture on the right. Write the # in the circle. Word Picture 1. Dominant 2. Recessive 3. Trait 4. Punnett Square Aa aa 5. Pedigree a Aa aa 6. Gregor Mendel 7. Genotype 8. Phenotype AaBb 9. Genetics Father's Genes 10. Heteozygous G GG Gg 9 Gg g9 B BB Bb 11. Homozygous 12. Hybrid bBb bb 13. Allele 14. Heredity Crossing between a red rose and a white rose producing a pink phenotype. 15. Incomplete Dominance

Question ? Question 7 The ability to taste certain substances, such as PTC is also genetically controlled. People that can taste have a dominant allele (T), while non-tasters have the recessive alleles (tt). Suppose a woman who is a non-PTC-taster has offspring with a man who is a homozygous PTC taster. What is the probability that they have a child with the tasting gene? A 25% e 50% © 75% O 100%

Can you please explain this discussion for me? Thank you!   "All humans and many other primates can be typed for the ABO blood group. There are four principal types: A, B, AB and O. There are two antigens and two antibodies that are mostly responsible for the ABO types. The specific combination of these four components determines an individual's type in most cases. Blood type O, characterized by the absence of A or B antigens, is the most common in most races. Type A is the next. The incidence of Type AB is usually the least."

questions below: Aura and Ryan are expecting a child. Aura has dark eyes and Ryan has light eyes. Aura's mother has light eyes. Draw a Punnett square and be sure to include the following information for full credit: 1. Place the parents alleles at the top and on the left side. 2. Write in the allele crosses inside the Punnett squares. 3. Write out the genotypes probabilities for an offspring. 4. Write out the phenotype probabilities for an offspring. 5. What is the probability that Aura and Ryan could have a child with light eyes, even if light is recessive to dark? Note: For this question, you will have to go further back into the family tree to get Aura's genotype.